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  • function not working R

    - by user3722828
    I've never programmed before and am trying to learn. I'm following that "coursera" course that I've seen other people post about — a course offered by Johns Hopkins on R programming. Anyway, this was supposed to be my first function. Yet, it doesn't work! But when I type out all the steps individually, it runs just fine... Can anyone tell me why? > pollutantmean <- function(directory, pollutant, id = 1:332){ + x<- list.files("/Users/mike******/Desktop/directory", full.names=TRUE) + y<- lapply(x, read.csv) + z<- do.call(rbind.data.frame, y[id]) + + mean(z$pollutant, na.rm=TRUE) + } > pollutantmean(specdata,nitrate,1:10) [1] NA Warning message: In mean.default(z$pollutant, na.rm = TRUE) : argument is not numeric or logical: returning NA #### > x<- list.files("/Users/mike******/Desktop/specdata",full.names=TRUE) > y<- lapply(x,read.csv) > z<- do.call(rbind.data.frame,y[1:10]) > mean(z$nitrate,na.rm=TRUE) [1] 0.7976266

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  • Delete duplicate records from a SQL table without a primary key

    - by Shyju
    I have the below table with the below records in it create table employee ( EmpId number, EmpName varchar2(10), EmpSSN varchar2(11) ); insert into employee values(1, 'Jack', '555-55-5555'); insert into employee values (2, 'Joe', '555-56-5555'); insert into employee values (3, 'Fred', '555-57-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); insert into employee values (1, 'Jack', '555-55-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6 ,'Lisa', '555-70-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); I dont have any primary key in this table .But i have the above records in my table already. I want to remove the duplicate records which has the same value in EmpId and EmpSSN fields. Ex : Emp id 5 Can any one help me to frame a query to delete those duplicate records Thanks in advance

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  • Sql Query - Selecting rows where user can be both friend and user

    - by Gublooo
    Hey Sorry the title is not very clear. This is a follow up to my earlier question where one of the members helped me with a query. I have a following friends Table Friend friend_id - primary key user_id user_id_friend status The way the table is populated is - when I send a friend request to John - my userID appears in user_id and Johns userID appears in user_id_friend. Now another scenario is say Mike sends me a friend request - in this case mike's userID will appear in user_id and my userID will appear in user_id_friend So to find all my friends - I need to run a query to find where my userID appears in both user_id column as well as user_id_friend column What I am trying to do now is - when I search for user say John - I want all users Johns listed on my site to show up along with the status of whether they are my friend or not and if they are not - then show a "Add Friend" button. Based on the previous post - I got this query which does part of the job - My example user_id is 1: SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id = u.user_id and f.user_id_friend = 1 where u.name like '%' So this only shows users with whom I am friends where they have sent me request ie my userID appears in user_id_friend. Although I am friends with others (where my userID appears in user_id column) - this query will return that as null To get those I need another query like this SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id_friend = u.user_id and f.user_id = 1 where u.name like '%' So how do I combine these queries to return 1 set of users and what my friendship status with them is. I hope my question is clear Thanks

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  • ASP, sorting database with conditions using multiple columns...

    - by Mitch
    First of all, I'm still working in classic ASP (vbScript) with an MS Access Database. And, yes I know its archaic, but I'm still hopeful I can do this! So now to my problem: Take the following table as an example: PROJECTS ContactName StartDate EndDate Complete Mitch 2009-02-13 2011-04-23 No Eric 2006-10-01 2008-11-15 Yes Mike 2007-05-04 2009-03-30 Yes Kyle 2009-03-07 2012-07-08 No Using ASP (with VBScript), and an MS Access Database as the backend, I’d like to be able to sort this table with the following logic: I would like to sort this table by date, however, depending on whether a given project is complete or not I would like it to use either the “StartDate” or “EndDate” as the reference for a particular row. So to break it down further, this is what I’m hoping to achieve: For PROJECTS where Complete = “Yes”, reference “EndDate” for the purpose of sorting. For PROJECTS where Complete = “No”, reference “StartDate” for the purpose of sorting. So, if I were to sort the above table following these rules, the output would be: PROJECTS ContactName StartDate EndDate Complete 1 Eric 2006-10-01 2008-11-15* Yes 2 Mitch 2009-02-13* 2011-04-23 No 3 Kyle 2009-03-07* 2012-07-08 No 4 Mike 2007-05-04 2009-03-30* Yes *I’ve put a star next to the date that should be used for the sort in the table above. NOTE: This is actually a simplified version of what I really need to do, but I think that if I could just figure this out, I’ll be able to do the rest on my own. ANY HELP IS GREATLY APPRECIATED; I’VE BEEN STRUGGLING WITH THIS FOR FAR TOO LONG NOW! Thank you!

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  • can I make this select follower/following script more organized? (PHP/Mysql)

    - by ggfan
    In this script, it gets the followers of a user and the people the user is following. Is there a better relationship/database structure to get a user's followers and who they are following? All I have right now is 2 columns to determine their relationship. I feel this is "too simple"? (MYSQL) USER | FRIEND avian gary cend gary gary avian mike gary (PHP) $followers = array(); $followings = array(); $view = $_SESSION['user']; //view is the person logged in $query = "SELECT * FROM friends WHERE user='$view'"; $result = $db->query($query); while($row=$result->fetch_array()) { $follower=$row['friend']; $followers[] = $follower; } print_r($followers); echo "<br/>"; $query2 = "SELECT * FROM friends WHERE friend='$view'"; $result2 = $db->query($query2); while($row2=$result2->fetch_array()) { $following=$row2['user']; $followings[] = $following; } print_r($followings); echo "<br/>"; $mutual = array_intersect($followers, $followings); print_r($mutual); **DISPLAY** Your mutual friends avian Your followers avian You are following avian cen mike (I know avian is in all 3 displays, but I want to keep it that way)

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  • Python DictReader - Skipping rows with missing columns?

    - by victorhooi
    heya, I have a Excel .CSV file I'm attempting to read in with DictReader. All seems to be well, except it seems to omit rows, specifically those with missing columns. Our input looks like: mail,givenName,sn,lorem,ipsum,dolor,telephoneNumber [email protected],ian,bay,3424,8403,2535,+65(2)34523534545 mike[email protected],mike,gibson,3424,8403,2535,+65(2)34523534545 [email protected],ross,martin,,,,+65(2)34523534545 [email protected],david,connor,,,,+65(2)34523534545 [email protected],chris,call,3424,8403,2535,+65(2)34523534545 So some of the rows have missing lorem/ipsum/dolor columns, and it's just a string of commas for those. We're reading it in with: def read_gd_dump(input_file="blah 20100423.csv"): gd_extract = csv.DictReader(open('blah 20100423.csv'), restval='missing', dialect='excel') return dict([(row['something'], row) for row in gd_extract]) And I checked that "something" (the key for our dict) isn't one of the missing columns, I had originally suspected it might be that. It's one of the columns after that. However, DictReader seems to completely skip over the rows. I tried setting restval to something, didn't seem to make any difference. I can't seem to find anything in Python's CSV docs (http://docs.python.org/library/csv.html) that would explain this behaviour, but I may have misread something. Any ideas? Thanks, Victor

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  • how to join tables sql server

    - by Rick
    Im having some trouble with joining two tables. This is what my two tables look like: Table 1 Customer_ID CustomerName Add. 1000 John Smith 1001 Mike Coles 1002 Sam Carter Table 2 Sensor_ID Location Temp CustIDFK 1000 NY 70 1002 NY 70 1000 ... ... 1001 1001 1002 Desired: Sensor_ID Location Temp CustIDFK 1000 NY 70 John Smith 1002 NY 70 Sam Carter 1000 ... ... John Smith 1001 Mike Coles 1001 1002 I have made Customer_ID from table 1 my primary key, created custIDFK in table 2 and set that as my foreign key. I am really new to sql server so I am still having trouble with the whole relationship piece of it. My goal is to match one customer_ID with one Sensor_ID. The problem is that the table 2 does not have "unique IDs" since they repeat so I cant set that to my foreign key. I know I will have to do either an inner join or outer join, I just dont know how to link the sensor id with customer one. I was thinking of giving my sensor_ID a unique ID but the data that is being inserted into table 2 is coming from another program. Any suggestions?

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  • jquery json null when using localhost

    - by Eeyore
    I am trying to load json generated by my django app. It works when I save the json output and load it from a static file. However, when I make a call to a server it returns null. JSON {"users": [ { "id": 1, "name": "arnold" }, { "id": 2, "name": "frankie" } ]} Ajax call $.ajax({ url: "http://localhost:8000/json", //vs. json.js dataType: 'json', type: 'get', timeout: 20000, error: function() { alert("error"); }, beforeSend: function() { alert("beforeSend"); }, complete: function() { alert("complete"); }, success: function(data) { alert(data.users[0].name); } }); view.py return HttpResponse(simplejson.dumps(data), content_type = 'application/json; charset=utf8')

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  • Package visible in Synaptic but not in aptitude?

    - by sleepycat
    I can see libfreeimage3-dev in synaptic and have installed it from there, but what is it that I can't see it from the command line? I tried sudo aptitude update... mike@sleepycat:~$ sudo aptitude search '~n.*freeimage3.*' i libfreeimage3 - Support library for graphics image formats p libfreeimage3-dbg - Support library for graphics image formats Any ideas?

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  • Elinks and flash

    - by bajki
    Hello everybody, is there a possibility to "use" flash based objects with elinks ? I mean, i have an online flash based multiplayer game ( http://haxball.appspot.com ) and i want to connect to game with elinks installed on my shell server to create an always-present game room. To do it, i need a terminal-based webbrowser with flash support. There is an elinks installed so it would be great if there is such a possibility in it. Any ideas? Thanks, Mike

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  • remote desktop client with panning of large desktops?

    - by mikewse
    When using the standard Windows remote desktop client in Full Screen to connect to a large remote desktop, the result is usually that the remote desktop is resized to a smaller size matching the local display. Are there any RDP clients that in Full Screen instead leave the remote desktop at its original size and pan this larger area when the mouse reaches the border edges of the local display? Thanks Mike

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  • Script to monitor free space in Hdd

    - by s.mihai
    I have a server app that crushes when the HDD free space it's a multiple of 4Gb (on a Windows Server 2003). In general i keep track myself o that weekly since i use the machine from time to time. Can you point out an app or script (i don't wanna install powershell, is this doable???) that copies some larger files from one folder to another to get the free space out of the multiple of 4Gb range. Best regards, Mike

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  • Script to check a shared Exchange calendar and tehn email detial

    - by SJN
    Hi, We're running Server and Exchange 2003 here. There's a shared calendar which HR keep up-to-date detailing staff who are on leave. I'm looking for a VB Script (or alternate) which will extract the "appointment" titles of each item for the current day and then email the detail to a mail group, in doing so notifying the group with regard to which staff are on leave for the day. The resulting email body should be: Staff on leave today: Mike Davis James Stead Any ideas?

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  • CUPS Web Admin Error 500 Unknown

    - by Floyd Resler
    I keep getting a 500 Unknown error whenever I navigate off the home page of my CUPS web admin. I'm sure I have something misconfigured but I'm not sure what. Here's my configuration: # # "$Id: cupsd.conf.in 8805 2009-08-31 16:34:06Z mike $" # # Sample configuration file for the CUPS scheduler. See "man cupsd.conf" for a # complete description of this file. # # Log general information in error_log - change "warn" to "debug" # for troubleshooting... LogLevel warn # Administrator user group... SystemGroup lpadmin sys root # Only listen for connections from the local machine. Listen 192.168.6.101:631 Listen /var/run/cups/cups.sock ServerName 192.168.6.101 # Show shared printers on the local network. Browsing On BrowseOrder allow,deny BrowseAllow all BrowseLocalProtocols CUPS BrowseAddress 192.168.6.255 # Default authentication type, when authentication is required... DefaultAuthType Basic # Restrict access to the server... Order allow,deny Allow From All Allow From 127.0.0.1 # Restrict access to the admin pages... AuthType Default Require user @SYSTEM Order allow,deny Allow From All Allow From 127.0.0.1 # Restrict access to configuration files... AuthType Default Require user @SYSTEM Order allow,deny Allow From All Allow From 127.0.0.1 # Set the default printer/job policies... # Job-related operations must be done by the owner or an administrator... Require user @OWNER @SYSTEM Order deny,allow # All administration operations require an administrator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # All printer operations require a printer operator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # Only the owner or an administrator can cancel or authenticate a job... Require user @OWNER @SYSTEM Order deny,allow Order deny,allow # Set the authenticated printer/job policies... # Job-related operations must be done by the owner or an administrator... AuthType Default Order deny,allow AuthType Default Require user @OWNER @SYSTEM Order deny,allow # All administration operations require an administrator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # All printer operations require a printer operator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # Only the owner or an administrator can cancel or authenticate a job... AuthType Default Require user @OWNER @SYSTEM Order deny,allow Order deny,allow # # End of "$Id: cupsd.conf.in 8805 2009-08-31 16:34:06Z mike $". #

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  • Good website for wallpapers

    - by Gab Royer
    What are the best websites for wallpapers? My current favorite is http://interfacelift.com. Do you guys have a single source where you get all your wallpapers or do you just stumble on them on the web? Compiled results Desktop Nexus Deviant Art Of course, Google Interfacelift Aeon Project Digital Blasphemy Gnome Look and Kde Look VladStudio Flickr Wikimedia Commons NASA's image of the day Customize.org Random Walls Astronomy Picture of the day Delicious popular/wallpaper tag Studio twentyEight Instant Shift Social Wallpapering Bing's Image search Mike Swanson's collection 4chan

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  • ldap not properly resolving host

    - by mes5k
    Hi, I just changed the IP address of my (openldap) ldap server and despite DNS propagating, ldap still isn't resolving the new address correctly. When I run "host myserver.com" the proper ip address is returned. There is no entry in /etc/hosts for myserver.com. But when I run: ldapsearch -d 1 -x "uid" -H ldap://myserver.com I see the old address. How can I force ldap to check DNS for the proper IP address? thanks, Mike

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  • Thunderbird 3 - leave messages on server option

    - by user13834
    I just installed a new Thunderbird 3 on a few computers and immediately saw that i could not find the "leave messages on server" option... can anyone point that out to me ? On my personal pc i upgraded Thunderbird 2 to 3 and there appears the option, but when i create a new account... i can not find the option, can anyone help me with this ... Best regards, Mike.

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  • Business Strategy - Google Case Study

    Business strategy defined by SMBTN.com is a term used in business planning that implies a careful selection and application of resources to obtain a competitive advantage in anticipation of future events or trends. In more general terms business strategy is positioning a company so that it has the greatest competitive advantage over others in the markets and industries that they participate in. This process involves making corporate decisions regarding which markets to provide goods and services, pricing, acceptable quality levels, and how to interact with others in the marketplace. The primary objective of business strategy is to create and increase value for all of its shareholders and stakeholders through the creation of customer value. According to InformationWeek.com, Google has a distinctive technology advantage over its competitors like Microsoft, eBay, Amazon, Yahoo. Google utilizes custom high-performance systems which are cost efficient because they can scale to extreme workloads. This hardware allows for a huge cost advantage over its competitors. In addition, InformationWeek.com interviewed Stephen Arnold who stated that Google’s programmers are 50%-100% more productive compared to programmers working for their competitors.  He based this theory on Google’s competitors having to spend up to four times as much just to keep up. In addition to Google’s technological advantage, they also have developed a decentralized management schema where employees report directly to multiple managers and team project leaders. This allows for the responsibility of the technology department to be shared amongst multiple senior level engineers and removes the need for a singular department head to oversee the activities of the department.  This is a unique approach from the standard management style. Typically a department head like a CIO or CTO would oversee the department’s global initiatives and business functionality.  This would then be passed down and administered through middle management and implemented by programmers, business analyst, network administrators and Database administrators. It goes without saying that an IT professional’s responsibilities would be directed by Google’s technological advantage and management strategy.  Simply because they work within the department, and would have to design, develop, and support the high-performance systems and would have to report multiple managers and project leaders on a regular basis. Since Google was established and driven by new and immerging technology, all other departments would be directly impacted by the technology department.  In fact, they would have to cater to the technology department since it is a huge driving for in the success of Google. Reference: http://www.smbtn.com/smallbusinessdictionary/#b http://www.informationweek.com/news/software/linux/showArticle.jhtml?articleID=192300292&pgno=1&queryText=&isPrev=

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  • Get to Know a Candidate (11 of 25): Roseanne Barr&ndash;Peace &amp; Freedom Party

    - by Brian Lanham
    DISCLAIMER: This is not a post about “Romney” or “Obama”. This is not a post for whom I am voting. Information sourced for Wikipedia. Barr is an American actress, comedienne, writer, television producer, and director.  Barr began her career in stand-up comedy at clubs before gaining fame for her role in the sitcom Roseanne. The show was a hit and lasted nine seasons, from 1988 to 1997. She won both an Emmy Award and a Golden Globe Award for Best Actress for her work on the show. Barr had crafted a "fierce working-class domestic goddess" persona in the eight years preceding her sitcom and wanted to do a realistic show about a strong mother who was not a victim of patriarchal consumerism. The granddaughter of immigrants from Europe and Russia, Barr was the oldest of four children in a working-class Jewish Salt Lake City family; she was also active in the LDS Church. In 1974 she married Bill Pentland, with whom she had three children, before divorcing in 1990 and marrying comedian Tom Arnold for four years. Controversy arose when she sang "The Star-Spangled Banner" off-key at a 1990 nationally aired baseball game, followed by grabbing her crotch and spitting. After her sitcom ended, she launched her own talk show, The Roseanne Show, which aired from 1998 to 2000. In 2005, she returned to stand-up comedy with a world tour. In 2011, she starred in an unscripted TV show, Roseanne's Nuts that lasted from July to September of that year, about her life on a Hawaiian farm. The Peace and Freedom Party (PFP) is a nationally-organized political party with affiliates in more than a dozen states, including California, Florida, Colorado and Hawaii. Its first candidates appeared on the ballot in 1966, but the Peace and Freedom Party of California was founded on June 23, 1967, after the LAPD riot in the wealthy Century City section of Los Angeles, and qualified for the ballot in January 1968.  The Peace and Freedom Party went national in 1968 as a left-wing organization opposed to the Vietnam War. From its inception, Peace and Freedom Party has been a left-wing political organization. It is a strong advocate of protecting the environment from pollution and nuclear waste. It advocates personal liberties and universal, high quality and free access to education and health care. Its understanding of socialism includes a socialist economy, where industries, financial institutions, and natural resources are owned by the people as a whole and democratically managed by the people who work in them and use them. Barr is on the Ballot in: CA, CO, FL Learn more about Roseanne Barr and Peace and Freedom Party on Wikipedia.

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  • HP Compaq 2510p wireless disabled by hardware switch

    - by mylovelyhorse
    I have an HP Compaq 2510p laptop running ubuntu 12.04 LTS. ubuntu reports that wireless is disabled by means of a hardware switch. There is a 'soft-key' button on the laptop to control the physical wireless hardware but this does not respond. There is no other button, slider, (fn)+ combination to control the physical wireless hardware. There is no BIOS function to disable wireless (and on XP - previous OS - wireless functioned fine). mike@ubuntu:~$ rfkill list all 0: brcmwl-0: Wireless LAN Soft blocked: no Hard blocked: yes 1: hp-wifi: Wireless LAN Soft blocked: no Hard blocked: no Running rfkill unblock all doesn't change things and I can see no way to change use from 0: to 1: (if that's even possible - or desirable - in the first place). I have checked for additional drivers and the Broadcom proprietary wireless driver is already installed and has a green light. Essentially, I believe I need to make the HP 'soft-keys' work - or at least the wireless card toggle. Advice gratefully received. Cheers M

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  • Extended Blogs – Now cross posting to Sqlblog.com

    - by extended_events
    Thanks to some help from SQL MVP Adam Mechanic, the Extended Events blog is now being cross posted on SQLblog.com. Except for the first two posts (welcome message & Reading event data 101), these blogs will be identical so read whichever site you prefer, either the SQLblog version, or the original MSDN blog. - Mike Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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