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  • Sed substitution not doing what I want and think it should do

    - by nategoose
    I have am trying to use sed to get some info that is encoded within the path of a file which is passed as a parameter to my script (Bourne sh, if it matters). From this example path, I'd like the result to be 8 PATH=/foo/bar/baz/1-1.8/sing/song I first got the regex close by using sed as grep: echo $PATH | sed -n -e "/^.*\/1-1\.\([0-9][0-9]*\).*/p" This properly recognized the string, so I edited it to make a substitution out of it: echo $PATH | sed -n -e "s/^.*\/1-1\.\([0-9][0-9]*\).*/\1/" But this doesn't produce any output. I know I'm just not seeing something simple, but would really appreciate any ideas about what I'm doing wrong or about other ways to debug sed regular expressions.

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  • Finding all CLASSPATH resources matching a pattern

    - by binil
    I want to read a bunch of text files, by loading them as resources using the context classloader. URL url = Thread.currentThread() .getContextClassloader() .getResource("folder/foo.txt"); Is there some way to get a list of resources whose names match a given pattern? For eg: URL[] matchingUrls = someLibrary.getMatchingResources("folder/*.txt"); Libraries like Spring can scan the classpath to find classes with a given annotation, so I am wondering if there something similar to load a bunch of resources.

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  • Java replace all capturing groups

    - by Don
    Hi, If I have a regex with a capturing group, e.g. foo(g.*f). If I match this against a string and want to replace the first capturing group in all matches with baz so that foog___f blah foog________f is converted to: foobaz blah foobaz There doesn't appear to be any easy way to do this using the standard libraries, because the Matcher.replaceAll() method will only replace all matches of the entire pattern, am I missing something? Obviously I can just iterate through the matches, store the start and end index of each capturing group, then go back and replace them, but is there an easier way? Thanks, Don

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  • replace capturing group

    - by Don
    Hi, If I have a regex with a capturing group, e.g. foo(_+f). If I match this against a string and want to replace the first capturing group in all matches with baz so that foo___f blah foo________f is converted to: foobaz blah foobaz There doesn't appear to be any easy way to do this using the standard libraries. If I use Matcher.replaceAll() this will replace all matches of the entire pattern and convert the string to baz blah baz Obviously I can just iterate through the matches, store the start and end index of each capturing group, then go back and replace them, but is there an easier way? Thanks, Don

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  • Regular Expression; Find whether a line contains any word with more than X characters.

    - by Simpsoid
    Hi, I am trying to use a Validator on a ASP.NET site and need to find whether the Street Address textbox contains a valid entry. Entries with words that are longer than X characters (in this case 25, with no punctuation or spaces) will cause the HTML on a printed A4 page to not wrap properly and therefore not to confrom to certain sizes correctly pushing the margins off. For a street address I want to match that something like "201 Long Road" is valid but "235 ReallyLongAndNarrowWindingRoadBesideTheRiver Street" is invalid. Using a Microsoft .Net Regular Expression Validator I need to know what the RegEx pattern might be. I think if it does find a match the Validator will fire correctly however if there is no match the Validator won't fire and the Update button (in this case) won't fire. Since Street addresses can contain Capital Letters and numbers etc. it will need to accomodate for that and also Spaces, Commas, Semi-Colons and Colons and Hyphens are valid characters too. Any help would be greatly appreciated as I am really stuck with this problem. Thanks, David

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  • Regular Expression to recognise truncated forms of search string?

    - by Moonshield
    I'm trying to formulate a regular expression which will recognise the search term truncated by any number of characters from the right. For example, if the search term is "pickle", the regex should recognise "pi", "pick" but not "pickaxe". Initially I came up with the following: p(i(c(k(l(e)?)?)?)?)? That works perfectly, but seems a crude way of doing it. Is there a better way of doing this? I had a look around for something similar to what I want, but I'm not entirely sure what to search for.

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  • Removing repeated characters, including spaces, in one line

    - by Thumper
    I currently have a string, say $line='55.25040882, 3,,,,,,', that I want to remove all whitespace and repeated commas and periods from. Currently, I have: $line =~ s/[.,]{2,}//; $line =~ s/\s{1,}//; Which works, as I get '55.25040882,3', but when I try $line =~ s/[.,\s]{2,}//; It pulls out the ", " and leaves the ",,,,,,". I want to retain the first comma and just get rid of the whitespace. Is there a way to elegantly do this with one line of regex? Please let me know if I need to provide additional information.

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  • Question about regex in linux commands.

    - by smwikipedia
    I ran the following command at linux bash: apt-cache search hex.*(view|edit) My intention was to find any software packages whose name/description contains the pattern 'hex.*(view|edit)'. But among the results I got this: kipi-plugins - image manipulation/handling plugins for KIPI aware programs How could this be in the results list? I didn't see any matching string in this result. Is this a bug of the apt-cache search command? Or do I mis-understand how the regex is used by this command? Many thanks.

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  • Need to create regular expression in Javascript to check the valid conditional string

    - by user1796078
    I want to create the regular expression in javascript which will check the valid conditional string like -1 OR (1 AND 2) AND 1 -1 OR (1 AND 2) -1 OR 2 -1 OR 1 OR 1 -1 AND 1 AND 1 The string should not contain 'AND' and 'OR'. For example - 1 OR 2 AND 3 is invalid. -It should be (1 OR 2) AND 3 or 1 or (2 AND 3). I tried the following Regex. It works for most of the conditions but it is failing to check the above condition. /^(\s*\(\d+\s(AND|OR)\s\d+\)|\s*\d+)((\s*(AND|OR)\s*)(\(\d+\s(AND|OR)\s\d+\)|\s*\d+))*$/ Can anyone please help me to sort out the above problem.

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  • jQuery sanitizing comments and linkifying URLs

    - by iWasRobbed
    In terms of jQuery (or Javascript), what happens behind the scenes when a person posts a comment on Facebook, Twitter, or a blog? For instance, do they sanitize the text first, and then pattern match URL's into an actual link? Are there other items of concern that the client-side should check in addition to doing some checks on the backend? I have found a few regex's for turning URL's into links, but I'm not sure if there are better solutions. I'm trying to wrap my head around the problem, but I'm having a difficult time knowing where to start. Any guidance you can provide is greatly appreciated!

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  • Matching id's in BeautifulSoup

    - by Ockonal
    Hello, I'm using BeautifulSoup - python module. I have to find any reference to the div's with id like: 'post-#'. For example: <div id="post-45">...</div> <div id="post-334">...</div> How can I filter this? html = '<div id="post-45">...</div> <div id="post-334">...</div>' soupHandler = BeautifulSoup(html) print soupHandler.findAll('div', id='post-*') > []

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  • Jquery Match() IP Address?

    - by user1635970
    I'm using a jquery script to validate form fields. This works well, but I'd like to change the validation of one field to check for IP Addresses. The regex I want to use is : \b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b How do I amend the below to work with this ? (This is how the validation works for email address) jQuery("#Email").validate({ expression: "if (VAL.match(/^[^\\W][a-zA-Z0-9\\_\\-\\.]+([a-zA-Z0-9\\_\\-\\.]+)*\\@[a-zA-Z0-9_]+(\\.[a-zA-Z0-9_]+)*\\.[a-zA-Z]{2,4}$/)) return true; else return false;", message: "Should be a valid Email id" });

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  • Matching String.

    - by Harikrishna
    I have a string String mainString="///BUY/SELL///ORDERTIME///RT///QTY///BROKERAGE///NETRATE///AMOUNTRS///RATE///SCNM///"; Now I have another strings String str1= "RT"; which should be matched only with RT which is substring of string mainString but not with ORDERTIME which is also substring of string mainString. String str2= "RATE" ; And RATE(str2) should be matched with RATE which is substring of string mainString but not with NETRATE which is also substring of string mainString. How can we do that ?

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  • RegularExpressionValidator always fails, but ValidationExpression works in testing

    - by Jerph
    I found the answer to this, but it's a bit of a gotcha so I wanted to share it here. I have a regular expression that validates passwords. They should be 7 to 60 characters with at least one numeric and one alpha character. Pretty standard. I used positive lookaheads (the (?= operator) to implement it: (?=^.{7,60}$)(?=.*[0-9].*)(?=.*[a-zA-Z].*) I checked this expression in my unit tests using Regex.IsMatch(), and it worked fine. However, when I use it in a RegularExpressionValidator, it always fails. Why?

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  • Getting automatic matching brace in vim

    - by Bob
    I spend WAY to much time fumbling around because vim doesn't handle closing braces like most IDEs do. Here's what I want to happen: type this: if( whatever ) { <CR> where <CR> mean hit the enter key and get this: if( whatever ) { | } where | is the position of the cursor. It's what Eclipse does. It's what Visual Studio does. And it's what I want Vim to do. I've seen a few plugins, tried a few, and none of them seem to give me this behavior. Surely I can't be the first programmer to want this.

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  • String contains all the elements of a list

    - by CSSS
    I am shifting to Python, and am still relatively new to the pythonic approach. I want to write a function that takes a string and a list and returns true if all the elements in the list occur in the string. This seemed fairly simple. However, I am facing some difficulties with it. The code goes something like this: def myfun(str,list): for a in list: if not a in str: return False return True Example : myfun('tomato',['t','o','m','a']) should return true myfun('potato',['t','o','m','a']) should return false myfun('tomato',['t','o','m']) should return true Also, I was hoping if someone could suggest a possible regex approach here. I am trying out my hands on them too.

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  • comma in regex in String.replaceAll() method?

    - by kknight
    My code tries to replace "," with "/" in a string. Should I escape "," in the regex string? Both of the two code snippets generated the same results, so I am confused. Code snippet 1: String test = "a,bc,def"; System.out.println(test.replaceAll("\\,", "/")); Code snippet 2: String test = "a,bc,def"; System.out.println(test.replaceAll(",", "/")); Should I use "," or "\,"? Which is safer? Thanks.

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  • sip.conf configuration file - add new line to each record

    - by Flukey
    I have a sip configuration file which looks like this: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no For each record I need to add another line (vmxten for each record) for example the above becomes: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1664 [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1679 [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1700 [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1701 What would you say would be the quickest way to do this? there are hundreds of records in the file, therefore modifying all of the records by hand would take a long time. Would you use Regex? Would you use sed? I'm interested to know how you would approach the problem. Thanks

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  • PHP: parse URL for matching directory /somedirectory/ and execute conditional code

    - by Scott B
    This has to be pretty simple, but I'd like to parse the current URL and execute conditional code depending on whether the user is on the /sitemap/ directory. So for example, if the site is example.com, and if the request is example.com/sitemap/. Then I want to execute conditional code in that case. I'm using wordpress so I'm not sure if there is a built-in function that gets this... A pure PHP solution is fine.

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  • Cross vertion line matching.

    - by BCS
    I'm considering how to do automatic bug tracking and as part of that I'm wondering what is available to match source code line numbers (or more accurate numbers mapped from instruction pointers via something like addr2line) in one version of a program to the same line in another. (Assume everything is in some kind of source control and is available to my code) The simplest approach would be to use a diff tool/lib on the files and do some math on the line number spans, however this has some limitations: It doesn't handle cross file motion. It might not play well with lines that get changed It doesn't look at the information available in the intermediate versions. It provides no way to manually patch up lines when the diff tool gets things wrong. It's kinda clunky Before I start diving into developing something better: What already exists to do this? What features do similar system have that I've not thought of?

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  • .net equivalent for php preg_replace

    - by Hath
    What is the c#.net equivalent for php's preg_replace function? php code is like this: const ALLOW_VALUES = '[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]'; public function streetTownHash($data, $hashCheck = false, $updateRecord = false) { foreach($data as $key=>$value){ try{ $value = mb_convert_case($value, MB_CASE_LOWER, "UTF-8"); } catch(Exception $e) { echo "Requires extension=php_mbstring.dll enabled ! - $e"; } $valueConcat .= preg_replace('/'.self::ALLOW_VALUES.'/','',$value); # Remove punctuation etc } $streetTownHash = sha1($valueConcat); .... this is as far as i've got but not sure about it.. private SHA1 hash = SHA1.Create(); private string hashAllowed = "[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]"; public string HashString(string value) { value = // = regex not sure this part var bytes = ASCIIEncoding.UTF8.GetBytes(value); var hashed = hash.ComputeHash(bytes); return ASCIIEncoding.UTF8.GetString(hashed); }

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  • Searching for URL's Relative to Site Root in Javascript Source

    - by James
    Hi, I am working on a web site with several other developers and we have had problems where people commit JavaScript code with AJAX calls that use URL's relative to the site root. An example would be /Home/Index which will not work if the site is hosted in a virtual directory. To get round the problem we use a $.url() method to convert it to a full path, e.g. $("#container").load($.url("/Home/Index")) I am trying to write a unit test that will search each JavaScript file and find places where the $.url method is not being used. The only problem is that I cannot seem to write a regex expression to do this. I have tried the following: (?!\$\.url\()"(/\w*)+" But this does not work. I cannot find a way to say that I don't want the $.url in front. Does anyone know if this is possible? Note that I need regular expressions that are compatible with .NET Thanks.

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  • Need help with regular expressions - URL redirection

    - by paperless
    Hello everyone. I'm trying to redirect an easy to remember url to a php file but I'm having some trouble with the regex. Here's what I have at the moment: RewriteRule ^tcb/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,}) /tcb/lerbd.php?autocarro=$1&tipo=$2&dsd=$3 It is working but only if I supply all 3 arguments. I want the last two arguments to be optional so it either works with only the first or all three. I'm hoping you can help me with this. Thank you very much.

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