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  • django url tag performance

    - by zxygentoo
    I was trying to integrate django-voting into my project following the RedditStyleVoting instruction. In my urls.py, i did something like this: url(r'^sections/(?P<object_id>\d+)/(?P<direction>up|down|clear)vote/?$', vote_on_object, dict( model=Section, template_object_name='section', template_name='script/section_confirm_vote.html', allow_xmlhttprequest=True ), name="section_vote", then, in my template: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} It takes over 1.3s to load the page, but by hard coding it like this: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} I got 50ms. Just avoid the url tag resolving stuff I got a 20+ times performance improvement. Is there something I did wrong? If not, then what's the best practice here, should we do things the right way or the fast way?

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  • Can I turn off implicit Python unicode conversions to find my mixed-strings bugs?

    - by Tal Weiss
    When profiling our code I was surprised to find millions of calls to C:\Python26\lib\encodings\utf_8.py:15(decode) I started debugging and found that across our code base there are many small bugs, usually comparing a string to a unicode or adding a sting and a unicode. Python graciously decodes the strings and performs the following operations in unicode. How kind. But expensive! I am fluent in unicode, having read Joel Spolsky and Dive Into Python... I try to keep our code internals in unicode only. My question - can I turn off this pythonic nice-guy behavior? At least until I find all these bugs and fix them (usually by adding a u'u')? Some of them are extremely hard to find (a variable that is sometimes a string...). Python 2.6.5 (and I can't switch to 3.x).

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  • Python: why does str() on some text from a UTF-8 file give a UnicodeDecodeError?

    - by AP257
    I'm processing a UTF-8 file in Python, and have used simplejson to load it into a dictionary. However, I'm getting a UnicodeDecodeError when I try to turn one of the dictionary values into a string: f = open('my_json.json', 'r') master_dictionary = json.load(f) #some json wrangling, then it fails on this line... mysql_string += " ('" + str(v_dict['code']) Traceback (most recent call last): File "my_file.py", line 25, in <module> str(v_dict['code']) + "'), " UnicodeEncodeError: 'ascii' codec can't encode character u'\xf4' in position 35: ordinal not in range(128) Why is Python even using ASCII? I thought it used UTF-8 by default, and this is a UTF-8 file. What is the problem?

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  • How do I get the path of the current executed file in python?

    - by Sorin Sbarnea
    This may seam a newbie question but it is not. It looks that common approaches are not always working: Currently I know only two options but none of them looks to work an all cases. sys.argv[0] This means using path = os.path.abspath(os.path.dirname(sys.argv[0])) but this does not work if you are running from another python script from another directory, and this can really happen in real life. __file__ this means that path = os.path.abspath(os.path.dirname(__file__)) but I found that this doesn't work: py2exe that doesn't have a __file__ attribute but there is an workaround. when you run from IDLE with execute() there is no __file__ attribute OS X 10.6 where I get NameError: global name '__file__' is not defined Related questions with incomplete answers: http://stackoverflow.com/questions/1296501/python-find-path-to-file-being-run http://stackoverflow.com/questions/1483827/python-path-to-current-file-depends-on-how-i-execute-the-program http://stackoverflow.com/questions/2259503/how-to-know-the-path-of-the-running-script-in-python http://stackoverflow.com/questions/509742/python-chdir-to-dir-the-py-script-is-in

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  • A RAM error of big array

    - by flint
    I have a big file, more than 400M. In that file, there are 13496*13496 number, means 13496 rows and 13496 cols. I want to read them to a array. This is my code: _L1 = [[0 for col in range(13496)] for row in range(13496)] _L1file = open('distanceCMD.function.txt') while (i<13496): print "i="+str(i) _strlf = _L1file.readline() _strlf = _strlf.split('\t') _strlf = _strlf[:-1] _L1[i] = _strlf i += 1 _L1file.close() And this is my error massage: MemoryError: File "D:\research\space-function\ART3.py", line 30, in <module> _strlf = _strlf.split('\t')

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  • Running "source" from python

    - by R S
    Hello, I have a file a.txt with lines of commands I want to run, say: echo 1 echo 2 echo 3 If I was on csh (unix), I would have done source a.txt and it would run. From python I want to run os.execl with it, however I get: >>> os.execl("source", "a.txt") Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.5/os.py", line 322, in execl execv(file, args) OSError: [Errno 2] No such file or directory How to do it?

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  • socket.error: [Errno 10054]

    - by C0d3r
    import socket, sys if len(sys.argv) !=3 : print "Usage: ./supabot.py <host> <port>" sys.exit(1) irc = sys.argv[1] port = int(sys.argv[2]) sck = socket.socket(socket.AF_INET, socket.SOCK_STREAM) sck.connect((irc, port)) sck.send('NICK supaBOT\r\n') sck.send('USER supaBOT supaBOT supaBOT :supaBOT Script\r\n') sck.send('JOIN #darkunderground' + '\r\n') data = '' while True: data = sck.recv(1024) if data.find('PING') != -1: sck.send('PONG ' + data.split() [1] + '\r\n') print data elif data.find('!info') != -1: sck.send('PRIVMSG #darkunderground supaBOT v1.0 by sourD' + '\r\n') print sck.recv(1024) when I run this code I get this error.. socket.error: [Errno 10054] An existing connection was forcibly closed by the remote host it says that the error is in line 16, in data = sck.recv(1024)

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  • Django colon syntax in template tags: only in newer versions?

    - by Alan
    I just deployed an application to a new server, and although I'm using virtualenv, I had to install a new environment on the production server, which has a different architecture. Anyway, I received no TemplateSytaxErrors in development, but on the production server, I get: Exception Type: TemplateSyntaxError Exception Value: Caught SyntaxError while rendering: invalid syntax (views.py, line 25) The offending line is: {% url admin:password_change as password_change_url %} Upon removing that line, the TemplateSyntaxError hops to the next line that has a colon in it (and lets other template tags work fine). So my question is this: is there some discrepancy in versions of Python/Django that would allow or disallow the namespacing syntax? The template tags are in django-grappelli (http://code.google.com/p/django-grappelli/), so I'd rather not go through their code and rewrite all the template tags. Development server: 32-bit Debian Python 2.5.5 Django 1.2.1 Production server: 64-bit CentOS Python 2.4.3 Django 1.2.1 Any ideas?

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  • Halting Django's dev server via page request?

    - by Ben Blank
    I'm looking at writing a portable, light-weight Python app. As the "GUI toolkit" I'm most familiar with — by a wide margin! — is HTML/CSS/JS, I thought to use Django as a framework for the project, using its built-in "development server" (manage.py runserver). I've been banging on a proof-of-concept for a couple hours and the only real problem I've encountered so far is shutting down the server once the user has finished using the app. Ideally, I'd like there to be a link on the app's pages which shuts down the server and closes the page, but nothing I see in the Django docs suggests this is possible. Can this be done? For that matter, is this a reasonable approach for writing a small, portable GUI tool?

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  • Python interpreter invocation with "-c" and indentation issues

    - by alexander
    I'm trying to invoke Python using the "-c" argument to allow me to run some arbitrary python code easily, like this: python.exe -c "for idx in range(10): print idx" Now this code works fine, from within my batch file, however, I'm running into problems when I want to do anything more than this. Consider the following Python code: foo = 'bar' for idx in range(10): print idx this would then give you 0-9 on the stdout. However, if I collapse this into a single line, using semicolons as delimiters, to get the following: foo = 'bar';for idx in range(10): print idx and try to run it using python.exe -c it get a SyntaxError raised: C:\Python>python.exe -c "foo = 'bar';for idx in range(10): print idx" File "<string>", line 1 foo = 'bar';for idx in range(10): print idx ^ SyntaxError: invalid syntax Anyone know how I can actually use this without switching to a separate .py file?

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  • trying to load css/images in django

    - by tipu
    I looked http://docs.djangoproject.com/en/dev/howto/static-files/ already, but am still confused on how to get css/image files loaded. On my server, the images folder and css file are located at /srv/twingle/search my urls.py 1 from django.conf.urls.defaults import * 2 3 # Uncomment the next two lines to enable the admin: 4 # from django.contrib import admin 5 # admin.autodiscover() 6 7 urlpatterns = patterns('twingle.search.views', 8 url(r'^$', 'index'), 9 url(r'^search/(?P<param>\w+)$', 'index'), 10 ) 11 (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', 12 {'document_root': '/srv/twingle/search'}), 13 I try to access my css as follows, <link rel="stylesheet" type="text/css" href="/site_media/style.css" /> That's exactly how the tutorial says to do it, but it doesn't work. Any suggestions?

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  • Django i18n: makemessages only on site level possible?

    - by AndiDog
    I have several strings in my site that don't belong to any app, for example {% block title %}{% trans "Login" %}{% endblock %} or a modified authentication form used to set the locale cookie class AuthenticationFormWithLocaleOption(AuthenticationForm): locale = forms.ChoiceField(choices = settings.LANGUAGES, required = False, initial = preselectedLocale, label = _("Locale/language")) Now when I execute django-admin.py makemessages --all -e .html,.template in the site directory, it extracts the strings from all Python, .html and .template files, including those in my apps. That is because I develop my apps inside that directory: Directory structure: sitename myapp1 myapp2 Is there any way to extract all strings that are not in my apps? The only solution I found is to move the app directories outside the site directory structure, but I'm using bzr-externals (similar to git submodules or svn externals) so that doesn't make sense in my case. Moving stuff that needs translation into a new app is also possible but I don't know if that is the only reasonable solution.

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  • Newbie programmer looking for a fun, small project (pref. C++/Python)

    - by Francisco P.
    Hello everyone, I have some experience in Scheme and C++ (read: a semester of each) I know the very basics of Python (used it for physics simulations with the Visual Python module). Can you recommend me some fun and small (i.e. don't take much time) projects on either Python or C++? I have no real preferences, just that it is fun :P Thanks for your time! PS: I've tried projecteuler and python challenge. Euler is good, but more about math than coding, and py challenge just didn't work for me.

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  • how to get apache mod_cache work with mod_wsgi (django)?

    - by harmv
    I thought i'd speed up my django projects, by letting apache doing some caching for me. Unfortunately I see that apache never caches my dynamic pages. Has mod_cache problems with mod_wsgi served code ? My apache config: <VirtualHost *:80 ServerName myserver.com CacheEnable mem / # for testing only CacheIgnoreQueryString On CacheIgnoreCacheControl On WSGIDaemonProcess aname processes=1 threads=25 WSGIProcessGroup aname Alias /media/ /home/harm/projects/test/media/ WSGIScriptAlias / /home/harm/projects/test/wsgi.py The response does have the correct caching headers: Content-Length 2647 Content-Encoding gzip Vary Accept-Encoding Cache-Control public, max-age=3600 Keep-Alive timeout=15, max=100 Connection Keep-Alive Content-Type application/x-javascript Am I missing something ?

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  • In python, is there anyway to have a variable be a different random number everytime?

    - by woah113
    Basically I have this: import random variable1 = random.randint(13, 19) And basically what that does is assign variable1 a random number between 13 and 19. Great. But, what I want it to do is assign a different random number between 13 and 19 to that variable every time it is called. Is there anyway I can do this? If I'm not being clear enough here's an example: import random variable1 = random.randint(13, 19) print(variable1) print(variable1) print(variable1) And the output I want would look something like this: ./script.py 15 19 13 So yeah, anyway I could do this in python? (More specifically python3. but the answer would probably be similar to a python2 answer)

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  • Django - raw_id_fields title not refreshing.

    - by James Howell
    Hi, I am currently having an issue when using the raw_id_field within admin.py in my Django project. My site's admin area has a number of image upload fields for various different model pages which are all ForeignKey fields to an Image model where all images for the site are stored. As the site will eventually be dealing with a large quantity of images (100s, maybe 1000s) the default select box would be unusable. I created various admin.ModelAdmin classes e.g class InfoSlideAdmin(admin.ModelAdmin): raw_id_fields=('image',) These change the image selector within my Edit pages from a Select Box to a Raw ID Field. However when I select a different image using this control although the ID of the new image is shown the title from the previous image still displays. Any ideas?

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  • Does django take SCRIPT_NAME into account when using the default LOGIN_URL

    - by DanJ
    Hi, I'm using Django 1.0.2 and trying to figure out how to get the @login_required working correctly. When I use the built-in server it redirects to the default login_url, or my LOGIN_URL as defined in settings.py as expected. What is not clear to me is how to deploy to the server where my site is not at the root. In my templates I use the url template tag, and in the views I can access request.META['SCRIPT_NAME'], but for some reason it doesn't seem to apply to the LOGIN_URL used. What am I missing? Thanks.

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  • how to get files as they are added to a remote server

    - by Jordan
    I am using a bash script (below) on a remote server (so far using ssh to connect) to execute a python script that downloads a lot of pdf files one at a time (getting the download locations from a text file with the URL's) in a loop. I would like to move the files from the remote server to my local computer as they are downloaded, and then delete the file from the remote server. Is there a way that I can expand my bash script to do this? Or are there alternatives for completing this task? while read line; do python python_script.py -l $line; done < pdfURLs.txt

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  • django integrate htmls into templates

    - by dana
    hi guys, i have a django 'templating' question if i have in views.py: def cv(request): if request.user.is_authenticated(): cv = OpenCv.objects.filter(created_by=request.user) return render_to_response('cv/cv.html', { 'object_list': cv, }, context_instance=RequestContext(request)) and in cv.html something like: {% for object in object_list %} First Name {{ object.first_name }} Last Name {{ object.last_name }} Url {{object.url}} Picture {{object.picture}} Bio {{object.bio}} Date of birth {{object.date_birth}} {% endfor %} but i want this content to appear on the profile.html page too, how can i do it? a smple {% include cv.html %} in the profile.html doesn't work. Also, is there another way to 'parse the object list' than explicitly write all the objects, like above? thanks in advance!

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  • How to dump STDIN to a file, using C++ STL?

    - by Jimm Chen
    HHello all, this is a straight forward question, but not a straight forward answer can be found by just Googling today. Hope someone can show me a concise answer before I dig into those thick C++ books and finally find the solution out. Thank you. I'm writing this program so to make a workaround in this issue: Why do I get 'Bad file descriptor' when trying sys.stdin.read() in subversion pre-revprop-change py script? Note: Content from STDIN may be arbitrary binary data. Please use C++ STL functions, iostream, ifstream etc . If the file creation/writing failed, I'd like to catch the exception to know the case.

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  • tkinter python entry not being displayed

    - by user1050619
    I have created a Form with labels and entries..but for some reason the entries are not being created, peoplegui.py from tkinter import * from tkinter.messagebox import showerror import shelve shelvename = 'class-shelve' fieldnames = ('name','age','job','pay') def makewidgets(): global entries window = Tk() window.title('People Shelve') form = Frame(window) form.pack() entries = {} for (ix, label) in enumerate(('key',) + fieldnames): lab = Label(form, text=label) ent = Entry(form) lab.grid(row=ix, column=0) lab.grid(row=ix, column=1) entries[label] = ent Button(window, text="Fetch", command=fetchRecord).pack(side=LEFT) Button(window, text="Update", command=updateRecord).pack(side=LEFT) Button(window, text="Quit", command=window.quit).pack(side=RIGHT) return window def fetchRecord(): print('In fetch') def updateRecord(): print('In update') if __name__ == '__main__': window = makewidgets() window.mainloop() When I run it the labels are created but not the entries.

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  • Django: Proper place to unregister ModelAdmins

    - by lazerscience
    Sometimes I need to UNREGISTER some ModelAdmins from the admin site, because I don't want them to be there as they are, eg. if I'm using the Sites framework, and I dont want it to appear in the admin. It's no big deal to e.g. call admin.site.unregister(Site) to do so. In most cases I put it in admin.py of some related app that I have made, but sometimes I end up putting it in a place that hasn't much to do with the original app; another possibility would be making a "dummy app" and put it there... Does anybody know a more descent place where these calls can live?

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  • django access to parent

    - by SledgehammerPL
    model: class Product(models.Model): name = models.CharField(max_length = 128) (...) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive And now I'd like to get list of the most often useable products: ReceiptComponent.objects.values('product').annotate(Count('product')).order_by('-product__count' the example result: [{'product': 3, 'product__count': 5}, {'product': 6, 'product__count': 4}, {'product': 5, 'product__count': 3}, {'product': 7, 'product__count': 2}, {'product': 1, 'product__count': 2}, {'product': 11, 'product__count': 1}, {'product': 8, 'product__count': 1}, {'product': 4, 'product__count': 1}, {'product': 9, 'product__count': 1}] It's almost what I need. But I'd prefer having Product object not product value, because I'd like to use this in views.py for generating list.

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  • Django template tag basic question

    - by ninja123
    It looks like this template tag works like a charm for most people: http://blog.localkinegrinds.com/2007/09/06/digg-style-pagination-in-django/ For some reason I get this error: Caught an exception while rendering: 'is_paginated' I use this template tag in my template like so: {% load digg_paginator %} {% digg_paginator %} Where digg_paginator.py is in my app/templatetags folder and the included template context digg_paginator.html is in my app/templates folder. The queryset that needs pagination is called 'destinations'. If i just specify {% digg_paginator %}, how does it know what variable to paginate?? I feel I am missing something important here or just plain stupid :P Someone please help, or explain to me how this should be done. Thanks

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  • How To Collapse Just One Field in Django Admin?

    - by Apreche
    The django admin allows you to specify fieldsets. You properly structure a tuple that groups different fields together. You can also specify classes for certain groups of fields. One of those classes is collapse, which will hide the field under a collapsable area. This is good for hiding rarely used or advanced fields to keep the UI clean. However, I have a situation where I want to hide just one lonesome field on many different apps. This will be a lot of typing to create a full fieldset specification in every admin.py file just to put one field into the collapsed area. It also creates a difficult maintenance situation because I will have to edit the fieldset every time I edit the associated model. I can easily exclude the field entirely using the exclude option. I want something similar for collapse. Is this possible?

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