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  • How to Get on Google's Top 10 List

    A question I often asked by new clients is why some websites rank higher on Google than others? This question can be difficult to answer because of the number of variables involved and the fact that Google's search algorithms are closely guarded secret. However, there are a number of standards which affect every website regardless of its topic, purpose, or age.

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  • SQL View: Beyond the Basics

    Joe Celko delves into the main uses of views, explains how the WITH CHECK OPTION works, and demonstrates how the INSTEAD OF trigger can be used in those cases where views cannot be updatable. What are your servers really trying to tell you? Find out with new SQL Monitor 3.0, an easy-to-use tool built for no-nonsense database professionals.For effortless insights into SQL Server, download a free trial today.

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  • Samba login before requesting list of shares?

    - by user69359
    I'm relatively inexperienced at this and am starting to get a little frustrated: I have a Ubuntu Server with several user accounts. The Samba file server hosts a number of public shares + the home directories of each user as a private share. When connecting to the server using my OSX machine, I am prompted to enter my login data, and get a overview of all the public shares + my accounts home directory share. Exactly the way I want it. How ever, when I connect to the server from a Ubuntu machine, I am never prompted to enter any login data, and can only see the public folders. If a user wants to connect to their home directory on the server, they have to go through "connect to server" and mount their specific private share. Is there anyway to configure Samba or the Ubuntu client in a way that will make the user experience more similar to how it is on my OSX box? Thank you for your time!

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  • Inserting Records in Ascending Order function- C homework assignment

    - by Aaron McRuer
    Good day, Stack Overflow. I have a homework assignment that I'm working on this weekend that I'm having a bit of a problem with. We have a struct "Record" (which contains information about cars for a dealership) that gets placed in a particular spot in a linked list according to 1) its make and 2) according to its model year. This is done when initially building the list, when a "int insertRecordInAscendingOrder" function is called in Main. In "insertRecordInAscendingOrder", a third function, "createRecord" is called, where the linked list is created. The function then goes to the function "compareCars" to determine what elements get put where. Depending on the value returned by this function, insertRecordInAscendingOrder then places the record where it belongs. The list is then printed out. There's more to the assignment, but I'll cross that bridge when I come to it. Ideally, and for the assignment to be considered correct, the linked list must be ordered as: Chevrolet 2012 25 Chevrolet 2013 10 Ford 2010 5 Ford 2011 3 Ford 2012 15 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2013 20 from the a text file that has the data ordered the following way: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Notice that the alphabetical order of the "make" field takes precedence, then, the model year is arranged from oldest to newest. However, the program produces this as the final list: Chevrolet 2012 25 Chevrolet 2013 10 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2012 20 Ford 2010 5 Ford 2011 3 Ford 2012 15 I sat down with a grad student and tried to work out all of this yesterday, but we just couldn't figure out why it was kicking the Ford nodes down to the end of the list. Here's the code. As you'll notice, I included a printList call at each instance of the insertion of a node. This way, you can see just what is happening when the nodes are being put in "order". It is in ANSI C99. All function calls must be made as they are specified, so unfortunately, there's no real way of getting around this problem by creating a more efficient algorithm. #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_LINE 50 #define MAX_MAKE 20 typedef struct record { char *make; int year; int stock; struct record *next; } Record; int compareCars(Record *car1, Record *car2); void printList(Record *head); Record* createRecord(char *make, int year, int stock); int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock); int main(int argc, char **argv) { FILE *inFile = NULL; char line[MAX_LINE + 1]; char *make, *yearStr, *stockStr; int year, stock, len; Record* headRecord = NULL; /*Input and file diagnostics*/ if (argc!=2) { printf ("Filename not provided.\n"); return 1; } if((inFile=fopen(argv[1], "r"))==NULL) { printf("Can't open the file\n"); return 2; } /*obtain values for linked list*/ while (fgets(line, MAX_LINE, inFile)) { make = strtok(line, " "); yearStr = strtok(NULL, " "); stockStr = strtok(NULL, " "); year = atoi(yearStr); stock = atoi(stockStr); insertRecordInAscendingOrder(&headRecord,make, year, stock); } printf("The original list in ascending order: \n"); printList(headRecord); } /*use strcmp to compare two makes*/ int compareCars(Record *car1, Record *car2) { int compStrResult; compStrResult = strcmp(car1->make, car2->make); int compYearResult = 0; if(car1->year > car2->year) { compYearResult = 1; } else if(car1->year == car2->year) { compYearResult = 0; } else { compYearResult = -1; } if(compStrResult == 0 ) { if(compYearResult == 1) { return 1; } else if(compYearResult == -1) { return -1; } else { return compStrResult; } } else if(compStrResult == 1) { return 1; } else { return -1; } } int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock) { Record *previous = *head; Record *newRecord = createRecord(make, year, stock); Record *current = *head; int compResult; if(*head == NULL) { *head = newRecord; printf("Head is null, list was empty\n"); printList(*head); return 1; } else if ( compareCars(newRecord, *head)==-1) { *head = newRecord; (*head)->next = current; printf("New record was less than the head, replacing\n"); printList(*head); return 1; } else { printf("standard case, searching and inserting\n"); previous = *head; while ( current != NULL &&(compareCars(newRecord, current)==1)) { printList(*head); previous = current; current = current->next; } printList(*head); previous->next = newRecord; previous->next->next = current; } return 1; } /*creates records from info passed in from main via insertRecordInAscendingOrder.*/ Record* createRecord(char *make, int year, int stock) { printf("CreateRecord\n"); Record *theRecord; int len; if(!make) { return NULL; } theRecord = malloc(sizeof(Record)); if(!theRecord) { printf("Unable to allocate memory for the structure.\n"); return NULL; } theRecord->year = year; theRecord->stock = stock; len = strlen(make); theRecord->make = malloc(len + 1); strncpy(theRecord->make, make, len); theRecord->make[len] = '\0'; theRecord->next=NULL; return theRecord; } /*prints list. lists print.*/ void printList(Record *head) { int i; int j = 50; Record *aRecord; aRecord = head; for(i = 0; i < j; i++) { printf("-"); } printf("\n"); printf("%20s%20s%10s\n", "Make", "Year", "Stock"); for(i = 0; i < j; i++) { printf("-"); } printf("\n"); while(aRecord != NULL) { printf("%20s%20d%10d\n", aRecord->make, aRecord->year, aRecord->stock); aRecord = aRecord->next; } printf("\n"); } The text file you'll need for a command line argument can be saved under any name you like; here are the contents you'll need: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Thanks in advance for your help. I shall continue to plow away at it myself.

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  • iptables : how to allow incoming ftp traffic?

    - by logansama
    Hi, Still fighting my way through the jungle that is called iptables. I have managed to allow FTP access outside of our LAN: both these would work. NOTE: eth0 is the LAN interface and eth1 is the WAN interface. iptables -t filter -A FORWARD -i eth0 -p tcp --dport 20:21 -j ACCEPT or iptables -A FORWARD -i eth0 -o eth1 -p tcp --sport 20:21 --dport 1024:65535 -j ACCEPT But when i connect to a external FTP server i manage to log in and all is fine until it wishes to List the directory content. Then nothing happens as the data is blocked, due to the fact that i do not have a rule set up to allow it! (my last rule on the FORWARD chain is to block all traffic) I have tried a gazillion rules (many of which i did not understand) to try and allow the FTP traffic back through my server. One such rule for example was: iptables -A FORWARD -i eth1 -o eth0 -p tcp --sport 20:21 --dport 1024:65535 -j ACCEPT But i cannot get the List to work. It just times out after a while. Would anyone perhaps know how to build a rule which would allow FTP to List / allow such traffic back? Or have a link to sources i could work through? Thank you,

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  • MVC validation error with strongly typed view

    - by Remnant
    I have a simple form that I would like to validate on form submission. Note I have stripped out the html for ease of viewing <%=Html.TextBox("LastName", "")%> //Lastname entry <%=Html.ValidationMessage("LastName")%> <%=Html.TextBox("FirstName", "")%>//Firstname entry <%=Html.ValidationMessage("FirstName")%> <%=Html.DropDownList("JobRole", Model.JobRoleList)%> //Dropdownlist of job roles <% foreach (var record in Model.Courses) // Checkboxes of different courses for user to select { %> <li><label><input type="checkbox" name="Courses" value="<%=record.CourseName%>" /><%= record.CourseName%></label></li> <% } %> On submission of this form I would like to check that both FirstName and LastName are populated (i.e. non-zero length). In my controller I have: public ActionResult Submit(string FirstName, string LastName) { if (FirstName.Trim().Length == 0) ModelState.AddModelError("FirstName", "You must enter a first name"); if (LastName.Trim().Length == 0) ModelState.AddModelError("LastName", "You must enter a first name"); if (ModelState.IsValid) { //Update database + redirect to action } return View(); //If ModelState not valid, return to View and show error messages } Unfortunately, this code logic produces an error that states that no objects are found for JobRole and Courses. If I remove the dropdownlist and checkboxes then all works fine. The issue appears to be that when I return the View the view is expecting objects for the dropwdownlist and checkboxes (which is sensible as that is what is in my View code) How can I overcome this problem? Things I have considered: In my controller I could create a JobRoleList object and Course object to pass to the View so that it has the objects to render. The issue with this is that it will overwrite any dropdownlist / checkbox selections that the user has already made. In the parameters of my controller method Submit I could aslo capture the JobRoleList object and Course object to pass back to the View. Again, not sure this would capture any items the user has already selected. I have done much googling and reading but I cannot find a good answer. When I look at examples in books or online (e.g. Nerddinner) all the validation examples involve simple forms with TextBox inputs and don't seems to show instances with multiple checkboxes and dropdownlists. Have I missed something obvious here? What would be best practice in this situation? Thanks

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  • MVC Partial View Not Refreshing when using JSON data

    - by 40-Love
    I have a dropdown that I'm using to refresh a div with checkboxes. I am trying to figure out why my view is not refreshing if I pass in data in JSON format. If I pass in just a regular string, the view refreshes. If I pass in JSON data, the view does not refresh. If I step through the code in the Partial view, I can see the correct number of records are being passed in, however the view doesn't get refreshed with the correct number of checkboxes. I tried to add some cache directives, it didn't work. This doesn't work: $(function () { $('#ddlMoveToListNames').change(function () { var item = $(this).val(); var selectedListID = $('#ddlListNames').val(); var checkValues = $('input[name=c]:checked').map(function () { return $(this).val(); }).toArray(); $.ajax({ url: '@Url.Action("Test1", "WordList")', type: 'POST', cache: false, data: JSON.stringify({ words: checkValues, moveToListID: item, selectedListID: selectedListID }), dataType: 'json', contentType: 'application/json; charset=utf-8', success: function (result) { } }) .done(function (partialViewResult) { $("#divCheckBoxes").replaceWith(partialViewResult); }); }); }); This works: $(function () { $('#ddlMoveToListNames').change(function () { var item = $(this).val(); var selectedListID = $('#ddlListNames').val(); var checkValues = $('input[name=c]:checked').map(function () { return $(this).val(); }).toArray(); $.ajax({ url: '@Url.Action("Test1", "WordList")', type: 'POST', cache: false, data: { selectedListID: item }, success: function (result) { } }) .done(function (partialViewResult) { $("#divCheckBoxes").replaceWith(partialViewResult); }); }); }); Partial View: @model WLWeb.Models.MyModel <div id="divCheckBoxes"> @foreach (var item in Model.vwWordList) { @Html.Raw("<label><input type='checkbox' value='" + @Html.DisplayFor(modelItem => item.Word) + "' name='c'> " + @Html.DisplayFor(modelItem => item.Word) + "</label>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;"); } </div> Controller: [AcceptVerbs(HttpVerbs.Post)] [OutputCache(NoStore = true, Duration = 0, VaryByParam = "*")] public PartialViewResult Test1(MyModel vm, string[] words, string moveToListID, string selectedListID) { int listNameID = Convert.ToInt32(moveToListID); List<vwWordList> lst = db.vwWordLists.Where(s => s.Word.StartsWith("wa") && s.ListID == listNameID).ToList(); vm.vwWordList = lst; return PartialView("Partial1", vm); } View: @Html.DropDownListFor(x => Model.FilterViewModel.MoveToListNameID, Model.FilterViewModel.MoveToListNameList, new { @id = "ddlMoveToListNames", style = "width:100px;" })

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  • UIVIewController not released when view is dismissed

    - by Nelson Ko
    I have a main view, mainWindow, which presents a couple of buttons. Both buttons create a new UIViewController (mapViewController), but one will start a game and the other will resume it. Both buttons are linked via StoryBoard to the same View. They are segued to modal views as I'm not using the NavigationController. So in a typical game, if a person starts a game, but then goes back to the main menu, he triggers: [self dismissViewControllerAnimated:YES completion:nil ]; to return to the main menu. I would assume the view controller is released at this point. The user resumes the game with the second button by opening another instance of mapViewController. What is happening, tho, is some touch events will trigger methods on the original instance (and write status updates to them - therefore invisible to the current view). When I put a breakpoint in the mapViewController code, I can see the instance will be one or the other (one of which should be released). I have tried putting a delegate to the mainWindow clearing the view: [self.delegate clearMapView]; where in the mainWindow - (void) clearMapView{ gameWindow = nil; } I have also tried self.view=nil; in the mapViewController. The mapViewController code contains MVC code, where the model is static. I wonder if this may prevent ARC from releasing the view. The model.m contains: static CanShieldModel *sharedInstance; + (CanShieldModel *) sharedModel { @synchronized(self) { if (!sharedInstance) sharedInstance = [[CanShieldModel alloc] init]; return sharedInstance; } return sharedInstance; } Another post which may have a lead, but so far not successful, is UIViewController not being released when popped I have in ViewDidLoad: // checks to see if app goes inactive - saves. [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(resignActive) name:UIApplicationWillResignActiveNotification object:nil]; with the corresponding in ViewDidUnload: [[NSNotificationCenter defaultCenter] removeObserver:self name:UIApplicationWillResignActiveNotification object:nil]; Does anyone have any suggestions? EDIT: - (void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{ NSString *identifier = segue.identifier; if ([identifier isEqualToString: @"Start Game"]){ gameWindow = (ViewController *)[segue destinationViewController]; gameWindow.newgame=-1; gameWindow.delegate = self; } else if ([identifier isEqualToString: @"Resume Game"]){ gameWindow = (ViewController *)[segue destinationViewController]; gameWindow.newgame=0; gameWindow.delegate = self;

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  • ImageView place at center on click in gallery view

    - by TGMCians
    i used gallery view in which i place multiple imageview dynamically but on click imageview place at center and second question how to start first imageview from left of screen. I do not want to change the place until user scroll horizontally by finger . Is there any way to achieve this. Please help for this.. private class ImageAdapter extends BaseAdapter{ public ImageAdapter() { //To set blank at bottom and make visible TextView textView = (TextView)findViewById(R.id.textView2); textView.setVisibility(View.VISIBLE); //To set the visibility visible of gallery myGallery.setVisibility(View.VISIBLE); } public int getCount() { return ProductItemArray.Image_URL.length; } public Object getItem(int position) { return null; } public long getItemId(int position) { return 0; } public View getView(int position, View arg1, ViewGroup arg2) { ImageView bottomImageView = new ImageView(context); if(Helper.isTablet(context)) bottomImageView.setLayoutParams(new Gallery.LayoutParams(VirtualMirrorActivity.convertDpToPixel(100, context), VirtualMirrorActivity.convertDpToPixel(100, context))); else bottomImageView.setLayoutParams(new Gallery.LayoutParams(VirtualMirrorActivity.convertDpToPixel(80, context), VirtualMirrorActivity.convertDpToPixel(80, context))); UrlImageViewHelper.setUrlDrawable(bottomImageView, ProductItemArray.Image_URL[position]); bottomImageView.setBackgroundResource(R.layout.border); return bottomImageView; } } myGallery.setAdapter(new ImageAdapter()); myGallery.setSelection(1); myGallery.setOnItemClickListener(new OnItemClickListener() { @Override public void onItemClick(AdapterView<?> parent, View view, final int position, long arg3) { linearLayout.removeView(frameImageView); Thread newThread = new Thread(new Runnable() { public void run() { URL url_1 = null; try { isAlreadyExistInWishlist = false; VMProductListPaging.productUrl = ProductItemArray.Image_small_URL[position]; VMProductListPaging.productId = ProductItemArray.productId[position]; VMProductListPaging.productName = ProductItemArray.product_Name[position]; url_1 = new URL(ProductItemArray.Image_small_URL[position]); bmp = BitmapFactory.decodeStream(url_1.openConnection().getInputStream()); isExecuted = true; bitmapHandler.sendMessage(bitmapHandler.obtainMessage()); } catch (Exception e) { //Toast.makeText(context,"Sorry!! This link appears to be broken",Toast.LENGTH_LONG).show(); } } }); newThread.start(); } }); Layout.xml <Gallery android:id="@+id/galleryView" android:layout_width="fill_parent" android:layout_height="wrap_content" android:spacing="5dp" android:layout_below="@+id/sendPhoto" android:layout_marginTop="10dp" android:visibility="gone"/>

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  • Prevent Explorer From Expanding Network Folders when in Folders View

    - by Chris
    When you are browsing a network share and there are over 1000 folders in the root (like at work), is there a way to prevent Explorer from expanding all the Folders when you have the "Folders" view enabled? Explorer will open the folder your double clicked on, and show that in the right navigation pane, and it's great, but wait about five seconds and the rest of the folder list pops into view, I'd rather that not happen. There is only one folder I'm interested in (or have access to), and it's annoying waiting for Explorer to load the rest of the files.

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  • Mac OS X: Finder view options?

    - by trolle3000
    Hi there. In OS X 10.6, Finder usually looks something like this: The Finder window looks like that when you double-click on most folders or drives. However, whenever I mount a Truecrypt Volume and double-click that, it looks like this: Is there any way to default to the first view option for all types of folders? I tried view options in Finder, but it didn't seem to work.

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  • BIND split-view DNS config problem

    - by organicveggie
    We have two DNS servers: one external server controlled by our ISP and one internal server controlled by us. I'd like internal requests for foo.example.com to map to 192.168.100.5 and external requests continue to map to 1.2.3.4, so I'm trying to configure a view in bind. Unfortunately, bind fails when I attempt to reload the configuration. I'm sure I'm missing something simple, but I can't figure out what it is. options { directory "/var/cache/bind"; forwarders { 8.8.8.8; 8.8.4.4; }; auth-nxdomain no; # conform to RFC1035 listen-on-v6 { any; }; }; zone "." { type hint; file "/etc/bind/db.root"; }; zone "localhost" { type master; file "/etc/bind/db.local"; }; zone "127.in-addr.arpa" { type master; file "/etc/bind/db.127"; }; zone "0.in-addr.arpa" { type master; file "/etc/bind/db.0"; }; zone "255.in-addr.arpa" { type master; file "/etc/bind/db.255"; }; view "internal" { zone "example.com" { type master; notify no; file "/etc/bind/db.example.com"; }; }; zone "example.corp" { type master; file "/etc/bind/db.example.corp"; }; zone "100.168.192.in-addr.arpa" { type master; notify no; file "/etc/bind/db.192"; }; I have excluded the entries in the view for allow-recursion and recursion in an attempt to simplify the configuration. If I remove the view and just load the example.com zone directly, it works fine. Any advice on what I might be missing?

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  • My facebook blocking ACL has stopped working

    - by Josh
    This probably very simple. This was setup before I arrived, and has been working to block facebook. I recently eliminated some static port forwarding on this 2691 (as in, I don't think anything else has changed), and now facebook is once again accessible. Why is this list not doing what it seems like it should be doing (and was doing)? Would an extended outbound ACL be more appropriate (I think that would have been my thought if I had been tasked with creating this in the first place)? Something different? I've included below what I believe are the relevant parts of the config. interface FastEthernet0/0 ip address my.pub.ip.add my.ip.add.msk ip access-group 1 in ip nat outside ip virtual-reassembly duplex auto speed auto access-list 1 deny 69.171.224.0 0.0.31.255 access-list 1 deny 74.119.76.0 0.0.3.255 access-list 1 deny 204.15.20.0 0.0.3.255 access-list 1 deny 66.220.144.0 0.0.15.255 access-list 1 deny 69.63.176.0 0.0.15.255 access-list 1 permit any ip nat inside source list 105 interface FastEthernet0/0 overload access-list 105 deny ip 192.168.0.0 0.0.0.255 192.168.8.0 0.0.0.255 access-list 105 permit ip 192.168.0.0 0.0.0.255 any access-list 105 permit ip 192.168.1.0 0.0.0.255 any EDIT ACL is once again blocking Facebook. Here is the new definition for those interested... access-list 1 deny 66.220.144.0 0.0.7.255 access-list 1 deny 66.220.152.0 0.0.7.255 access-list 1 deny 69.63.176.0 0.0.7.255 access-list 1 deny 69.63.176.0 0.0.0.255 access-list 1 deny 69.63.184.0 0.0.7.255 access-list 1 deny 69.171.224.0 0.0.15.255 access-list 1 deny 69.171.239.0 0.0.0.255 access-list 1 deny 69.171.240.0 0.0.15.255 access-list 1 deny 69.171.255.0 0.0.0.255 access-list 1 deny 74.119.76.0 0.0.3.255 access-list 1 deny 173.252.64.0 0.0.31.255 access-list 1 deny 173.252.70.0 0.0.0.255 access-list 1 deny 173.252.96.0 0.0.31.255 access-list 1 deny 204.15.20.0 0.0.3.255 access-list 1 permit any

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  • I can't see headers or footers on Word 2007 unless in full screen view

    - by kevyn
    I have a machine on a domain that does not show any headers or footers when viewing documents in word 2007, unless I switch to full screen mode. Other computers can see the headers and footers no problems. here is a video of what is happening: http://showmewhatswrong.com/play/c6fIjBVWT (expires in 6 days - but to summarize, it just shows me flicking between all the view options in word, and only when in full screen view can you see the headers and footers) any help greatly appreciated! Vista Business 32bit Office 2007

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  • Save a view in Windows Media Player

    - by Charles Roper
    I like to view my library in various ways in WMP. For example, I usually search for Podcast and order the result by date added. This gives me a list of my podcasts by date order, newest to oldest. Is there a way of saving this view so that I don't have recreate it each time I open WMP? If it's not possible to do this, can anyone suggest an app that does do it, and that handles syncing as well as WMP.

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  • VMware view for Remote Non Admin Users

    - by jcw248
    Has anyone came up with a way that I can connect to a view enviroment and not have to copy files or install software yet? I have heard of virtualizing the client. I would like to see it work similar to connecting to a view enviroment using a Linux machine. Where the desktop is launched through the browser.

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  • View a pdf with quick webview though apache proxy

    - by Musa
    I have a site(IIS) that is accessed via a proxy in apache(on an IBM i). This site serves PDFs which has quick web view and if I access a pdf directly from the IIS server the PDFs starts to display immediately but if I go through the proxy I have to wait until the entire pdf downloads before I can view it. In the apache config file I use ProxyPass /path/ http://xxx.xxx.xxx.xxx/ <LocationMatch "/path/"> Header set Cache-Control "no-cache" </LocationMatch> I tried adding SetEnv proxy-sendcl to LocationMatch directive this had no effect. The PDFs that view quickly makes a lot of partial requests This is the initial request and response headers GET http://xxx.xxx.xxx.xxx/xxx.PDF HTTP/1.1 Host: xxx.xxx.xxx.xxx Proxy-Connection: keep-alive Cache-Control: no-cache Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8 Pragma: no-cache User-Agent: Mozilla/5.0 (Windows NT 6.2; rv:9.0.1) Gecko/20100101 Firefox/9.0.1 Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 Cookie: chocolatechip HTTP/1.1 200 OK Via: 1.1 xxxxxxxx Connection: Keep-Alive Proxy-Connection: Keep-Alive Content-Length: 15330238 Date: Mon, 25 Aug 2014 12:48:31 GMT Content-Type: application/pdf ETag: "b6262940bbecf1:0" Server: Microsoft-IIS/7.5 Last-Modified: Fri, 22 Aug 2014 13:16:14 GMT Accept-Ranges: bytes X-Powered-By: ASP.NET This is a partial request and response GET http://xxx.xxx.xxx.xxx/xxx.PDF HTTP/1.1 Host: xxx.xxx.xxx.xxx Proxy-Connection: keep-alive Cache-Control: no-cache Pragma: no-cache User-Agent: Mozilla/5.0 (Windows NT 6.2; rv:9.0.1) Gecko/20100101 Firefox/9.0.1 Accept: */* Referer: http://xxx.xxx.xxx.xxx/xxxx.PDF Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 Cookie: chocolatechip Range: bytes=0-32767 HTTP/1.1 206 Partial Content Via: 1.1 xxxxxxxx Connection: Keep-Alive Proxy-Connection: Keep-Alive Content-Length: 32768 Date: Mon, 25 Aug 2014 12:48:31 GMT Content-Range: bytes 0-32767/15330238 Content-Type: application/pdf ETag: "b6262940bbecf1:0" Server: Microsoft-IIS/7.5 Last-Modified: Fri, 22 Aug 2014 13:16:14 GMT Accept-Ranges: bytes X-Powered-By: ASP.NET These are the headers I get if I go through he proxy GET /path/xxx.PDF HTTP/1.1 Host: domain:xxxx Connection: keep-alive Cache-Control: no-cache Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8 Pragma: no-cache User-Agent: Mozilla/5.0 (Windows NT 6.2; rv:9.0.1) Gecko/20100101 Firefox/9.0.1 Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8 HTTP/1.1 200 OK Date: Mon, 25 Aug 2014 13:28:42 GMT Server: Microsoft-IIS/7.5 Content-Type: application/pdf Last-Modified: Fri, 22 Aug 2014 13:16:14 GMT Accept-Ranges: bytes ETag: "b6262940bbecf1:0"-gzip X-Powered-By: ASP.NET Cache-Control: no-cache Expires: Thu, 24 Aug 2017 13:28:42 GMT Vary: Accept-Encoding Content-Encoding: gzip Keep-Alive: timeout=300, max=100 Connection: Keep-Alive Transfer-Encoding: chunked I'm guessing its because the proxy uses Transfer-Encoding: chunked but I'm not sure and wasn't able to turn it off to check. Browser Chrome 36.0.1985.143 m Using the native PDF viewer Any help to get the pdf quick web view through the proxy working would be appreciated.

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  • OWA web access calendar view missing items

    - by Marrie
    I have a user syncing calendar items - uses Outlook 2003, uses iPhone and uses OWA web access to view calendar....some recurring all day events are not showing up in OWA web access view, they are viewable in both iPhone and Outlook (client)....any ideas? ...Using Outlook Web Access version: 8.1.240.5 with Exchange Server 2007 Version: 08.01.0240.006

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  • How to visualize a list of lists of lists of ... in R?

    - by Martin
    Hi there, I have a very deep list of lists in R. Now I want to print this list to the standard output to get a better overview of the elements. It should look like the way the StatET plugin for eclipse shows a list. Example list: l6 = list() l6[["h"]] = "one entry" l6[["g"]] = "nice" l5 = list() l5[["e"]] = l6 l4 = list() l4[["f"]] = "test" l4[["d"]] = l5 l3 = list() l3[["c"]] = l4 l2 = list() l2[["b"]] = l3 l1 = list() l1[["a"]] = l2 This should print like: List of 1 $ a:List of 1 ..$ b:List of 1 .. ..$ c:List of 2 .. .. ..$ f: chr "test" .. .. ..$ d:List of 1 .. .. .. ..$ e:List of 2 .. .. .. .. ..$ h: chr "one entry" .. .. .. .. ..$ g: chr "nice" I know this is possible with recursion and the deepness. But is there a way to do this with the help of rapply or something like that? Thanx in advance, Martin

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  • Is this GetEnumAsStrings<T>() method reinventing the wheel?

    - by Edward Tanguay
    I have a number of enums and need to get them as List<string> objects in order to enumerate through them and hence made the GetEnumAsStrings<T>() method. But it seems to me there would be an easier way. Is there not a built-in method to get an enum like this into a List<string>? using System; using System.Collections.Generic; namespace TestEnumForeach2312 { class Program { static void Main(string[] args) { List<string> testModes = StringHelpers.GetEnumAsStrings<TestModes>(); testModes.ForEach(s => Console.WriteLine(s)); Console.ReadLine(); } } public static class StringHelpers { public static List<string> GetEnumAsStrings<T>() { List<string> enumNames = new List<string>(); foreach (T item in Enum.GetValues(typeof(TestModes))) { enumNames.Add(item.ToString()); } return enumNames; } } public enum TestModes { Test, Show, Wait, Stop } }

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  • Recursion in assembly?

    - by Davis
    I'm trying to get a better grasp of assembly, and I am a little confused about how to recursively call functions when I have to deal with registers, popping/pushing, etc. I am embedding x86 assembly in C++. Here I am trying to make a method which given an array of integers will build a linked list containing these integers in the order they appear in the array. I am doing this by calling a recursive function: insertElem (struct elem *head, struct elem *newElem, int data) -head: head of the list -data: the number that will be inserted at the end of a list -newElem: points to the location in memory where I will store the new element (data field) My problem is that I keep overwriting the registers instead of a typical linked list. For example, if I give it an array {2,3,1,8,3,9} my linked-list will return the first element (head) and only the last element, because the elements keep overwriting each other after head is no longer null. So here my linked list looks something like: 2--9 instead of 2--3--1--8--3--9 I feel like I don't have a grasp on how to organize and handle the registers. newElem is in EBX and just keeps getting rewritten. Thanks in advance!

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  • How to flatten list of options using higher order functions?

    - by Synesso
    Using Scala 2.7.7: If I have a list of Options, I can flatten them using a for-comprehension: val listOfOptions = List(None, Some("hi"), None) listOfOptions: List[Option[java.lang.String]] = List(None, Some(hi), None) scala> for (opt <- listOfOptions; string <- opt) yield string res0: List[java.lang.String] = List(hi) I don't like this style, and would rather use a HOF. This attempt is too verbose to be acceptable: scala> listOfOptions.flatMap(opt => if (opt.isDefined) Some(opt.get) else None) res1: List[java.lang.String] = List(hi) Intuitively I would have expected the following to work, but it doesn't: scala> List.flatten(listOfOptions) <console>:6: error: type mismatch; found : List[Option[java.lang.String]] required: List[List[?]] List.flatten(listOfOptions) Even the following seems like it should work, but doesn't: scala> listOfOptions.flatMap(_: Option[String]) <console>:6: error: type mismatch; found : Option[String] required: (Option[java.lang.String]) => Iterable[?] listOfOptions.flatMap(_: Option[String]) ^ The best I can come up with is: scala> listOfOptions.flatMap(_.toList) res2: List[java.lang.String] = List(hi) ... but I would much rather not have to convert the option to a list. That seems clunky. Any advice?

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