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  • ZeroTurnaround sort la version 3.1 de son outil de productivité Java JRebel et améliore son support

    Outre des corrections d'anomalies, JRebel supporte désormais les changements dans le mapping Object Relationnel pour les implémentations de JPA que sont Hibernate et OpenJPA. Toplink/EclipseLink est également pris en charge mais c'est encore expérimental (à activer si vous souhaitez tester). Au rayon de l'accès aux données, il y a également désormais une prise en charge des modifications de sql maps pour iBatis.

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  • Merge sort. ArrayIndexOutOfBoundsException [migrated]

    - by user94892
    When I execute the program I am getting an error as stated below the program. Please help me figure out the problem.. import java.util.*; class Mergesort { public static void main(String args[]) { Scanner in= new Scanner(System.in); System.out.println("Enter the number of elements"); int n= in.nextInt(); int a[]= new int[n]; System.out.println("Enter the contents"); for(int i=0; i<n; i++) { a[i]=in.nextInt(); } a = mergesort(a,n); for(int i=0; i<n; i++) { System.out.println(a[i]); } } public static int[] mergesort(int[] x, int z) { if(z==1) { return x; } int b[]=new int[z/2]; int c[]=new int[z-z/2]; int i,j,k; for(int p=0;p<z/2; p++) { b[p]= x[p]; c[p]= x[p+z/2]; } c[z-z/2-1]= x[z-1]; b= mergesort(b,z/2); c= mergesort(c,z-z/2); for(i=0,j=0,k=0; k<z; k++) { if(b[i]<=c[j]) { x[k]=b[i]; i++; } else if( b[i]>c[j]) { x[k]=c[j]; j++; } else if(i== z/2) { x[k]= c[j]; j++; } else if(j == z-z/2) { x[k]= b[i]; i++; } } return x; } } Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1 at Mergesort.mergesort(Mergesort.java:41) at Mergesort.mergesort(Mergesort.java:36) at Mergesort.main(Mergesort.java:16)

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  • What sort of leaderboard for my game?

    - by Martin
    I recently published a word game for Windows Phone and I am really happy to have some players. The game is entirely offline and at the end of a game, the player's score is published to a server. I'm collecting the scores to build a leaderboard. Right now, I don't believe that the leaderboard I offer to my users is appropriate. I essentially accumulate the score of all the games of a user for a given day and that becomes their score. So if Player 1 plays 3 games and gets 100, 150 and 200 points, its score for the day is 450 points. I would like to get your ideas and opinion. How do I keep my game challenging and engaging with a good leaderboard? Should I continue accumulating the score for a day? Should I just keep the best score? Thanks!

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  • Force Your Mac to Sort Folders on Top of Files (Windows Style)

    - by Eric Z Goodnight
    Even die-hard Mac converts have their issues with Mac OS, and one of those problems is that OS X lists folders mixed in with all other files. Here’s how to fix that in under five minutes with a clever hack. You know you’ve had that issue. You’ve dug through your files looking for that one elusive folder, and because it’s jumbled in with all the other stuff, it’s more or less impossible to find. Have no fear, with no downloads or silly plug-in software, you can finally make Mac OS behave like Windows and Linux and list those folders in the proper order.  How To Encrypt Your Cloud-Based Drive with BoxcryptorHTG Explains: Photography with Film-Based CamerasHow to Clean Your Dirty Smartphone (Without Breaking Something)

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  • Adobe sort Project Parfait, un outil en ligne pour extraire le CSS de votre PSD

    Adobe Project Parfait : extraire le CSS de votre PSDAdobe signe un bel outil qui promet de rendre de bons services aux webmaster en permettant d'extraire le code CSS d'un fichier PSD dans le navigateur. Dans le navigateur? C'est à dire que la version actuelle (beta) est gratuite et ne nécessite pas de posséder Photoshop pour l'utiliser.On peut imaginer que le webmaster a reçu la maquette d'une page en PSD qu'il lui suffit d'uploader sur Project Parfait pour en extraire le CSS.L'interface intuitive...

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  • Windows 7 Enterprise : Microsoft sort une version d'évaluation gratuite de l'édition "réservée aux professionnels de l'informatique"

    Microsoft propose une version d'évaluation gratuite de Windows 7 Enterprise Que pensez-vous de cette édition spécialement dédiée aux professionnels de l'informatique Le 8 avril 2014, Windows XP sera de l'histoire ancienne pour Microsoft. Plus aucune mise à jour et plus aucun support ne seront proposés pour le système d'exploitation n°1 dans le monde. Vista a suivi mais a déboussolé tant d'utilisateurs que pour beaucoup de professionnels IT, le vrai successeur de Windows XP est en fait Windows 7. Et plus exactement Windows 7 Enterprise. Au moment où Microsoft vient de lancer une offre spéciale de 90 jours d'essai gratuit pour cette édition spéciale (justement en rapport avec...

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  • How to sort time column by value instead of alphabetically

    - by Turch
    I'm creating a pivot table by connecting to an SSAS tabular model (Data - From Other Sources - From Analysis Services) . The model has a "time" column that I want to sort by. The default (database) sorting is earliest to latest: When I click the triangle next to 'Row Labels' and select "Sort A to Z", I get alphabetically sorted times: How can I get the times to sort by time? Changing the number format from "General" to "Time" does nothing. The times aren't stored as text either - the data type of the column in the SSAS model is Auto (Date)

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  • Sort rectangles in a grid based on a comparison of the center point of each

    - by Mrwolfy
    If I have a grid of rectangles and I move one of the rectangles, say above and to the left of another rectangle, how would I resort the rectangles? Note the rectangles are in an array, so each rectangle has an index and a matching tag. All I really need to do is set the proper index based on the rectangles new center point position within the rectangle, as compared with the center point position of the other rectangles in the grid. Here is what I am doing now in pseudo code (works somewhat, but not accurate): -(void)sortViews:myView { int newIndex; // myView is the view that was moved. [viewsArray removeObject:myView]; [viewsArray enumerate:obj*view]{ if (myView.center.x > view.center.x) { if (myView.center.y > view.center.y) { newIndex = view.tag -1; *stop = YES; } else { newIndex = view.tag +1; *stop = YES; } } else if (myView.center.x < view.center.x) { if (myView.center.y > view.center.y) { newIndex = view.tag -1; *stop = YES; } else { newIndex = view.tag +1; *stop = YES; } } }]; if (newIndex < 0) { newIndex = 0; } else if (newIndex > 5) { newIndex = 5; } [viewsArray insertObject:myView atIndex:newIndex]; [self arrangeGrid]; }

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  • Lucene neo4j sort with boolean fields

    - by Daniele
    I have indexed some documents (nodes of neo4j) with a boolean property which not always is present. Eg. Node1 label : "label A" Node2: label : "label A" (note, same label of node1) special : true The goal is to get Node2 higher than node 1 for query "label A". Here the code: Index<Node> fulltextLucene = graphDb.index().forNodes( "my-index" ); Sort sort = new Sort(new SortField[] {SortField.FIELD_SCORE, new SortField("special", SortField.????, true) }); IndexHits<Node> results = fulltextLucene.query( "label", new QueryContext( "label A").sort(sort)); How can I accomplish that? Thanks

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  • Maintaining sort order of database table rows

    - by Lox
    Say I have at database table containing information about a news article in each row. The table has an integer "sort" column to dictate the order in which the articles are to be presented on a web site. How do I best implement and maintain this sort order. The problem I want to avoid is having the the articles numbered 1,2,3,4,..,100 and when article number 50 suddenly becomes interesting it gets its sort number set to 1 and then all articles between them must have their sort number increased by one. Sure, setting initial sort numbers to 100,200,300,400 etc. leaves some space for moving around but at some point it will break. Is there a correct way to do this, maybe a completely different approach? Added-1: All article titles are shown in a list linking to the contents, so yes all sorted items are show at once. Added-2: An item is not necessarily moved to the top of the list; any item can be placed anywhere in the ordered list.

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  • Prolog: using the sort/2 predicate

    - by Øyvind Hauge
    So I'm trying to get rid of the wrapper clause by using the sort library predicate directly inside split. What split does is just generating a list of numbers from a list that looks like this: [1:2,3:2,4:6] ---split-- [1,2,3,2,4,6]. But the generated list contains duplicates, and I don't want that, so I'm using the wrapper to combine split and sort, which then generates the desired result: [1,2,3,4,6]. I'd really like to get rid of the wrapper and just use sort within split, however I keep getting "ERROR: sort/2: Arguments are not sufficiently instantiated." Any ideas? Thanks :) split([],[]). split([H1:H2|T],[H1,H2|NT]) :- split(T,NT). wrapper(L,Processed) :- split(L,L2), sort(L2,Processed).

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  • Virtual methods as Comp function to sort

    - by wilsongoncalo.mp
    Hello everyone! I'm new to C++ and i'm trying to use std::sort function to sort a vector of Solutions. The code is something like this (solution list is a *vector): void SolutionSet::sort(Comparator &comparator) { std::sort(solutionsList_->begin(), solutionsList_->end(), &comparator::compare); } The comparator param is a Comparator´s child class instance , and the compare method is virtual at Comparator class and implemented by all Comparator's child classes. And i want to use that function as a comparator function at std:sort(). Is this possible? If it is, can someone tell me how? Because with the previous code, it doesn't work. If i've not made myself clear, please just ask! Thank you guys!

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  • Shell Sort problem

    - by user191603
    Show the result of running Shell Sort on the input 9,8,7,6,5,4,3,2,1 using increments { 1,3,7 }. I have done this part. the result is: 9 8 7 6 5 4 3 2 1 (original) 2 1 7 6 5 4 3 9 8 ( 7-sort ) 2 1 4 3 5 7 6 9 8 ( 3-sort ) 1 2 3 4 5 6 7 8 9 ( 1-sort ) Then the question requires me to determine the running time of Shell Sort using Shell's increments of N/2, N/4, ..., 1 for sorted input. I am not quite sure how to answer the second question as I don't understand the requirement of this question. So, would anyone give some hints to let me finish this question? Thank you for your help first!

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  • sort list(of string()) using a variable index into string() as key - vb.net

    - by tullynyguy
    I have a List(of String()). I have written a custom comparer (implements IComparer(of string)) to do an alphanumeric sort. Is there a way to sort the List using a given index to determine which position in the String() to sort by? In other words one time I might sort by Index = 0 and another time by Index = 3. The length of all String() in the list is the same. For reference this question is similar to Sort List<String[]> except I am using VB.net and that question is hardwired to Index=0.

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  • efficient sort with custom comparison, but no callback function

    - by rob
    I have a need for an efficient sort that doesn't have a callback, but is as customizable as using qsort(). What I want is for it to work like an iterator, where it continuously calls into the sort API in a loop until it is done, doing the comparison in the loop rather than off in a callback function. This way the custom comparison is local to the calling function (and therefore has access to local variables, is potentially more efficient, etc). I have implemented this for an inefficient selection sort, but need it to be efficient, so prefer a quick sort derivative. Has anyone done anything like this? I tried to do it for quick sort, but trying to turn the algorithm inside out hurt my brain too much. Below is how it might look in use. // the array of data we are sorting MyData array[5000], *firstP, *secondP; // (assume data is filled in) Sorter sorter; // initialize sorter int result = sortInit (&sorter, array, 5000, (void **)&firstP, (void **)&secondP, sizeof(MyData)); // loop until complete while (sortIteration (&sorter, result) == 0) { // here's where we do the custom comparison...here we // just sort by member "value" but we could do anything result = firstP->value - secondP->value; }

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  • Any 3rd party tools that integrate IIS management with some sort of application inventory/change man

    - by NoCarrier
    I've got an environment with several IIS 6 web servers hosting hundreds of apps (dozens of sites, hundreds of virtual directories) all with a myriad of different configurations belonging to dozens of different developers (all deploying apps willy nilly). Is there some sort of managed software solution that will centralize management of all my IIS6 environments provide some inventory functionality allow for reporting or querying of said application inventory enforce and automate some sort of deployment process?

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  • joining text files with 600M+ lines

    - by dnkb
    I have two files huge.txt and small.txt. Huge has around 600M rows and it's 14Gigs, each line has four space separated words (tokens) and finally another space separated column with a number. Small has 150K rows with a size of ~3M, a space separated word and a number. Both Files are sorted using the sort command, with no extra options. The words in both files may include apostrophes (') and dashes (-). The deisred output would contain all columns from the huge.txt and the second column (the number) from small txt where the first word of huge.txt and the first word of small.txt match. My attemtpts below failed miserably with the following error: cat huge.txt|join -o 1.1 1.2 1.3 1.4 2.2 - small.txt > output.txt join: memory exhausted What I suspect is that the sorting order isn't right somehow even though the files are pre-sorted using: sort -k1 huge.unsorted.txt > huge.txt sort -k1 small.unsorted.txt > small.txt Problems seem to appear around words that have apostrophes (') or dashes (-). I also tried dictinoary sorting using the -d option bumping into the same error at the end. I see two ways out of this but don't know how to implement any of them. 1) Any tips how to sort the files in a way that the join command considers them to be sorted properly? 2) I was thinking of calculating MD5 or some other hashes of the strings to get rid of the apostrophes and dashes, and do the sorting and joining with the hashes instead of the strings themselves an dat the "translate" back the hashes to strings, but leave the numbers intact at the end of the lines. Since there would be only 150K hashes it's not that bad. What would be a good way to calculate individual hashes for each of the strings? Some AWK magic? See file samples at the end. Thank you! sample of huge.txt had stirred me to 46 had stirred my corruption 57 had stirred old emotions 55 had stirred something in 69 had stirred something within 40 sample of small.txt caley 114881 calf 2757974 calfed 137861 calfee 71143 calflora 154624 calfskin 148347 calgary 9416465 calgon's 94846

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  • Sort music files by disc number in Vista

    - by furikuretsu
    I'm sitting under Vista and the problem is -- though I can see disc number of track in Winamp or some other multimedia players, I cannot sort files by disc number in Windows Explorer. I've scanned through the whole long list of available properties of files but haven't found "disc number" or similar property. So is there any way to sort tracks by disc number in Windows Explorer, and if there is, then how to do it?

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  • Sort each standalone line alphabetically

    - by Daniel
    I want to sort some items in alphabetic order, but in a very specifc way. I have, for example, the following list, each item separated by comma: monkeys, dogs, cats pineapple, banana, orange yellow, red, blue, green silver, gold, platinum delphi, java, c++, visual basic I want to sort each line alphabetically, WITHOUT changing line order. My desired result would be: cats, dogs, monkeys banana, orange, pineapple blue, green, red, yellow gold, platinum, silver c++, delphi, java, visual basic My target list has got 3000+ lines, so it should be an automated process. Thanks!

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  • File size limit exceeded in bash

    - by yboren
    I have tried this shell script on a SUSE 10 server, kernel 2.6.16.60, ext3 filesystem the script has problem like this: cat file | awk '{print $1" "$2" "$3}' | sort -n > result the file's size is about 3.2G, and I get such error message: File size limit exceeded in this shell, ulimit -f is unlimited after I change script into this cat file | awk '{print $1" "$2" "$3}' >tmp sort -n tmp > result the problem is gone. I don't know why, can anyone help me with an explanation?

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