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  • form with multiple upload but allow no upload on edit problems

    - by minus4
    hiya i have a section that when created takes in images, however when you edit this item i dont want them to re-upload none changes images just to change a description or name. i have created this that deals with uploading files: public void UploadFiles(string currentFileName, FormCollection form) { // loop through all files in form post foreach (string file in Request.Files) { HttpPostedFileBase hpf = Request.Files[file]; // if no file is uploaded, we could be editing so set to current value if (hpf.ContentLength == 0) { form[file] = currentFileName; } else { //rename the file unique so we dont clash with names var filename = hpf.FileName.Replace(" ", "_").Replace(".", DateTime.Now.Date.Ticks + "."); UploadFileName = filename; hpf.SaveAs(Server.MapPath("~/Content/custom/" + filename)); // set the name of the file in our post to the new name form[file] = UploadFileName; } } // ensure value is still sent when no files are uploaded on edit if(Request.Files.Count <= 0) { UploadFileName = currentFileName; } } all works fine when only one image is required (CurrentFileName), however there is now a new image available taking it to a total of 2 images in the database therefor currentFileName is obsolete. has anyone tackled this and how as i have hit a wall with this one. thought of string[] currentFiles but cant see how to match this into string file in Request.Files. if it helps i am also working with models for the form so i could pass over the model but i dont think your able to do model.file without some kind of reflection. help much appreciated. thanks

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  • Kohana 3 jQuery/AJAX request not working

    - by dscher
    I am trying to post some data to a controller in Kohana 3 using the jQuery AJAX method. I seem to have an issue with the data not getting to where I want it to be. I want the data to go to the /application/classes/controller/stock.php file where the file will process the data. I can't seem to figure this one out. Hopefully someone can help. My jQuery ajax call is: $.ajax({ type: 'POST', url: 'add_stock', data: { 'links': 'link_array' } }); 'add_stock' is the name of the action within the controller. I didn't know what else to try. I've also tried '.' and './' hoping that would be right but it's not. In Firebug, although it says the request was 200 OK, I see that the "RESPONSE" is "Failed to load source for: http://localhost/ddm/v2/stocks/add_stock" and my script in my controller which grabs the data isn't working. Here is that code in case it helps: $links = $_POST['links']; $link_obj = Jelly::factory('link') ->set('stock', $stock->id) ->set('links', $links); $link_obj->save(); I think that the problem is that I'm giving the ajax call the ROUTE and not the actual page it needs to deliver the POST data to. I just can't figure it out here. Any help?

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  • login form using ajax, to submit without refreshing

    - by Brad
    I am using this tutorial to create a login form http://www.ryancoughlin.com/2008/11/04/use-jquery-to-submit-form/ It authenticates against w/ our ldap server. What I am having a problem with is the line success: function(){ $('form#submit').hide(function(){$('div.success').fadeIn();}); It runs success even though we don't even know if the username and password binded successfully. Is there a way to only run success if the username and password posted was binded successfully?

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  • UserControl Behaviour on a Windows Form

    - by AK
    Hi, I have a usercontrol UC1 with a combobox and a button. From the constructor, after initializing all the controls, I am populating the combobox with an array of information brought from other class library. I have kept the UC1 on windows form. When I tried to open the form's designer I see some errors and a suggestion to rebuild to fix the errors. After searching over net I found that the logic of populating the combobox is the culprit. I changed the code with an additional check of null and the issue is fixed now. My question is, how am i able to see the same usercontrol seperatly in designer view, but not when i placed the UC1 on a form and trying to see the designer view for the form? The same combobox populating logic should affect the drawing of UC1 when I try to see it in designer view right? Thanks, AK.

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  • A Django form for entering a 0 to n email addresses

    - by Erik
    I have a Django application with some fairly common models in it: UserProfile and Organization. A UserProfile or an Organization can both have 0 to n emails, so I have an Email model that has a GenericForeignKey. UserProfile and Organization Models both have a GenericRelation called emails that points back to the Email model (summary code provided below). The question: what is the best way to provide an Organization form that allows a user to enter organization details including 0 to n email addresses? My Organization create view is a Django class-based view. I'm leading towards creating a dynamic form and an enabling it with Javascript to allow the user to add as many email addresses as necessary. I will render the form with django-crispy-forms. I've thought about doing this with a formset embedded within the form, but this seems like overkill for email addresses. Embedding a formset in a form delivered by a class-based view is cumbersome too. Note that the same issue occurs with the Organization fields phone_numbers and locations. emails.py: from django.db import models from parent_mixins import Parent_Mixin class Email(Parent_Mixin,models.Model): email_type = models.CharField(blank=True,max_length=100,null=True,default=None,verbose_name='Email Type') email = models.EmailField() class Meta: app_label = 'core' organizations.py: from emails import Email from locations import Location from phone_numbers import Phone_Number from django.contrib.contenttypes import generic from django.db import models class Organization(models.Model): active = models.BooleanField() duns_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this emails = generic.GenericRelation(Email,content_type_field='parent_type',object_id_field='parent_id') legal_name = models.CharField(blank=True,default=None,null=True,max_length=200) locations = generic.GenericRelation(Location,content_type_field='parent_type',object_id_field='parent_id') name = models.CharField(blank=True,default=None,null=True,max_length=200) organization_group = models.CharField(blank=True,default=None,null=True,max_length=200) organization_type = models.CharField(blank=True,default=None,null=True,max_length=200) phone_numbers = generic.GenericRelation(Phone_Number,content_type_field='parent_type',object_id_field='parent_id') taxpayer_id_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this class Meta: app_label = 'core' parent_mixins.py from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic from django.db import models class Parent_Mixin(models.Model): parent_type = models.ForeignKey(ContentType,blank=True,null=True) parent_id = models.PositiveIntegerField(blank=True,null=True) parent = generic.GenericForeignKey('parent_type', 'parent_id') class Meta: abstract = True app_label = 'core'

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  • how to create a 2 column to seperate label and input element in a form

    - by Blankman
    My form looks like: ** <p><label>first name</label><input type=text name=fn /></p> <p><label>last name</label><input type=text name=ln /></p> </div> <div id="rightform"> <p><label>state</label><input type=text name=state /></p> <p><label>city</label><input type=text name=city /></p> </div> ** I want the layout so all the labels line up on the left (with the label text right-aligned), and the input box all lined up, floating to the left. So the form should look like: asdf-label INPUTBOX 123-label INPUTBOX yet-another-label INPUTBOX There will be another form on the right side of the above form (with the id=#rightform) Really confused how to do this properly...

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  • Investigating the root cause behind SharePoint's "request not found in the TrackedRequests"

    - by Muhimbi
    We have a long standing issue in our bug tracking system about the dreaded "ERROR: request not found in the TrackedRequests. We might be creating and closing webs on different threads." message in SharePoint's trace log. As we develop Workflow software for the SharePoint market, we look into this issue from time to time to make sure it is not caused by our products. I have personally come to the conclusion that this is a problem in SharePoint, but perhaps someone else can prove me wrong. Here is what I know: According to the hundreds of search results returned by Google on this topic, this issue appears to be mainly related to SharePoint Workflows, both SharePoint Designer and Visual Studio based workflows. Assuming ULS logging is set to Monitorable, the easiest way to reproduce this problem is to create a new SharePoint Designer Workflow, attach it to a document library, set it to auto start on add/update, don't add any actions, save the workflow and upload a file to the document library. The error is only visible in the SharePoint trace log, it does not appear to impact the execution of the workflow at hand. I have verified that the problem occurs on 32 bit as well as 64 bit systems, Win2K3 and 2K8, WSS and MOSS with SharePoint versions up to the December 2009 Cumulative Update (6524). The problem does not occur when a workflow is started manually. There are dozens of related posts on MSDN Forums, hundreds on Google, one on StackOverflow and none on SharePoint Overflow. There appears to be no answer. Does anyone have any idea about what is going on, what is causing this and if we should worry or file this under 'Red Herrings'.

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  • how to Decorate the error message on zend framework

    - by ulduz114
    this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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  • Cannot populate form with ajax and populate jquery plugin

    - by Azriel_
    I'm trying to populate a form with jquery's populate plugin, but using $.ajax The idea is to retrieve data from my database according to the id in the links (ex of link: get_result_edit.php?id=34), reformulate it to json, return it to my page and fill up the form up with the populate plugin. But somehow i cannot get it to work. Any ideas: here's the code: $('a').click(function(){ $('#updatediv').hide('slow'); $.ajax({ type: "GET", url: "get_result_edit.php", success: function(data) { var $response=$(data); $('#form1').populate($response); } }); $('#updatediv').fadeIn('slow'); return false; whilst the php file states as follow: <?php $conn = new mysqli('localhost', 'XXXX', 'XXXXX', 'XXXXX'); @$query = 'Select * FROM news WHERE id ="'.$_GET['id'].'"'; $stmt = $conn->query($query) or die ($mysql->error()); if ($stmt) { $results = $stmt->fetch_object(); // get database data $json = json_encode($results); // convert to JSON format echo $json; } ?> Now first thing is that the mysql returns a null in this way: is there something wrong with he declaration of the sql statement in the $_GET part? Second is that even if i put a specific record to bring up, populate doesn't populate. Update: I changed the populate library with the one called "PHP jQuery helper functions" and the difference is that finally it says something. finally i get an error saying NO SUCH ELEMENT AS i wen into the library to have a look and up comes the following function function populateFormElement(form, name, value) { // check that the named element exists in the form var name = name; // handle non-php naming var element = form[name]; if(element == undefined) { debug('No such element as ' + name); return false; } // debug options if(options.debug) { _populate.elements.push(element); } } Now looking at it one can see that it should print out also the name, but its not printing it out. so i'm guessing that retrieving the name form the json is not working correctly. Link is at http://www.ocdmonline.org/michael/edit%5Fnews.php with username: Testing and pass:test123 Any ideas?

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  • spring add default value to form:select

    - by Mike
    I'm developing a spring application, now I've added a dropdownlist to one of my jsp pages using: <form:select multiple="single" path="users[y.count-1].X" items="${Y}" itemValue="id" itemLabel="name"/> Now I'd like to add the default value "Nothing selected", however I can't seem to find how to do this. I've tried: <form:select multiple="single" path="users[y.count-1].X" items="${Y}" itemValue="id" itemLabel="name"> <form:option value="Nothing selected" /> </form:select> But "Nothing selected" isn't displayed in my dropdownlist.

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  • Gravatar XML-RPC request problem in Objective-C

    - by Erik
    Hi all, I'm trying to incorporate some Gravatar functionality using its XML-RPC API in an iPhone app I'm writing. I grabbed the Cocoa XML-RPC Framework by Eric Czarny (http://github.com/eczarny/xmlrpc) and it works well when I tested it with some of the Wordpress methods. However, when I try to use the Gravatar API, I always receive a response of "Error code: -9 Authentication error". I think I'm constructing the request correctly, but I've been wracking my brain and can't seem to figure it out. Maybe someone has some experience with this API or can see what I'm doing wrong. Here's the call: <?xml version="1.0"> <methodCall> <methodName>grav.addresses</methodName> <params> <param><value><string>PASSWORD_HERE</string></value></param> </params> </methodCall> Again, the Cocoa XML-RPC Framework worked like a dream with Wordpress, but it's choking on the Gravatar API for some reason. Thanks for your help.

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  • Creating a nested model form

    - by Elliot
    Hey Guys, I'm trying to build a multi model form - but one of the issues, is I need to link the models within the form. For example, lets say the form I have has the following models: Users, Profiles When creating a new user, I'd like to create a new profile simultaneously, and then link the two. The issue is, if neither have been created yet, they don't have ID's yet - so how can I assign linking values? Thanks! -Elliot

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  • Trying to inherit variable "text" from Form 1 for use in Form 2????

    - by JB
    I have a Form 1 as listed below, im trying to inherit the variable text from it so i can compare is value in an if statement so i can output the file specified for that id number in Form 2...is this possible??? Form 1, where variable is being used: public void button2_Click(object sender, System.EventArgs e) { timer1.Enabled = true; string text = textBox1.Text; Mainform = this; this.Hide(); } Form 2 where im trying to use the variable: if (text == "900456318") { System.Diagnostics.Process.Start("C:\\Users\\Joshua Banks\\Desktop\\Downtown_atlanta_night"); } }

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  • Form submit event problem

    - by developer 2010
    <form id="form1" runat="server" onsubmit="return CheckForm(this)"> <script type="text/javascript" language="javascript"> function CheckForm(frm) { if(CheckEntireForm(frm) == false) return false; } </script> Hello EveryBody Please help me to get solution I've used a javascript function on form's onSubmit event like which validates my page's textboxes etc. NOTE: i am not using asp.net's validation. i have got my own validation classes I've also used a dropdownlist with auto post back set to true in asp.net 2.0 when dropdownlist's selected index is changed it calls form's onsubmit while this did not use to happen in asp.net 1.1 I've used this on 140 pages in my website the worst case will be to call CheckForm(this.form) on my save buttons client click on all the pages. I am looking for a backword compatibility solution which can be applied at a single place like web.config or some class etc. i am using asp.net and javascript

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  • Extract form variable in AJAX response using jquery

    - by Jake
    All, I have a Jquery ajax request calling out a URL. The ajax response I receive is an HTML form with one hidden variable in it. As soon as my ajax request is successful, I would like to retrieve the value of the hidden variabl. How do I do that? Example: html_response for the AJAX call is : <html><head></head><body><form name="frmValues"><input type="hidden" name="priceValue" value="100"></form></body></html> $.ajax({ type: 'GET', url: "/abc/xyz/getName?id="+101, cache: false, dataType: "html", success: function(html_response) { //Extract form variable "priceValue" from html_response //Alert the variable data. } }); Thanks

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  • Django upload failing on request data read error

    - by Jake
    Hi All, I've got a Django app that accepts uploads from jQuery uploadify, a jQ plugin that uses flash to upload files and give a progress bar. Files under about 150k work, but bigger files always fail and almost always at around 192k (that's 3 chunks) completed, sometimes at around 160k. The Exception I get is below. exceptions.IOError request data read error File "/usr/lib/python2.4/site-packages/django/core/handlers/wsgi.py", line 171, in _get_post self._load_post_and_files() File "/usr/lib/python2.4/site-packages/django/core/handlers/wsgi.py", line 137, in _load_post_and_files self._post, self._files = self.parse_file_upload(self.META, self.environ[\'wsgi.input\']) File "/usr/lib/python2.4/site-packages/django/http/__init__.py", line 124, in parse_file_upload return parser.parse() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 192, in parse for chunk in field_stream: File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 314, in next output = self._producer.next() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 468, in next for bytes in stream: File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 314, in next output = self._producer.next() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 375, in next data = self.flo.read(self.chunk_size) File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 405, in read return self._file.read(num_bytes) When running locally on the Django development server, big files work. I've tried setting my FILE_UPLOAD_HANDLERS = ("django.core.files.uploadhandler.TemporaryFileUploadHandler",) in case it was the memory upload handler, but it made no difference. Does anyone know how to fix this?

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  • JQuery form submit Question?

    - by SLAPme
    I'm kind of new to JQuery and was wondering how can I have the following text appear when the user submits there changes <p>Your changes have been saved.</p>? How do I fix my code so it displays this message? JQuery script. $(function() { $(".save-button").click(function() { $.post($("#contact-form").attr("action"), $("#contact-form").serialize(), function(html) { $("div.contact-info-form").html(html); }); return false; // prevent normal submit }); }); Here is the html. <div id="contact-info-form" class="form-content"> <h2>Contact Information</h2> <form method="post" action="index.php" id="contact-form"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><p>Changes have been saved</p><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form> </div>

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  • Adding Window Media Player in Win Form

    - by Emaad Ali
    Hi, i am developing a window form application i have to add window media player in form so that a user can play video on spot just clicking on media player play button. Can anyone tellme how i can achieve that functionality just tell how to add it in form. i am using C# with 3.5 framework thanks

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  • Send form when hitting enter

    - by Álvaro G. Vicario
    I have a form in a jQuery enabled site. The form does not feature an <input type="submit"> button. For that reason, it's not submitted when you hit enter. What's the recommended way to emulate such behaviour? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html lang="en"> <head><title></title> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"><!-- $(function(){ $("form input:first").focus(); }); //--></script> </head> <body> <form action="" method="post"> <input type="text" name="user"> <input type="password" name="pass"> </form> </body> </html>

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  • Single Form with Multiple Dynamic Buttons

    - by John Reilly
    I've spent hours/days trying to figure this out and now I'm completely perplexed so I thought I'd give stackoverflow a try. I'm (a newb) working in Java/JSP using Eclipse hosting on Google App Engine trying to develop an app for a volunteer organization I'm a member of. Rather than embarrass myself by showing my current code I'd love just a nudge in the right direction. I have a form (which doubles as a report basically) showing "people" grouped under the "task" they are currently working on. I would like to select multiple people from multiple tasks and reassign them to another task e.g. Bill and Jane are Gardening, Jeff is Painting. I want to select Jane and Jeff (all people have an associated checkbox in the form) and re-assign them to Sweeping (which is a task on the form but has no people assigned to it yet). Ideally, the re-assignment to Sweeping would be via a Sweeping button (each task would have a dynamically-created task button) that would pass the "Sweeping" value to a servlet along with an array or list of people whose checkbox has been checked. The servlet would handle the request (creating an Assignment "object/entity" with timeStamp, personId, taskId) and then re-direct back to the form/report which would then repaint with the current tasks/people generated from the Assignments class in the datastore. All the tasks are user-defined and retrieved from the database when building the form. Ditto the people. I've been trying to keep the jsp for presentation and the servlets for the processing but I'm no purist and would just like to get unstuck. Many thanks in advance for your assistance.

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  • Drupal 6 - Including a module form in a view

    - by espais
    I'm making use of the Favorites module, in order to allow my users to favorite nodes they like. Currently, I know that there is a block available for listing out the favorites, along with the 'Add to favorites' button at the top of this list. What I'd like to do is generate the form which includes the button, and include it within each node that I generate. I'd gotten it hacked up and quickly working by copying the generated form and placing it in my views-view--fields-.tpl.php template, however I believe that doing it this way goes against the thought behind Drupal, and probably introduces security issues with the form_id and form_token being hand-written. I've attempted to call the get_form function, and have passed it the form_id that I found in the generated form code, however I can't get Drupal to recognize it. From some Googling I've noticed that generating module forms programmatically may require a hook, but I haven't been able to find any good examples of this. What is the best way to go about creating this form?

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  • Issue with multipart/form-data

    - by kbrin80
    I am not able to get values from both files and text input in a servlet when my form includes multipart/form-data. I am using the apache.commons.fileuploads for help with the uploads. Any suggestions. Also in the code below there are some things that I feel should be more efficient. Is there a better way to store these multiple files in a db. public void performTask(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response) { boolean promo = false; Database db = new Database(); Homepage hp = db.getHomePageContents(); String part = ParamUtils.getStringParameter(request, "part", ""); if(part.equals("verbage")) { String txtcontent = (String)request.getParameter("txtcontent"); String promoheader = (String)request.getParameter("promoheader"); String promosubheader = (String)request.getParameter("promosubheader"); hp.setBodyText(txtcontent); hp.setPromoHeader(promoheader); hp.setPromoSubHeader(promosubheader); System.err.println(txtcontent); } else { boolean isMultipart = ServletFileUpload.isMultipartContent(request); if (!isMultipart) { } else { FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List items = null; try { items = upload.parseRequest(request); //System.err.print(items); } catch (FileUploadException e) { e.printStackTrace(); } Iterator itr = items.iterator(); while (itr.hasNext()) { FileItem item = (FileItem) itr.next(); if(item.getFieldName().equals("mainimg1")) { if(item.getName() !="") hp.setMainImg1(item.getName()); } if(item.getFieldName().equals("mainimg2")) { if(item.getName() !="") hp.setMainImg2(item.getName()); } if(item.getFieldName().equals("mainimg3")) { if(item.getName() !="") hp.setMainImg3(item.getName()); } if(item.getFieldName().equals("promoimg1")) { promo = true; if(item.getName() !="") { hp.setPromoImg1(item.getName()); try { File savedFile = new File("/Library/resin-4.0.1/webapps/ROOT/images/promoImg1.jpg"); item.write(savedFile); //System.err.print(items); } catch (Exception e) { System.err.println(e.getMessage()); } } } if(item.getFieldName().equals("promoimg2")) { if(item.getName() !="") { hp.setPromoImg2(item.getName()); try { File savedFile = new File("/Library/resin-4.0.1/webapps/ROOT/images/promoImg2.jpg"); item.write(savedFile); //System.err.print(items); } catch (Exception e) { System.err.println(e.getMessage()); } } } if(item.getFieldName().equals("promoimg3")) { if(item.getName() !="") { hp.setPromoImg3(item.getName()); try { File savedFile = new File("/Library/resin-4.0.1/webapps/ROOT/images/promoImg3.jpg"); item.write(savedFile); //System.err.print(items); } catch (Exception e) { System.err.println(e.getMessage()); } } } System.err.println("FNAME =" + item.getFieldName() + " : " + item.getName()); if (item.isFormField()) { } else { try { if(!promo) { String itemName = item.getName(); File savedFile = new File("/Library/resin-4.0.1/webapps/ROOT/images/"+itemName); item.write(savedFile); } //System.err.print(items); } catch (Exception e) { System.err.println(e.getMessage()); } } } } } db.updateHomePageContent(hp);

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  • Problems with GData Request Token

    - by Dan Delgado
    We have successfully used GData libraries to access a user's Google Docs. But we encountered problems when many users log in to our site and authorize our web app at the same time or successively. Here's what happens: First user successful logs in, authorizes our web app via OAuth and is able to add rubric (or google spreadsheet). Second user, immediately after first user adds a rubric, successfully logs in then webapp fails on authorize (Token not given. I tried to log it.) Third user fails on login. Fourth user was able to log in, authorize via OAuth, and create rubrics successfully. Fifth user was able to log in but like the second user, gets an invalid token on authorize (Token not given.) And the list goes on. Results were unpredicatable. Below is an excerpt of the stack trace we get when the fail scenario happens: Nested in org.springframework.web.util.NestedServletException: Request processing failed; nested exception is java.lang.NullPointerException: java.lang.NullPointerException at com.google.gdata.client.authn.oauth.OAuthUtil.normalizeParameters(OAuthUtil.java:158) at com.google.gdata.client.authn.oauth.OAuthUtil.getSignatureBaseString(OAuthUtil.java:81) at com.google.gdata.client.authn.oauth.OAuthHelper.addCommonRequestParameters(OAuthHelper.java:649) at com.google.gdata.client.authn.oauth.OAuthHelper.getOAuthUrl(OAuthHelper.java:592) at com.google.gdata.client.authn.oauth.OAuthHelper.getUnauthorizedRequestToken(OAuthHelper.java:276) at com.projectrix.controller.OAuthController.authorize(OAuthController.java:59) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Method.java:40) Help!

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  • Good way to handle inline-edit form using Rails and jQuery

    - by Tim Sullivan
    I have a list of items, being displayed in a series of DIVs. When someone clicks on an "edit" link, I want to replace the div with a form that will let them edit the contents of that item in a nice way. I'm trying to think of the ideal way to handle this. Do I create a hidden edit form for every item in the list, and hook the edit link to reveal it, like this: <div> <a href="#">edit</a> Item One <div id="edit_1202" class="editform">Edit form goes here</div> </div> <div> <a href="#">edit</a> Item Two <div id="edit_2318" class="editform">Edit form goes here</div> </div> Or is there a better way to fetch the data and insert the form's HTML into the right spot? Remember, I'm using jQuery, so I can't use the prototype helpers. Thanks!

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