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  • Longest substring that appears n times

    - by xcoders
    For a string of length L, I want to find the longest substring that appears n (n<L) or more times in ths string. For example, the longest substring that occurs 2 or more times in "BANANA" is "ANA", once starting from index 1, and once again starting from index 3. The substrings are allowed to overlap. In the string "FFFFFF", the longest string that appears 3 or more times is "FFFF". The brute force algorithm for n=2 would be selecting all pairs of indexes in the string, then running along until the characters are different. The running-along part takes O(L) and the number of pairs is O(L^2) (duplicates are not allowed but I'm ignoring that) so the complexity of this algorithm for n=2 would be O(L^3). For greater values of n, this grows exponentially. Is there a more efficient algorithm for this problem?

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  • doing a full permutation search and replace on a string

    - by user73307
    I'm writing an app that does something like a custom number (licence) place generator tool where if I ask for the plate "robin" it will suggest I try: r0bin rob1n r0b1n Are there any published algorithms which can do this? It has to be able to handle replacing single letters with multiples, e.g. m with rn and vise-versa and not fall over if it replaces an i with an l then comes to check the l and replaces it back to an i. The list of what gets swapped with what is going to be user input but I'm not expecting a huge list, possibly 10 pairs at most. I'll be implementing this in Ruby or Python but I should be able to convert code from any other language.

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  • Is there any way to get the combine two xml into one xml in Linux.

    - by Tattat
    XML one is something like that: <dict> <key>2</key> <array> <string>A</string> <string>B</string> </array> <key>3</key> <array> <string>C</string> <string>D</string> <string>E</string> </array> </dict> XML Two is something like that: <dict> <key>A</key> <array> <string>A1</string> <false/> <false/> <array> <string>Apple</string> <string>This is an apple</string> </array> <array> <string>Apple Pie</string> <string>I love Apple Pie.</string> </array> </array> <key>B</key> <array> <string>B7</string> <false/> <false/> <array> <string>Boy</string> <string>I am a boy.</string> </array> </array> </dict> I want to convert to this: <dict> <key>2</key> <array> <string>A, Apple, Apple Pie</string> <string>B, Boy</string> </array> ... </dict>

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  • Trying to implement a method that can compare any two lists but it always returns false

    - by Tyler Pfaff
    Hello like the title says I'm trying to make a method that can compare any two lists for equality. I'm trying to compare them in a way that validates that every element of one list has the same value as every element of another list. My Equals method below always returns false, can anyone see why that is? Thank you! using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; public class IEnumerableComparer<T> : IEqualityComparer<IEnumerable<T>> { public bool Equals(IEnumerable<T> x, IEnumerable<T> y) { for(int i = 0; i<x.Count();i++){ if(!Object.Equals(x.ElementAt(i), y.ElementAt(i))){ return false; } } return true; } public int GetHashCode(IEnumerable<T> obj) { if (obj == null) return 0; return unchecked(obj.Select(e => e.GetHashCode()).Aggregate(0, (a, b) => a + b)); } } Here is my data I'm using to test this Equals method. static void Main(string[] args) { Car car1 = new Car(); car1.make = "Toyota"; car1.model = "xB"; Car car2 = new Car(); car2.make = "Toyota"; car2.model = "xB"; List<Car> l1 = new List<Car>(); List<Car> l2 = new List<Car>(); l1.Add(car1); l2.Add(car2); IEnumerableComparer<Car> seq = new IEnumerableComparer<Car>(); bool b = seq.Equals(l1, l2); Console.Write(b); //always says false Console.Read(); } } Car class class Car { public String make { get; set; } public String model { get; set; } }

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  • Mod_Rewrite - Remove Query String From URLs

    There are plenty of tutorials and articles showing how to use the apache mod_rewrite module to tidy up messy URLs can create nice, human readable, search engine friendly URLs. No problem there and if that is what you are looking for you wont find that here.

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  • How to generate a random unique string with more than 2^30 combination. I also wanted to reverse the process. Is this possible?

    - by Yusuf S
    I have a string which contains 3 elements: a 3 digit code (example: SIN, ABD, SMS, etc) a 1 digit code type (example: 1, 2, 3, etc) a 3 digit number (example: 500, 123, 345) Example string: SIN1500, ABD2123, SMS3345, etc.. I wanted to generate a UNIQUE 10 digit alphanumeric and case sensitive string (only 0-9/a-z/A-Z is allowed), with more than 2^30 (about 1 billion) unique combination per string supplied. The generated code must have a particular algorithm so that I can reverse the process. For example: public static void main(String[] args) { String test = "ABD2123"; String result = generateData(test); System.out.println(generateOutput(test)); //for example, the output of this is: 1jS8g4GDn0 System.out.println(generateOutput(result)); //the output of this will be ABD2123 (the original string supplied) } What I wanted to ask is is there any ideas/examples/libraries in java that can do this? Or at least any hint on what keyword should I put on Google? I tried googling using the keyword java checksum, rng, security, random number, etc and also tried looking at some random number solution (java SecureRandom, xorshift RNG, java.util.zip's checksum, etc) but I can't seem to find one? Thanks! EDIT: My use case for this program is to generate some kind of unique voucher number to be used by specific customers. The string supplied will contains 3 digit code for company ID, 1 digit code for voucher type, and a 3 digit number for the voucher nominal. I also tried adding 3 random alphanumeric (so the final digit is 7 + 3 digit = 10 digit). This is what I've done so far, but the result is not very good (only about 100 thousand combination): public static String in ="somerandomstrings"; public static String out="someotherrandomstrings"; public static String encrypt(String kata) throws Exception { String result=""; String ina=in; String outa=out; Random ran = new Random(); Integer modulus=in.length(); Integer offset= ((Integer.parseInt(Utils.convertDateToString(new Date(), "SS")))+ran.nextInt(60))/2%modulus; result=ina.substring(offset, offset+1); ina=ina+ina; ina=ina.substring(offset, offset+modulus); result=result+translate(kata, ina, outa); return result; } EDIT: I'm sorry I forgot to put the "translate" function : public static String translate(String kata,String seq1, String seq2){ String result=""; if(kata!=null&seq1!=null&seq2!=null){ String[] a=kata.split(""); for (int j = 1; j < a.length; j++) { String b=a[j]; String[]seq1split=seq1.split(""); String[]seq2split=seq2.split(""); int hint=seq1.indexOf(b)+1; String sq=""; if(seq1split.length>hint) sq=seq1split[hint]; String sq1=""; if(seq2split.length>hint) sq1=seq2split[hint]; b=b.replace(sq, sq1); result=result+b; } } return result; }

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  • How to split a string with negative numbers using ActionScript 3.0

    - by inzombiak
    I'm having trouble loading my level. I'm using Ogmo to create my level then I import it. I have no problem converting 0's and 1's into an Array, but I can't figure out how to do the same for -1's. It separates the "-" and the "1". Any help would be great. I've posted my code and the XML files below levelXML = new XML(e.target.data); playerX = int(levelXML.Entities.Player.@x); playerY = int(levelXML.Entities.Player.@y); levelGrid = levelXML.Grid; levelGrid = levelGrid.split("\n").join(""); levelTiles = levelXML.Tiles; levelTiles = levelTiles.split("\n").join(""); levelTiles = levelTiles.split(",").join(""); tileArray = levelTiles.split(""); gridArray = levelGrid.split(""); for(i = 0; i <= 34; i++) { levelArray[i] = new Array(); for(j = 0; j <= 34; j++) { if(tileArray[j*35 + i] == 0) { gridArray[j*35+i] = -1; } var currentSymbol = gridArray[j*35+i]; levelArray[i][j] = currentSymbol; if(gridArray[j*35 + i] == 1) { wall = new Wall; addChild(wall); wall.x = i*20 + 10; wall.y = j*20 + 10; } else if(gridArray[j*35 + i] == -1) { pellet = new Pellet; addChild(pellet); pellet.x = i*20 + 10; pellet.y = j*20 + 10; } } } I know the code is very dirty, but I needed a quick fix. Grid exportMode="Bitstring" 11111111111111111111111111111111111 10000000000000000011000000000000001 10000000000000000011000000000000001 10011111001111110011001111110011001 10011111001111110011001111110011001 10011111001111110011001111110011001 10000000000000000000000000000000001 10000000000000000000000000000000001 10011111001100111111100110011111001 10011111001100000100000110011111001 10000000001100000100000110000000001 10000000001111100100111110000000001 11111111001111100100111110011111111 00000001001111100100111110010000000 00000001001100000000000110010000000 11111111001100000000000110011111111 00000000000000111111100000000000000 00000000000000100000100000000000000 11111111001100100000100110011111111 00000001001100111111100110010000000 00000001001100000000000110010000000 11111111001100111111100110011111111 10000000000000000100000000000000001 10000000000000000100000000000000001 10011111001111100100111110011111001 10000011000000000000000000011000001 10000011000000000000000000011000001 11110011001100111111100110011001111 11110011001100111111100110011001111 10000000001100000100000110000000001 10000000001100000100000110000000001 10011111111111100100111111111111001 10000000000000000000000000000000001 10000000000000000000000000000000001 11111111111111111111111111111111111 Tiles tileset="Tiles" exportMode="CSV"-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,0,0,0,0,0,0,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1

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  • Need to create a string token dynamically base on which method is calling it

    - by sa
    This is a minimal code. I have the string Str which is used by various methods. I want to in getId method be able to do 2 things Assign class="PDP" to it and Give it a value3 So the final string looks like <tr class='PDP' id='{2}'> <td {0}</td><td>{1}</td></tr> But please note that I will need different values for class in different methods so some Str will have PDP, another will have PTM etc. Is there a clean way to achieve this . private const string Str = "<tr><td >{0}</td><td>{1}</td></tr>"; public static string getId() { string field=string.Format(str, value1,value2, found=true? value3:""); }

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  • non-static method setPrzechowaj(java.lang.String) cannot be referenced froma a static context

    - by bigbluedragon
    hey i have problem with JDialogForm. I have created it using netbeans 6.8. That JDialogForm have textfield and button below it. and here is some code... private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) { String sciezka = jTextField1.getText(); if (sciezka.length() > 0) { Zmienne_pomocnicze.setPrzechowaj(sciezka); } } Now i want to copy that string "sciezka" to my main window but if I do it like this public class Zmienne_pomocnicze { public String n; public void setPrzechowaj (String neew) { n = neew; } public String getPrzechowaj () { return n; } } i get error in jButton1: non-static method setPrzechowaj(java.lang.String) cannot be referenced froma a static context any ideas?

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  • Regular expression match, extracting only wanted segments of string

    - by Ben Carey
    I am trying to extract three segments from a string. As I am not particularly good with regular expressions, I think what I have done could probably be done better... I would like to extract the bold parts of the following string: SOMETEXT: ANYTHING_HERE (Old=ANYTHING_HERE, New=ANYTHING_HERE) Some examples could be: ABC: Some_Field (Old=,New=123) ABC: Some_Field (Old=ABCde,New=1234) ABC: Some_Field (Old=Hello World,New=Bye Bye World) So the above would return the following matches: $matches[0] = 'Some_Field'; $matches[1] = ''; $matches[2] = '123'; So far I have the following code: preg_match_all('/^([a-z]*\:(\s?)+)(.+)(\s?)+\(old=(.+)\,(\s?)+new=(.+)\)/i',$string,$matches); The issue with the above is that it returns a match for each separate segment of the string. I do not know how to ensure the string is the correct format using a regular expression without catching and storing the match if that makes sense? So, my question, if not already clear, how I can retrieve just the segments that I want from the above string?

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  • How to remove a string from Dictionary<>

    - by Ranjana
    i have used dictionary to collect the array of values i have value in DataTable . How to compare the values get from DataTable, whether dictionary key contains the name in DataTable. if DataTable has not that value,then remove that key name from dictionary. My code: DataTable dtcolumnsname = clsServiceManager.Instnce.Get_ColumnNames(ClsUserInfo.UserName, strTableName); Dictionary<string,string> FinalDicColumnVal = new Dictionary<string,string>(); foreach (KeyValuePair<string, string> item in ColumnValues) { if (dtcolumnsname.Columns.Contains(item.Key)) { FinalDicColumnVal.Add(item.Key, item.Value); } } but this if (dtcolumnsname.Columns.Contains(item.Key)) is not get values of each datarow items in datatable.how to compare the dt row values with dictionary key names

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  • Using Enums for comparing string values in Switch

    - by kaleidoscope
    Problem Scenario: There is an enum keeping track of operations to be performed on a table Public Enum PartitionKey { Createtask, Updatetask, Deletetask } User is entering the value for the operation to be performed and the code to check the value entered in switch case. Switch (value) {           case PartitionKey.Createtask.ToString():          {          Create();          break;          }          case PartitionKey.Updatetask.ToString():          {           Update();           break;          }          case PartitionKey.Deletetask.ToString():          {           Delete();          break;          } } and it displays as error as “.” Solution: One of the possible implmentation is as below. Public Enum PartitionKey: byte { Createtask, Updatetask, Deletetask } Switch ((PartitionKey)(Int32.Parse(value))) {          case PartitionKey.Createtask:          {                   Create();                   break;          }          case PartitionKey.Updatetask:          {                    Update();                   break;          }          case PartitionKey.Deletetask:          {                    Delete();                   break;          }          default:          {                   break;          } } Technorati Tags: Enum,A Constant Value is required,Geeta,C#

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  • python dictionary conversion from string?

    - by shahjapan
    if I've string like "{ partner_name = test_partner}" OR " { partner_name : test_partner } its an example string will be very complex with several special characters included like =, [ , ] , { , } what will be the best way to convert it into a python object - so I can process it I tried with eval but it requires " ' " for string, but how can we add this special character \' before starting and ending of every word, I tried regular express re.findal('\w+') but it fails when my string contains ' _ ' or like characters as it will separate the string by ' _ ' Object of this question is my application needs, user friendly language as input - and I thought Json Dict will be good - but user is lazzy to put " ' " before and after of each string... then I thought for yaml but its also complex, if anybody can suggest better user friendly input which I use as python object - then please help me out.

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  • How can I handle this string concatenation in C in a reusable way

    - by hyphen this
    I've been writing a small C application that operates on files, and I've found that I have been copy+pasting this code around my functions: char fullpath[PATH_MAX]; fullpath[0] = '\0'; strcat(fullpath, BASE_PATH); strcat(fullpath, subdir); strcat(fullpath, "/"); strcat(fullpath, filename); // do something with fullpath... Is there a better way? The first thought that comes to mind is to create a macro but I'm sure this is a common problem in C, and I'm wondering how others have solve it.

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  • return char1 + char2? Isn't it possible?

    - by pocoa
    I'm trying to return a string from a function. Which basically adds some chars together and return the string representation. string toString() { char c1, c2, c3; // some code here return c1 + c2; // Error: invalid conversion from `char' to `const char*' } it is possible to return boolean values like return c1 == 'x'. Isn't it possible to return string values? I know that it is possible to it like this: string result; result.append(c1, c2); return result; I'm new to C++ so I thought that there must be more elegant solution around.

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  • Search Engine Optimization on a Shoe String Budget (aka DIY SEO) - Part I

    SEO is critical to having your small/local business being found online. There are services out there that charge hundreds or even thousands of dollars a month for this service and frankly many of them are worth that and more for the qualified leads they help send your way. However for the small business person there often is no budget for this so they have to have a more DIY (do it yourself) approach at the start. This article is the first in a series that outlines some basics before you start spending money.

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  • Cannot pass a input from text box to a query string and then keep the string in this box.

    - by Nikita Barsukov
    I have a simple ASP.net page: <form id="form1" runat="server"> <p><asp:TextBox id="input_box" runat="server"></asp:TextBox> <asp:Button Text="OK" runat="server" OnClick="run" /></p> </form> I want to send input from input_box to a query string, and then keep this input in the input_box when the page reloads. That's the code behind page: protected void Page_Load(object sender, EventArgs e) { input_box.Text = Request.QueryString["input"]; } protected void run(object sender, EventArgs e) { string url = string.Format("?input={0}", input_box.Text); Response.Redirect(Request.Url.AbsolutePath + url); } Problem is that when query string is not empty, string from input_box cannot be passed to query string. How to correct it?

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  • Stored Connection Strings per user

    - by pehaada
    In the past I've used a Singleton Pattern to load the connection string when the application starts via the global.asa file. I have a project now where each user has a unique connection string to the database. I would like to load this connection string once. The issue is that the singleton pattern will not work for me since each user has there own connection string. Basically the connection string is created dynamically. I do not want to store it is session. If anyway has a clever way of doing this in .NET let me know ?

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  • How to insert complex strings into Actionscript?

    - by Ole Jak
    How to insert complex strings into Actionscript? So I have a string -vvv -I rc w:// v dv s="60x40" --ut="#scode{vcode=FV1,acode=p3,ab=128,ch=2,rate=4400}:dup{dt=st{ac=http{mime=v/x-flv},mux=mpeg{v},dt=:80/sm.fv}}" How to insert it into code like public var SuperPuperComplexString:String = new String(); SuperPuperComplexString = TO_THAT_COMPLEX_STRING; That string has so many problems like some cart of it can happen to be like regexp BUTI DO NOT want it to be parsed as any kind of reg exp - I need It AS IT IS!) How to put that strange string into variable (put it not inputing it thru UI - hardcode it into AS code)?

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  • StringIndexOutOfBoundsException: String index out of range 0

    - by Evan F
    I'm trying to write a program to take the first letter of the user input to generate a username. I'm trying to write it so that if the user leaves the input blank, then the letter that would otherwise be taken to generate the username defaults to the letter 'z'. Here is my full code: import java.util.Scanner; /** UsernameGenerator.java Generates a username based on the users inputs. @author: Evan Fravert */ public class UsernameGenerator { /** * Generates a username based on the users inputs. *@param args command line argument */ public static void main(String[] args) { // abcde String first; String middle; String last; String password1; String password2; int randomNum; randomNum = (int) (Math.random() * 1000) + 100; Scanner userInput = new Scanner(System.in); System.out.println("Please enter your first name:"); first = userInput.nextLine(); String firstLower = first.toLowerCase(); System.out.println("Please enter your middle name:"); middle = userInput.nextLine(); String middleLower = middle.toLowerCase(); System.out.println("Please enter your last name:"); last = userInput.nextLine(); int lastEnd = last.length()-1; String lastLower = last.toLowerCase(); System.out.println("Please enter your password:"); password1 = userInput.nextLine(); System.out.println("Please enter your password again:"); password2 = userInput.nextLine(); char firstLetter = firstLower.charAt(0); char middleLetter = middleLower.charAt(0); char lastLetter = lastLower.charAt(0); char lastLast = lastLower.charAt(lastEnd); if first.length() == 0) { firstLetter = 'z'; } else { firstLetter = firstLower.charAt(0); } System.out.println("Your username is " + firstLetter + "" + middleLetter + "" + lastLetter + "" + "" + lastLast + "" + randomNum); System.out.println("Your password is " + password1); System.out.println("Welcome " + first + " " + middle + " " + last + "!"); } }

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  • How to have NHibernate persist a String.Empty property value as NULL

    - by Todd
    I have a fairly simple class that I want to save to SQL Server via NHibernate (w/ Fluent mappings). The class is made up mostly of optional string fields. My problem is I default the class fields to string.empty to avoid NullRefExceptions and when NHibernate saves the row to the database each column contains an empty string instead of null. Question: Is there a way for me to get NHibernate to automatically save null when the string property is an empty string? Or do I need to litter my code with if (string.empty) checks?

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  • The Connection String Reference Site

    - by Yousef_Jadallah
    In this great site http://www.connectionstrings.com/ you can find about 517 connection strings and 120 providers, drivers and class libraries listed in the database. These for Database Servers as well Data Files. Just you need to choose the needed element then you will get all the information that you calling for.   Hope this helps,

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