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• Creating a ListView and setting the background color of a view in each row.

  - by Tarmon

  Hey Everyone, I am trying to implement a ListView that is composed of rows that contain a View on the left followed by a TextView to the right of that. I want to be able to change the background color of the first View based on it's position in the ListView. Below is what I have at this point but it doesn't seem to due anything. public class Routes extends ListActivity { String[] ROUTES; TextView selection; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); ROUTES = getResources().getStringArray(R.array.routes); setContentView(R.layout.routes); setListAdapter(new IconicAdapter()); selection=(TextView)findViewById(R.id.selection); } public void onListItemClick(ListView parent, View v, int position, long id) { selection.setText(ROUTES[position]); } class IconicAdapter extends ArrayAdapter<String> { IconicAdapter() { super(Routes.this, R.layout.row, R.id.label, ROUTES); } } public View getView(int position, View convertView, ViewGroup parent) { LayoutInflater inflater = getLayoutInflater(); View row = inflater.inflate(R.layout.row, parent, false); TextView label = (TextView) row.findViewById(R.id.label); label.setText(ROUTES[position]); View icon = (View) row.findViewById(R.id.icon); switch(position){ case 0: icon.setBackgroundColor(R.color.Red); break; case 1: icon.setBackgroundColor(R.color.Red); break; case 2: icon.setBackgroundColor(R.color.Green); break; case 3: icon.setBackgroundColor(R.color.Green); break; case 4: icon.setBackgroundColor(R.color.Blue); break; case 5: icon.setBackgroundColor(R.color.Blue); break; } return(row); } } Any input is appreciated and if you have any questions don't hesitate to ask! Thanks, Rob

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• Adding scrollbars to UserControl

  - by Bevin

  I am trying to add vertical and horizontal scrollbars to my UserControl with the HorizontalScroll and VerticalScroll properties, but I am having extreme issues. My problem arises when I drag or manipulate the scroll box on the bar. When I let it go, it simply jumps back to the start position! I know of the AutoScroll property, but I do not want to use it since I want to be able to control every aspect of my scrollbars, and I don't want it to be done automatically. Also, according to the documentation, AutoScroll is for "[enabling] the user to scroll to any controls placed outside of its visible boundaries" which isn't what I want. I just want scrollbars. ...aaand I suppose I could add VScrollBar and HScrollBar to the control, but why should I do this when the scroll functionality already exists? Seems like a waste to me.

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• how do i add two delegates to a ui element at run time?

  - by Michael Xu

  Hi everyone, im trying to implement some behaviors when a mapview element scrolls... by coding a delegate for the scrollview inside of a mapview. so, right now, i got a pointer to the scroll view used by the map view in my code. however, i wish to set the delegate of this scroll view inside the map view, but the issue is that the mapview already sets up a default delegate for this scroll view inside the map view. can i make my delegate implement all of the messages of the protocol, explicitly sending them to the mapview's default delegate while also implementing my own behaviors? how else can i go about adding my own delegate behavior, to an already existing default delegate....? thanks everyone, michael

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• How to calculate both positive and negative angle between two lines?

  - by Jaanus

  There is a very handy set of 2d geometry utilities here. The angleBetweenLines has a problem, though. The result is always positive. I need to detect both positive and negative angles, so if one line is 15 degrees "above" or "below" the other line, the shape obviously looks different. The configuration I have is that one line remains stationary, while the other line rotates, and I need to understand what direction it is rotating in, by comparing it with the stationary line. EDIT: in response to swestrup's comment below, the situation is actually that I have a single line, and I record its starting position. The line then rotates from its starting position, and I need to calculate the angle from its starting position to current position. E.g if it has rotated clockwise, it is positive rotation; if counterclockwise, then negative. (Or vice versa.) How to improve the algorithm so it returns the angle as both positive or negative depending on how the lines are positioned?

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• Inserting a ContentControl after another ContentControl

  - by Markus Roth

  In our VSTO Word 2010 Addin, we are trying to insert a RichTextControl after a given other ContentControl. We have tried this: public ContentControl AddContentControl(WdContentControlType type, int position) { Paragraph paragraphBefore = null; if (position == 0) { if (WordDocument.Paragraphs.Count == 0) { WordDocument.Paragraphs.Add(); } paragraphBefore = WordDocument.Paragraphs.First; } else { paragraphBefore = Controls.ElementAt(position - 1).Range.Paragraphs.Last; } object start = paragraphBefore.Range.End; object end = paragraphBefore.Range.End + 1; paragraphBefore.Range.InsertParagraphAfter(); Range rangeToUse = WordDocument.Range(ref start, ref end); ContentControl newControl = _ContentControl = _WordDocument.ContentControls.Add(type, rangeToInsert); Controls.Insert(position, newControl); OnNewContentControl(newControl, position); return newControl.ContentControl; } which works fine, unless the control that is before the one we want to insert has an empty paragraph at the end. If that is the case, the new ContentControl is inserted within the last control. How can we avoid this?

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• Is there a way to seek a specific location in an xml by knowing the index relative to the text nodes

  - by Rachel

  I have a xml document. I know the index where i need to insert the new node. The index that i have is the position considering only the text nodes and ignoring the element tags. Is there a java api to seek the index in a xml knowing the position relative to the text nodes alone and insert a new node in that position?

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• IE z-index relative/absolute bug in list

  - by AJM

  I have the following navigation where .topNav has position:relative and subnav has position:absolute. I cant get the sublist to appear over the main list due to z-index problems. This seems to be a known problem. <ul> <li class="topNav">About Us <ul class="subNav"><li> Subsection A</li><li>Subsection B</li></ul> </li> </ul> Does anyone know of a workaround? UPDATE http://brh.numbera.com/experiments/ie7_tests/zindex.html shows exacly the problem I have. My original posting was in the context of a list but I have reduced the problem to the fact that z-index dosn't seem to work when have an element with position:absolute inside a parent element with position:relative

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• Make character escape from shot

  - by M28

  Hello all math masters, I got a problem for you: I have a 2D game (top down), and I would like to make the character escape from a shot, but not just walk away from the shot (I mean, don't be pushed by the shot), I want it to have a good dodging skills. The variables are: shotX - shot x position shotY - shot y position shotSpeedX - shot x speed shotSpeedY - shot x speed charX - character x position charY - character y position keyLeft - Set to true to make the character press the to left key keyRight - Set to true to make the character press the to right key keyUp - Set to true to make the character press the to up key keyDown - Set to true to make the character press the down key I can understand the following languages: C/C++ Java Actionscript 2/3 Javascript

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• getLocationInWindow sens me a wrong y coordinate

  - by user1805792

  When i try to get the position where i touch on an imageviewer with this code, the y position of my touch is lower than the y position that getLocationInWindows gives, so there must be something wrong int[] viewCoords = new int[2]; miViewer.getLocationInWindow(viewCoords); int touchX=(int)event.getX(); int touchY=(int)event.getY(); int imageX = touchX - viewCoords[0]; int imageY = touchY - viewCoords[1];

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• Finding what makes strings unique in a list, can you improve on brute force?

  - by Ed Guiness

  Suppose I have a list of strings where each string is exactly 4 characters long and unique within the list. For each of these strings I want to identify the position of the characters within the string that make the string unique. So for a list of three strings abcd abcc bbcb For the first string I want to identify the character in 4th position d since d does not appear in the 4th position in any other string. For the second string I want to identify the character in 4th position c. For the third string it I want to identify the character in 1st position b AND the character in 4th position, also b. This could be concisely represented as abcd -> ...d abcc -> ...c bbcb -> b..b If you consider the same problem but with a list of binary numbers 0101 0011 1111 Then the result I want would be 0101 -> ..0. 0011 -> .0.. 1111 -> 1... Staying with the binary theme I can use XOR to identify which bits are unique within two binary numbers since 0101 ^ 0011 = 0110 which I can interpret as meaning that in this case the 2nd and 3rd bits (reading left to right) are unique between these two binary numbers. This technique might be a red herring unless somehow it can be extended to the larger list. A brute-force approach would be to look at each string in turn, and for each string to iterate through vertical slices of the remainder of the strings in the list. So for the list abcd abcc bbcb I would start with abcd and iterate through vertical slices of abcc bbcb where these vertical slices would be a | b | c | c b | b | c | b or in list form, "ab", "bb", "cc", "cb". This would result in four comparisons a : ab -> . (a is not unique) b : bb -> . (b is not unique) c : cc -> . (c is not unique) d : cb -> d (d is unique) or concisely abcd -> ...d Maybe it's wishful thinking, but I have a feeling that there should be an elegant and general solution that would apply to an arbitrarily large list of strings (or binary numbers). But if there is I haven't yet been able to see it. I hope to use this algorithm to to derive minimal signatures from a collection of unique images (bitmaps) in order to efficiently identify those images at a future time. If future efficiency wasn't a concern I would use a simple hash of each image. Can you improve on brute force?

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• Removing views from UIScrollView

  - by mohan

  I have two UIScrollViews that I move images between. The user can drag and forth between the scroll views. I am trying to animate the movement of the image from one scroll view to another. In -touchesMoved (handled in my UIViewController which has two custom UIScrollViews that intercept touch and sends to my UIViewController), I am trying to set the "center" of my UIImageView that is being moved. As it is moved, the image gets hidden behind the UIScrollView and not visible. How do I make it appear on top of the UIScrollView? I am able to handle the -touchesEnded properly by animating in the destination scroll view. I am also confused about -convertPoint:fromView: usage in the iPhone Programming Guide (See Chapter 3, Event Handling). If the touch coordinates are in window coordinates, to change my view (UIImageView inside a UIScrollView which is inside a UIView and inside a window) center don't I have to use -convertPoint:toView:, i.e., imageView.center = [self.view.window convertPoint:currentTouchPosition toView:imageView]; What am I missing?

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• c#: Clean way to fit a collection into a multidimensional array?

  - by Rosarch

  I have an ICollection<MapNode>. Each MapNode has a Position attribute, which is a Point. I want to sort these points first by Y value, then by X value, and put them in a multidimensional array (MapNode[,]). The collection would look something like this: (30, 20) (20, 20) (20, 30) (30, 10) (30, 30) (20, 10) And the final product: (20, 10) (20, 20) (20, 30) (30, 10) (30, 20) (30, 30) Here is the code I have come up with to do it. Is this hideously unreadable? I feel like it's more hacky than it needs to be. private Map createWorldPathNodes() { ICollection<MapNode> points = new HashSet<MapNode>(); Rectangle worldBounds = WorldQueryUtils.WorldBounds(); for (float x = worldBounds.Left; x < worldBounds.Right; x += PATH_NODE_CHUNK_SIZE) { for (float y = worldBounds.Y; y > worldBounds.Height; y -= PATH_NODE_CHUNK_SIZE) { // default is that everywhere is navigable; // a different function is responsible for determining the real value points.Add(new MapNode(true, new Point((int)x, (int)y))); } } int distinctXValues = points.Select(node => node.Position.X).Distinct().Count(); int distinctYValues = points.Select(node => node.Position.Y).Distinct().Count(); IList<MapNode[]> mapNodeRowsToAdd = new List<MapNode[]>(); while (points.Count > 0) // every iteration will take a row out of points { // get all the nodes with the greatest Y value currently in the collection int currentMaxY = points.Select(node => node.Position.Y).Max(); ICollection<MapNode> ythRow = points.Where(node => node.Position.Y == currentMaxY).ToList(); // remove these nodes from the pool we're picking from points = points.Where(node => ! ythRow.Contains(node)).ToList(); // ToList() is just so it is still a collection // put the nodes with max y value in the array, sorting by X value mapNodeRowsToAdd.Add(ythRow.OrderByDescending(node => node.Position.X).ToArray()); } MapNode[,] mapNodes = new MapNode[distinctXValues, distinctYValues]; int xValuesAdded = 0; int yValuesAdded = 0; foreach (MapNode[] mapNodeRow in mapNodeRowsToAdd) { xValuesAdded = 0; foreach (MapNode node in mapNodeRow) { // [y, x] may seem backwards, but mapNodes[y] == the yth row mapNodes[yValuesAdded, xValuesAdded] = node; xValuesAdded++; } yValuesAdded++; } return pathNodes; } The above function seems to work pretty well, but it hasn't been subjected to bulletproof testing yet.

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• Positioning DIV's with Javascript

  - by Andrew P.

  I have two divs that I need to position horizontally dependent on the width of the user's screen. I've styled their vertical position in CSS, and I am trying to position them horizontally using Javascript. My divs: <div id="tl"> blah blah </div> <div id="bl"> blah blah </div> My CSS: #tl { position: absolute; top: -14px; right: 0; } #bl { position: absolute; bottom: 1px; right: 0; } My Javascript: var tl = document.getElementById('tl'); var bl = document.getElementById('bl'); var wide = parseInt(screen.width); var nudge = wide*.86; nudge = nudge+21; tl = tl.style; tl.right = ( parseInt(tl.right) + nudge ); bl = bl.style; bl.right = ( parseInt(bl.right) + nudge ); However... nothing happens. No errors, and definitely no movement from my divs. What am I doing wrong? Can anyone help?

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• Dragging a div along with all of its child divs

  - by roygbiv

  I have the following code: <body> <div id="container" style="position:absolute; left:0px; top:0px; z-index:1;"> <div id="div1" style="background-color:Red; position:absolute; left:0px; top:0px; width:256px; height:256px; z-index:0;" >&nbsp;</div> <div id="div2" style="background-color:Black; position:absolute; left:256px; top:0px; width:256px; height:256px; z-index:0;" >&nbsp;</div> <div id="div3" style="background-color:Green; position:absolute; left:512px; top:0px; width:256px; height:256px; z-index:0;" >&nbsp;</div> <div id="div4" style="background-color:Yellow; position:absolute; left:768px; top:0px; width:256px; height:256px; z-index:0;" >&nbsp;</div> <div id="div5" style="background-color:Blue; position:absolute; left:1024px; top:0px; width:256px; height:256px; z-index:0;" >&nbsp;</div> </div> <script type="text/javascript"> <!-- SET_DHTML("container"); //--> </script> </body> I want to drag the 'container' div such that all child divs are dragged at the same time. I can drag individual divs, but that is not what I want. Can a div drag child divs or do they have to be images? I am using the WalterZorn drag drop API, but am open to using any API, script or whatever.

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• Sorting By Multiple Conditions in Ruby

  - by viatropos

  I have a collection of Post objects and I want to be able to sort them based on these conditions: First, by category (news, events, labs, portfolio, etc.) Then by date, if date, or by position, if a specific index was set for it Some posts will have dates (news and events), others will have explicit positions (labs, and portfolio). I want to be able to call posts.sort!, so I've overridden <=>, but am looking for the most effective way of sorting by these conditions. Below is a pseudo method: def <=>(other) # first, everything is sorted into # smaller chunks by category self.category <=> other.category # then, per category, by date or position if self.date and other.date self.date <=> other.date else self.position <=> other.position end end It seems like I'd have to actually sort two separate times, rather than cramming everything into that one method. Something like sort_by_category, then sort!. What is the most ruby way to do this?

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• How can I apply a PSSM efficiently?

  - by flies

  I am fitting for position specific scoring matrices (PSSM aka Position Specific Weight Matrices). The fit I'm using is like simulated annealing, where I the perturb the PSSM, compare the prediction to experiment and accept the change if it improves agreement. This means I apply the PSSM millions of times per fit; performance is critical. In my particular problem, I'm applying a PSSM for an object of length L (~8 bp) at every position of a DNA sequence of length M (~30 bp) (so there are M-L+1 valid positions). I need an efficient algorithm to apply a PSSM. Can anyone help improve performance? My best idea is to convert the DNA into some kind of a matrix so that applying the PSSM is matrix multiplication. There are efficient linear algebra libraries out there (e.g. BLAS), but I'm not sure how best to turn an M-length DNA sequence into a matrix M x 4 matrix and then apply the PSSM at each position. The solution needs to work for higher order/dinucleotide terms in the PSSM - presumably this means representing the sequence-matrix for mono-nucleotides and separately for dinucleotides. My current solution iterates over each position m, then over each letter in word from m to m+L-1, adding the corresponding term in the matrix. I'm storing the matrix as a multi-dimensional STL vector, and profiling has revealed that a lot of the computation time is just accessing the elements of the PSSM (with similar performance bottlenecks accessing the DNA sequence). If someone has an idea besides matrix multiplication, I'm all ears.

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• Cocos2D TouchesEnded not allowing me to access sprites?

  - by maiko

  Hey Guys! Thanks so much for reading! - (void)ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { UITouch * touch = [touches anyObject]; CGPoint location = [[CCDirector sharedDirector] convertToGL: [touch locationInView:touch.view]]; CGRect myRect = CGRectMake(100, 120, 75, 113); int tjx = sprite.position.x; if(CGRectContainsPoint(myRect, location)) { tjx ++; } } For some reason, ccTouchesEnded isn't allowing me to access my "sprite". I also tried to use CGRectMake like so : CGRectMake( sprite.position.x, sprite.position.y, sprite.contentSize.Width, sprite.contentSize.Height) But I couldn't access my sprites position or height. I keep getting "sprite" undeclared when it is declared in the init method, and added to the child. Please help!! I'm sure i'm missing something really simple here.

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• Background image help (Solved)

  - by J2

  thanks for help, ended up with this html{ position:relative; min-width:950px; height:100%; background:black url(images/GrassBG.png) repeat-y top center; font:13px "Lucida Grande",Helvetica,Arial,sans-serif; } body.main{ width:950px; margin:0 auto; position:relative; } is there any way when using a div for a background image- to limit the height to only the content displayed? im putting the background image in a div because i want it centered via position:relative but the image doesnt show up unless i put a height on the div, and thats not what i want because i dont want to be able to just scroll down to the bottom of the image where theres no content ive tried putting the background image on the body css but if the browser is less than the width of the image, it just throws it over to the left and you can only see half of it- is there no way to make the background position:relative on the body? sorry if that doesnt make sense < thanks why can you not use Position:relative; on the body?

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• STOP ERASING MY QUESTIONS! - VIEWING FIRST_ROWS BEFORE QUERY COMPLETES (RE-VISITED)

  - by Frank Developer

  OK, so say I have a table with 500K rows, then I ad-hoc query with unsupported indexing which requires a full table scan. I would like to immediately view the first rows returned while the full table scan continues. Then I want to scroll thru the next results. In the meantime, I would like to display the progress of the table scan, example: "SEARCHING.. FOUND 23 OF 500,000 ROWS SO FAR". If I scroll too far ahead, I want to display a message like: "REACHED LAST ROW IN LOOK-AHEAD BUFFER.. QUERY HAS NOT COMPLETED".. Can this be done? Maybe like: spawn/exec, declare scroll cursor, open, fetch, etc.?

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• http server implentation, the page does not show properly

  - by none

  well, as i am doing a small project of coding an http server. the code is at http://code.google.com/p/reactor/ the current puzzle is when asked to parse a page with java script and css. As an http server it just sends a page (copied from another website) and it parsed inproperly. when a simple html page is been parse , by my firefox, it shows ok, however when parsing a more complex page(css+javascript) the page is all wired like this : ???? ????? if(getCookie('pais999')==null){varisToplayerDouble="True";isToplayerDouble=(isToplayerDouble=="True")?true:falsevarToplayerCookieName='pais999';varTopLayerCookieExpiredDays=1;varToplayerLink='http://xads.zedo.com/ads2/c?a=239671;g=0;c=455000000;i=0;x=7168;n=455;s=0;k=http://www.pais.co.il/Pais/Games/Lotto/';varToplayerImpression='http://l4.zedo.com/log/p.gif?a=239671;c=455000000;x=7168;n=455;e=i;i=0;s=0;z='+Math.random();varToplayerBigPath='pais/January2007/98one_toplayer.swf';varToplayerSmallPath='pais/January2007/98one_reminder.swf';varToplayerBigWidth=1005;varToplayerBigHeight=500;varToplayerSmallWidth=100;varToplayerSmallHeight=100;varToplayerBigLeft=(0==0)?resWidth/2-ToplayerBigWidth/2:resWidth/2-ToplayerBigWidth/2+0varToplayerBigTop=0;varToplayerSmallLeft=resWidth-ToplayerSmallWidth-0;varToplayerSmallTop=0;varSecondsToChangeBigToSmall=15;}elseif(getCookie('NF999')==null){varisToplayerDouble="True";isToplayerDouble=(isToplayerDouble=="True")?true:falsevarToplayerCookieName='NF999';varTopLayerCookieExpiredDays=1;varToplayerLink='http://xads.zedo.com/ads2/c?a=238663;g=0;c=455000000;i=0;x=7168;n=455;s=0;k=http://www.new-pharm.co.il/SkiGame/?ToolID=OLJD8O';varToplayerImpression='http://l4.zedo.com/log/p.gif?a=238663;c=455000000;x=7168;n=455;e=i;i=0;s=0;z='+Math.random();varToplayerBigPath='NewFarm/Ski/995ONE_TopLayer_550x360.swf';varToplayerSmallPath='NewFarm/Ski/995ONE_Reminder_100x100.swf';varToplayerBigWidth=550;varToplayerBigHeight=360;varToplayerSmallWidth=100;varToplayerSmallHeight=100;varToplayerBigLeft=(0==0)?resWidth/2-ToplayerBigWidth/2:resWidth/2-ToplayerBigWidth/2+0varToplayerBigTop=0;varToplayerSmallLeft=resWidth-ToplayerSmallWidth-0;varToplayerSmallTop=0;varSecondsToChangeBigToSmall=15;}elseif(1==0){}$("divToplayerBig").style.width=ToplayerBigWidth;$("divToplayerBig").style.height=ToplayerBigHeight;$("divToplayerBig").style.left=resWidth/2-ToplayerBigWidth/2;$("divToplayerSmall").style.width=ToplayerSmallWidth;$("divToplayerSmall").style.height=ToplayerSmallHeight;$("divToplayerSmall").style.right=ToplayerSmallWidthvartopOff=0;if(ToplayerBigTop0)topOff=resHeight-ToplayerBigHeight+ToplayerBigTop;varisMain=false;#divToplayerBig{position:absolute;right:20px;bottom:1px;}bodydiv#divToplayerBig{position:fixed;}#divToplayerSmall{position:absolute;right:20px;bottom:10px;}bodydiv#divToplayerSmall{position:fixed;}????|??????LIVE|???????????|ONE???????|ONETV |????'??|BigONE|?????????| CrazyONE | where the source code of the html is : ONE:???:??????????????????????????? ????  ????? if(getCookie('pais999')==null){varisToplayerDouble="True";isToplayerDouble=(isToplayerDouble=="True")?true:falsevarToplayerCookieName='pais999';varTopLayerCookieExpiredDays=1;varToplayerLink='http://xads.zedo.com/ads2/c?a=239671;g=0;c=455000000;i=0;x=7168;n=455;s=0;k=http://www.pais.co.il/Pais/Games/Lotto/';varToplayerImpression='http://l4.zedo.com/log/p.gif?a=239671;c=455000000;x=7168;n=455;e=i;i=0;s=0;z='+Math.random();varToplayerBigPath='pais/January2007/98one_toplayer.swf';varToplayerSmallPath='pais/January2007/98one_reminder.swf';varToplayerBigWidth=1005;varToplayerBigHeight=500;varToplayerSmallWidth=100;varToplayerSmallHeight=100;varToplayerBigLeft=(0==0)?resWidth/2-ToplayerBigWidth/2:resWidth/2-ToplayerBigWidth/2+0varToplayerBigTop=0;varToplayerSmallLeft=resWidth-ToplayerSmallWidth-0;varToplayerSmallTop=0;varSecondsToChangeBigToSmall=15;}elseif(getCookie('NF999')==null){varisToplayerDouble="True";isToplayerDouble=(isToplayerDouble=="True")?true:falsevarToplayerCookieName='NF999';varTopLayerCookieExpiredDays=1;varToplayerLink='http://xads.zedo.com/ads2/c?a=238663;g=0;c=455000000;i=0;x=7168;n=455;s=0;k=http://www.new-pharm.co.il/SkiGame/?ToolID=OLJD8O';varToplayerImpression='http://l4.zedo.com/log/p.gif?a=238663;c=455000000;x=7168;n=455;e=i;i=0;s=0;z='+Math.random();varToplayerBigPath='NewFarm/Ski/995ONE_TopLayer_550x360.swf';varToplayerSmallPath='NewFarm/Ski/995ONE_Reminder_100x100.swf';varToplayerBigWidth=550;varToplayerBigHeight=360;varToplayerSmallWidth=100;varToplayerSmallHeight=100;varToplayerBigLeft=(0==0)?resWidth/2-ToplayerBigWidth/2:resWidth/2-ToplayerBigWidth/2+0varToplayerBigTop=0;varToplayerSmallLeft=resWidth-ToplayerSmallWidth-0;varToplayerSmallTop=0;varSecondsToChangeBigToSmall=15;}elseif(1==0){}$("divToplayerBig").style.width=ToplayerBigWidth;$("divToplayerBig").style.height=ToplayerBigHeight;$("divToplayerBig").style.left=resWidth/2-ToplayerBigWidth/2;$("divToplayerSmall").style.width=ToplayerSmallWidth;$("divToplayerSmall").style.height=ToplayerSmallHeight;$("divToplayerSmall").style.right=ToplayerSmallWidthvartopOff=0;if(ToplayerBigTop0)topOff=resHeight-ToplayerBigHeight+ToplayerBigTop;varisMain=false;#divToplayerBig{position:absolute;right:20px;bottom:1px;}bodydiv#divToplayerBig{position:fixed;}div#divToplayerBig{right:auto;bottom:auto;left:expression((-20-divToplayerBig.offsetWidth+(document.documentElement.clientWidth?document.documentElement.clientWidth:document.body.clientWidth)+(ignoreMe2=document.documentElement.scrollLeft?document.documentElement.scrollLeft:document.body.scrollLeft))+'px');top:expression((0-divToplayerBig.offsetHeight-topOff+(document.documentElement.clientHeight?document.documentElement.clientHeight:document.body.clientHeight)+(ignoreMe=document.documentElement.scrollTop?document.documentElement.scrollTop:document.body.scrollTop))+'px');}#divToplayerSmall{position:absolute;right:20px;bottom:10px;}bodydiv#divToplayerSmall{position:fixed;}div#divToplayerSmall{right:auto;bottom:auto;left:expression((-20-divToplayerSmall.offsetWidth+(document.documentElement.clientWidth?document.documentElement.clientWidth:document.body.clientWidth)+(ignoreMe2=document.documentElement.scrollLeft?document.documentElement.scrollLeft:document.body.scrollLeft))+'px');top:expression((0-divToplayerSmall.offsetHeight+(document.documentElement.clientHeight?document.documentElement.clientHeight:document.body.clientHeight)+(ignoreMe=document.documentElement.scrollTop?document.documentElement.scrollTop:document.body.scrollTop))+'px');}varisTopTrans=(ToplayerBigPath.indexOf("transparent")-1)?false:true;varisRemTrans=(ToplayerSmallPath.indexOf("transparent")-1)?false:true;vartop1session=3;vartop2session=5;InitToplayer(isTopTrans,isRemTrans);window.onload=StartToplayer;????|??????LIVE|???????????|ONE???????|ONETV |????'??|BigONE|?????????|  CrazyONE |????????????????????????????????????????????????????????19/01/07  19:30?????????????????????-?????:?????????????????????????19/01/07  18:43??????????????:??????????????????????19/01/07  17:41???:??????????????????????????????????19/01/07  16:49?????:??????"?????????????/?????1:2,??????"??????19/01/07  16:45????????????????????????????,?????2.5???????????????19/01/07  16:37???????:???"?????????????????-19:30?????????????19/01/07  14:32?????"?????????-18:30?????????"????????,????'??????19/01/07  14:45????????????????????????????????"?:??????????????19/01/07  14:37??????????:??????????????????????????????0:019/01/07  13:46varswfPeleSmall=newSWFObject("http://images.one.co.il/images/PeleEmulator/emulator_pelephone_01a.swf","peleSmall",160,470,"6","#FFFFFF");swfPeleSmall.addParam("quality","high");swfPeleSmall.addParam("wmode","transparent");swfPeleSmall.write("divPeleSmall");varswfPeleBig=newSWFObject("http://images.one.co.il/images/PeleEmulator/emulator_pelephone_02d.swf","peleBig",400,470,"6","#FFFFFF");swfPeleBig.addParam("quality","high");swfPeleBig.addParam("wmode","transparent");swfPeleBig.write("divWithBig");???:???????????????????????????????????????-ONE????????????????????????????????????????????.????????,???????????1:2,?????????????:"???????????"DisplayFlash("W_S_round_border_pic.swf","156","201","1","style=position:absolute");?????????????????????????(??????)?????????                          19/01/20077:26???????????????(????)????????????????????????????6:3,5:7?-5:7???????????????????????,???????23?????.?????,????????????????????????????????,???????????????????????????????????????????,????????????????????.??????????????????????????,??????????????????????????.????????????????????????????-1:1?????????.?????????????????????????????'?????????????????????????????.?????????????.???????????????????????????????(16???????),???????????????????????????????????????3???????,???????????????????????.????????- (only part of of the page presentation in firefox and page source html) why is it happening? what is midding in the http response? StringBuffer tResponse = new StringBuffer(); tResponse.append("HTTP/1.1 200 OK\n"); tResponse.append("Date: "+new Date().toString() +'\n'); tResponse.append("server: http-reactor/0.1-dev\n"); tResponse.append("last-Modified:"+ d.toString() +'\n'); tResponse.append("Content-Type: text/html; charset=windows-1255\n"); tResponse.append("Accept-Language: he; q=1.0, en; q=0.5:); tResponse.append("Content-Length: "+tFileContent.length()+'\n'); tResponse.append('\n'); tResponse.append(tFileContent); public StringBuffer FetchData(String FileName) throws FileNotFoundException{ StringBuffer tFileContent = new StringBuffer(); if (FileName.contains("../")) throw new SecurityException(); if (FileName.equals("/")) FileName = "\\index.html"; FileName.replace('/', '\\'); File f = new File(_root + FileName); Scanner scanner = new Scanner(f); while(scanner.hasNext()) tFileContent.append(scanner.next()); return generateResponse(tFileContent,f.lastModified()); } private StringBuffer generateResponse(StringBuffer tFileContent, long l) { StringBuffer tResponse = new StringBuffer(); Date d = new Date(l); tResponse.append("HTTP/1.1 200 OK\n"); tResponse.append("Date: "+new Date().toString() +'\n'); tResponse.append("server: http-reactor/0.1-dev\n"); tResponse.append("last-Modified:"+ d.toString() +'\n'); tResponse.append("Content-Type: text/html; charset=windows-1255\n"); tResponse.append("Accept-Language: he; q=1.0, en; q=0.5:); tResponse.append("Content-Length: "+tFileContent.length()+'\n'); tResponse.append('\n'); tResponse.append(tFileContent); return tResponse; }

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• Intelligent serial port mocks with Moq

  - by Padu Merloti

  I have to write a lot of code that deals with serial ports. Usually there will be a device connected at the other end of the wire and I usually create my own mocks to simulate their behavior. I'm starting to look at Moq to help with my unit tests. It's pretty simple to use it when you need just a stub, but I want to know if it is possible and if yes how do I create a mock for a hardware device that responds differently according to what I want to test. A simple example: One of the devices I interface with receives a command (move to position x), gives back an ACK message and goes to a "moving" state until it reaches the ordered position. I want to create a test where I send the move command and then keep querying state until it reaches the final position. I want to create two versions of the mock for two different tests, one where I expect the device to reach the final position successfully and the other where it will fail. Too much to ask?

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• add an image in listview

  - by danish

  Hi I would like to add more images in my list view as this code below only displays image 1 and 2 continuously in each row. What I want to do is display a different image for each different row. Here is mycode below; Thanks for any help. I am not good at java please change the code where necessary and I can then refer to it. public class starters extends ListActivity { private static class EfficientAdapter extends BaseAdapter { private LayoutInflater mInflater; private Bitmap mIcon1; private Bitmap mIcon2; private Bitmap mIcon3; private Bitmap mIcon4; private Bitmap mIcon5; private Bitmap mIcon6; private Bitmap mIcon7; private Bitmap mIcon8; private Bitmap mIcon9; private Bitmap mIcon10; public EfficientAdapter(Context context) { // Cache the LayoutInflate to avoid asking for a new one each time. mInflater = LayoutInflater.from(context); // Icons bound to the rows. mIcon1 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters1); mIcon2 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters2); mIcon3 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters3); mIcon4 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters4); mIcon5 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters5); mIcon6 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters6); mIcon7 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters7); mIcon8 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters8); mIcon9 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters9); mIcon10 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters10); } public int getCount() { return DATA.length; } public Object getItem(int position) { return position; } public long getItemId(int position) { return position; } public View getView(int position, View convertView, ViewGroup parent) { // A ViewHolder keeps references to children views to avoid unneccessary calls // to findViewById() on each row. ViewHolder holder; // When convertView is not null, we can reuse it directly, there is no need // to reinflate it. We only inflate a new View when the convertView supplied // by ListView is null. if (convertView == null) { convertView = mInflater.inflate(R.layout.starters, null); // Creates a ViewHolder and store references to the two children views // we want to bind data to. holder = new ViewHolder(); holder.text = (TextView) convertView.findViewById(R.id.text01); holder.text = (TextView) convertView.findViewById(R.id.secondLine); holder.icon = (ImageView) convertView.findViewById(R.id.icon01); convertView.setTag(holder); } else { // Get the ViewHolder back to get fast access to the TextView // and the ImageView. holder = (ViewHolder) convertView.getTag(); } // Bind the data efficiently with the holder. holder.text.setText(DATA[position]); holder.icon.setImageBitmap((position & 1) ==1 ? mIcon1 : mIcon2); return convertView; } static class ViewHolder { TextView text; ImageView icon; } } @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setListAdapter(new EfficientAdapter(this)); } private static final String[] DATA = { "Original nachos", "Toasted chicken and cheese quesadillas", "Chicken, lime and coriander nachos", "Spicy bean and cheese quesadillas", "Tuna and corn quesadillas", "Cheesy bean and sweetcorn nachos", "Crispy chicken, avocado and lime salad", "Beef and baby corn tostada", "Spicy mexican rice with chicken and prawns", "Chilli potato boats"}; }

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• ListView in ArrayAdapter order get's mixed up when scrolling

  - by Dan B

  Hi, I have a ListView in a custom ArrayAdapter that displays an icon ImageView and a TextView in each row. When I make the list long enough to let you scroll through it, the order starts out right, but when I start to scroll down, some of the earlier entries start re-appearing. If I scroll back up, the old order changes. Doing this repeatedly eventually causes the entire list order to be seemingly random. So scrolling the list is either causing the child order to change, or the drawing is not refreshing correctly. What could cause something like this to happen? I need the order the items are displayed to the user to be the same order they are added to the ArrayList, or at LEAST to remain in one static order. If I need to provide more detailed information, please let me know. Any help is appreciated. Thanks.

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• WPF window scrolling with top menu

  - by Greg R

  I'm running into a dilemma. When I make the ScrollViewer the main content object of my window, scrolling behaves exactly like I want it to. You resize to make it smaller than the content and the window and scroll bars appear. The problem comes in when I want the to menu to be static and the rest of content to be scrollable. I want the scroll bars to behave the same way as a browser window does, meaning when you resize it, the scroll bars appear based on the size of the content. When you expand the window, the content takes up the entire real estate of the window. Is that possible in WPF? Help would be GREATLY appreciated.

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• Accelerometer Values from Android/iPhone device

  - by mrlinx

  I'm trying to map my movements with a android device into an OpenGL scene. I've recorded accelerometer values for a simples movement: Moving the phone (lies flat on a table) 10cm forward (+x), and then 10cm backward (-x). The problem is that this values when used to calculate velocity and position, makes only the opengl cube go forward. Seems like the negative acceleration recorded was not enough to reduce the speed and invert its movement. What can be the problem? This is my function that updates the velocity and position every time new data comes in: void updatePosition(double T2) { double T = 0.005; Vec3 old_pos = position.clone(), old_vel = velocity.clone(); velocity = old_vel.plus(acceleration.times(T)); position = old_pos.plus(old_vel.times(T).plus(acceleration.times(0.5 * Math.pow(T, 2)))); } This is the X,Y,Z accelerometer values over the entire captured time:

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