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  • What is the safe way to use fork with Apache::DBI under mod_perl2?

    - by codeholic
    I have a problem when I use Apache::DBI in child processes. The problem is that Apache::DBI provides a single handle for all processes which use it, so I get DBD::mysql::db selectall_arrayref failed: Commands out of sync; you can't run this command now at /usr/local/www/apache22/data/test-fork.cgi line 20. Reconnection doesn't help, since Apache::DBI reconnects in all processes, as I understood the following error The server encountered an internal error and was unable to complete your request. Error message: DBD driver has not implemented the AutoCommit attribute at /usr/local/lib/perl5/site_perl/5.8.9/Apache/DBI.pm line 283. , Here's the origin code: use Data::Dumper 'Dumper'; use DBI (); my $dbh = DBI->connect($dsn, $username, $password, { RaiseError => 1, PrintError => 0, }); my $file = "/tmp/test-fork.tmp"; my $pid = fork; defined $pid or die "fork: $!"; if ($pid) { my $rows = eval { $dbh->selectall_arrayref('SELECT SLEEP(1)') }; print "Content-Type: text/plain\n\n"; print $rows ? "parent: " . Dumper($rows) : $@; } else { my $rows = eval { $dbh->selectall_arrayref('SELECT SLEEP(1)') }; open FH, '>', $file or die "$file: $!"; print FH $rows ? "child: " . Dumper($rows) : $@; close FH; } The code I used for reconnection: ... else { $dbh->disconnect; $dbh = DBI->connect($dsn, $username, $password, $attrs); my $rows = eval { $dbh->selectall_arrayref('SELECT SLEEP(1)') }; open FH, '>', $file or die "$file: $!"; print FH $rows ? "child: " . Dumper($rows) : $@; close FH; } Is there a safe way to use Apache::DBI with forking? Is there a way to make it create a new connection perhaps?

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  • Python error with IndentationError: unindent does not match any outer indentation level

    - by Vikrant Cornelio
    from tweepy import Stream from tweepy import OAuthHandler from tweepy.streaming import StreamListener ckey='W1VPPrau42ENAWP1EnDGpQ' csecret='qxtY2rYNN0QT0Ndl1L4PJhHcHuWRJWlEuVnHFDRSE' atoken='1577208120-B8vGWIquxbmscb9xdu5AUzENv09kGAJUCddJXAO' asecret='tc9Or4XoOugeLPhwmCLwR4XK8oUXQHqnl10VnQpTBzdNR' class listener(StreamListener): def on_data(self,data): print data return True def on_error(self,status): print status auth=OAuthHandler(ckey,csecret) auth.set_access_token(atoken,asecret) twitterStream=Stream(auth,listener()) twitterStream.filter(track=["car"]) I typed this in my Python shell i got an error...the error was IndentationError: unindent does not match any outer indentation level..Please help me!!!!!!!!!!!

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  • Matplotlib, plotting discreet values

    - by Arkapravo
    I am trying to plot the following ! from numpy import * from pylab import * import random for x in range(1,500): y = random.randint(1,25000) print(x,y) plot(x,y) show() However, I keep getting a blank graph (?). Just to make sure that the program logic is correct I added the code print(x,y), just the confirm that (x,y) pairs are being generated. (x,y) pairs are being generated, but there is no plot, I keep getting a blank graph. Any help ?

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  • problem with template inheritance

    - by amiad
    I'm trying to understand whay i get an error on this code: (the error is under g++ unix compiler. VS is compiling OK) template<class T> class A { public: T t; public: A(const T& t1) : t(t1) {} virtual void Print() const { cout<<*this<<endl;} friend ostream& operator<<(ostream& out, const A<T>& a) { out<<"I'm "<<typeid(a).name()<<endl; out<<"I hold "<<typeid(a.t).name()<<endl; out<<"The inner value is: "<<a.t<<endl; return out; } }; template<class T> class B : public A<T> { public: B(const T& t1) : A<T>(t1) {} const T& get() const { return t; } }; int main() { A<int> a(9); a.Print(); B<A<int> > b(a); b.Print(); (b.get()).Print(); return 0; } This code is giving the following error: main.cpp: In member function 'const T& B::get() const': main.cpp:23: error: 't' was not declared in this scope It did compiled when i changed the code of B to this: template<class T> class B : public A<T> { public: B(const T& t1) : A<T>(t1) {} const T& get() const { return A<T>::t; } }; I just cant understand what is the problem with the first code... It doesn't make sense that i really need to write "A::" every time...

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  • JasperPrintManager.printReport(jasperPrint,true)

    - by user121196
    I have a print button in jsp page that prints a report created in jasper. What does calling JasperPrintManager.printReport(jasperPrint,true) in a jsp page actually do? I imagine it has to invoke a javascript command to bring up the print dialog and sends the data to it. It is not working for me. any idea?

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  • How to determine if the variable is a function in Python?

    - by bodacydo
    Since functions are values in Python, how do I determine if the variable is a function? For example: boda = len # boda is the length function now if ?is_var_function(boda)?: print "Boda is a function!" else: print "Boda is not a function!" Here hypothetical ?is_var_function(x)? should return true if x is a callable function, and false if it is not. Please advise! Thanks, Boda Cydo.

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  • How to access memory location in Java?

    - by Abhishek Jain
    Is it possible that we can access memory location in Java directly or indirectly? If we tries to print a object, it will print hashcode. Does hashcode signify indirectly to memory location? For two object at different memory location but still their hashcode can varies. -Abhishek

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  • Perl glob one liner

    - by user260826
    Im working in a perl one liner to invert the contents of my file contents or perform operations, I was able to generate the script and one liner, but this one liner only works by entering file by file. perl -i -ne '$a=reverse $_;print "$a\n"' <filename> I want to change my one liner to get input from a range of files but when i do: perl -i -ne '$a=reverse $_;print "$a\n"' | ls -al I just get screen output of ls -al Not sure how to proceed. Thanks

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  • High level macro not recognized - Beginner MASM

    - by Francisco P.
    main proc finit .while ang < 91 invoke func, ang fstp res print real8$(ang), 13, 10 print real8$(res), 13, 10 fld ang fld1 fadd fstp ang .endw ret main endp What's wrong with this piece of MASM code? I get an error on .endw. I have ran some tests to ensure myself of that. Assembler tells me invalid instruction operands. Thank you for your time!

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  • OSX, G/AWK, Bash - "illegal statement, unterminated string" and no file output.

    - by S1syphus
    I have a script that somebody from SO kindly provided to solve an issue I was having, However, I'm having some issues getting it to work on OSX. gawk --version GNU Awk 3.1.6 awk --version awk version 20100208 The original source is: awk -F, -vOFS=, -vc=1 ' NR == 1 { for (i=1; i<NF; i++) { if ($i != "") { g[c]=i; f[c++]=$i } } } NR>2 { for (i=1; i < c; i++) { print $1,$2, $g[i] > "output_"f[i]".csv } }' data.csv When I run the script it gives the following error: awk: syntax error at source line 12 context is print $1,$2, $g[i] > >>> "output_"f <<< [i]".csv awk: illegal statement at source line 13 From the look of it the variable of [i] isn't been amended to the output file, but I don't know why. If I change AWK to GAWK and run the original script here is the output: gawk: cmd. line:11: print $1,$2, $g[i] > "output_"f[i]".csv gawk: cmd. line:11: ^ unterminated string So I edit the relevant line to fix the unterminated string print $1,$2, $g[i] > "output_"f[i]".csv" Then it runs through fine produces no errors, but there is no output files. Any ideas? I spent the majority of last night and this morning pouring over this. A sample input file: ,,L1,,,L2,,,L3,,,L4,,,L5,,,L6,,,L7,,,L8,,,L9,,,L10,,,L11, Title,r/t,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,neede d,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst EXAMPLEfoo,60,6,6,6,0,0,0,0,0,0,6,6,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 EXAMPLEbar,30,6,6,12,6,7,14,6,6,12,6,6,12,6,8,16,6,7,14,6,7.5,15,6,6,12,6,8,16,6,0,0,6,7,14 EXAMPLE1,60,3,3,3,3,5,5,3,4,4,3,3,3,3,6,6,3,4,4,3,3,3,3,4,4,3,8,8,3,0,0,3,4,4 EXAMPLE2,120,6,6,3,0,0,0,6,8,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 EXAMPLE3,60,6,6,6,6,8,8,6,6,6,6,6,6,0,0,0,0,0,0,6,8,8,6,6,6,0,0,0,0,0,0,0,10,10 EXAMPLE4,30,6,6,12,6,7,14,6,6,12,6,6,12,3,5.5,11,6,7.5,15,6,6,12,6,0,0,6,9,18,6,0,0,6,6.5,13 And the example out put should be So for L1 an example out put would look like: EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 And for L2: EXAMPLEfoo,60,0 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,0 EXAMPLE3,60,6 EXAMPLE4,30,6

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  • sort associative array in awk - help?

    - by Richard
    Hi all, I have an associative array in awk that gets populated like this... chr_count[$3]++ When I try to print my chr_counts I use this: for (i in chr_count) { print i,":",chr_count[i]; } But not surprisingly, the order of i is not sorted in any way. Is there an easy way to iterate over the sorted "keys" of chr_count?

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  • Multi-Page invoice printing on one page

    - by ryan
    I have an invoice that contains over 100 lines of product that I am trying to print. This single invoice should take over 3 pages, but when printed, the content flows off the footer and the next page is the following invoice. I am using divs instead of tables, and I can't understand why the long invoices will not print on multiple pages. Any ideas?

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  • Problem with recursivity in rebol

    - by Rebol Tutorial
    I have a block on which I want to iterate recursively folders: [ Chrome [ content [ preferences prefpages ] ] icons [ default ] locale [ en-EN [ csbar ] ] skin ] with this function: iterate-folder: func [folders [block!]][ foreach folder folders [ either not block? folder [ probe folder temp: folder input ] [ print "folder" probe folder print "folders" probe folders probe select folders folder type-folder: type? select folders folder probe type-folder input iterate-folder select folders folder ] ] ] but for stupid reason I can't see, probe folder returns none above so it doesn't work.

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  • How to accss memory location in Java?

    - by Abhishek Jain
    Is it possible that we can access memory location in Java directly or indirectly? If we tries to print a object, it will print hashcode. Does hashcode signify indirectly to memory location? For two object at different memory location but still their hashcode can varies. -Abhishek

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  • using graphviz with qt

    - by radi
    hi , i have a compiler project and i want to print the ast after the compile complete so can i print this ast to qt (on c++) panel using graphviz ? note : i dont know if there is a binding between qt or c++ and graphviz , so if it doesnt work please help me to find the alternative . thanks .

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  • Git for Websites / post-receive / Separation of Test and Production Sites

    - by Walt W
    Hi all, I'm using Git to manage my website's source code and deployment, and currently have the test and live sites running on the same box. Following this resource http://toroid.org/ams/git-website-howto originally, I came up with the following post-receive hook script to differentiate between pushes to my live site and pushes to my test site: while read ref do #echo "Ref updated:" #echo $ref -- would print something like example at top of file result=`echo $ref | gawk -F' ' '{ print $3 }'` if [ $result != "" ]; then echo "Branch found: " echo $result case $result in refs/heads/master ) git --work-tree=c:/temp/BLAH checkout -f master echo "Updated master" ;; refs/heads/testbranch ) git --work-tree=c:/temp/BLAH2 checkout -f testbranch echo "Updated testbranch" ;; * ) echo "No update known for $result" ;; esac fi done echo "Post-receive updates complete" However, I have doubts that this is actually safe :) I'm by no means a Git expert, but I am guessing that Git probably keeps track of the current checked-out branch head, and this approach probably has the potential to confuse it to no end. So a few questions: IS this safe? Would a better approach be to have my base repository be the test site repository (with corresponding working directory), and then have that repository push changes to a new live site repository, which has a corresponding working directory to the live site base? This would also allow me to move the production to a different server and keep the deployment chain intact. Is there something I'm missing? Is there a different, clean way to differentiate between test and production deployments when using Git for managing websites? As an additional note in light of Vi's answer, is there a good way to do this that would handle deletions without mucking with the file system much? Thank you, -Walt PS - The script I came up with for the multiple repos (and am using unless I hear better) is as follows: sitename=`basename \`pwd\`` while read ref do #echo "Ref updated:" #echo $ref -- would print something like example at top of file result=`echo $ref | gawk -F' ' '{ print $3 }'` if [ $result != "" ]; then echo "Branch found: " echo $result case $result in refs/heads/master ) git checkout -q -f master if [ $? -eq 0 ]; then echo "Test Site checked out properly" else echo "Failed to checkout test site!" fi ;; refs/heads/live-site ) git push -q ../Live/$sitename live-site:master if [ $? -eq 0 ]; then echo "Live Site received updates properly" else echo "Failed to push updates to Live Site" fi ;; * ) echo "No update known for $result" ;; esac fi done echo "Post-receive updates complete" And then the repo in ../Live/$sitename (these are "bare" repos with working trees added after init) has the basic post-receive: git checkout -f if [ $? -eq 0 ]; then echo "Live site `basename \`pwd\`` checked out successfully" else echo "Live site failed to checkout" fi

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  • NSLog(@"%@",super) crashing

    - by Chandan Shetty SP
    I used NSLog(@"%@",super) in a method(any method) and it is crashing.... Why? How to print the super contents? Updated : currentclassname : superClassName { } and also if i use NSLog(@"%@", [super description]); It is printing "<currentclassname: 0x3db7230>" instead of superClassName... It is expected to print superClassName right. Thanks in advance,

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  • how to get ipaddress of my computer

    - by astha goyal
    hello i want to knw the ipaddress of my computer. /sbin/ifconfig eth0 | grep 'inet addr:' | cut -d: -f2 | awk '{ print $1}' this command gives the ipaddress of my computer and print result on console but i want it in a varible sothat i can use it in my C program. How can i do that.

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  • SVN post-commit hook not executing file

    - by Oded
    I have created an exe file that will print to console the first and second arguments that it receives. In the SVN post-commit hook I wrote: PATH_TO_FILE\print.exe "%1" "%2" when I make a check-in, it gets stuck. %1 is the PATH %2 is revision number

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  • class, dict, self, init, args ?

    - by kame
    class attrdict(dict): def __init__(self, *args, **kwargs): dict.__init__(self, *args, **kwargs) self.__dict__ = self a = attrdict(x=1, y=2) print a.x, a.y b = attrdict() b.x, b.y = 1, 2 print b.x, b.y Could somebody explain the first four lines in words? I read about classes and methods. But here it seems very confusing.

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  • Get Element value with minidom, Python

    - by Eef
    Hi Guys, I am creating a GUI frontend for the Eve Online API in Python. I have successfully pulled the XML data from their server. I am trying to grab the value from a node called "name" from xml.dom.minidom import parse dom = parse("C:\\eve.xml") name = dom.getElementsByTagName('name') print name This seems to find the node ok but the output is below: [<DOM Element: name at 0x11e6d28>] How could I get it to print the value of the node? Cheers

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  • Why isn't django-nose running the doctests in my models?

    - by Conley Owens
    I'm trying to use doctests with django-nose. All my doctests are running, except not any doctests within a model (unless it is abstract). class TestModel1(models.Model): """ >>> print 'pass' pass """ pass class TestModel2(models.Model): """ >>> print 'pass' pass """ class Meta: abstract = True pass The first doctest does not run and the second does. Why is this?

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  • Creating meaningful routes in wizard style ASP.NET MVC form

    - by R0MANARMY
    I apologize in advance for a long question, figured better have a bit more information than not enough. I'm working on an application with a fairly complex form (~100 fields on it). In order to make the UI a little more presentable the fields are organized into regions and split across multiple (~10) tabs (not unlike this, but each tab does a submit/redirect to next tab). This large input form can also be in one of 3 views (read only, editable, print friendly). The form represents a large domain object (let's call it Foo). I have a controller for said domain object (FooController). It makes sense to me to have the controller be responsible for all the CRUD related operations. Here are the problems I'm having trouble figuring out. Goals: I'd like to keep to conventions so that Foo/Create creates a new record Foo/Delete deletes a record Foo/Edit/{foo_id} takes you to the first tab of the form ...etc I'd like to be able to not repeat the data access code such that I can have Foo/Edit/{foo_id}/tab1 Foo/View/{foo_id}/tab1 Foo/Print/{foo_id}tab1 ...etc use the same data access code to get the data and just specify which view to use to render it. My current implementation has a massive FooController with Create, Delete, Tab1, Tab2, etc actions. Tab actions are split out into separate files for organization (using partial classes, which may or may not be abuse of partial classes). Problem I'm running into is how to organize my controller(s) and routes to make that happen. I have the default route {controller}/{action}/{id} Which handles goal 1 properly but doesn't quite play nice with goal 2. I tried to address goal 2 by defining extra routes like so: routes.MapRoute( "FooEdit", "Foo/Edit/{id}/{action}", new { controller = "Foo", action = "Tab1", mode = "Edit", id = (string)null } ); routes.MapRoute( "FooView", "Foo/View/{id}/{action}", new { controller = "Foo", action = "Tab1", mode = "View", id = (string)null } ); routes.MapRoute( "FooPrint", "Foo/Print/{id}/{action}", new { controller = "Foo", action = "Tab1", mode = "Print", id = (string)null } ); However defining these extra routes causes the Url.Action to generate routs like Foo/Edit/Create instead of Foo/Create. That leads me to believe I designed something very very wrong, but this is my first attempt an asp.net mvc project and I don't know any better. Any advice with this particular situation would be awesome, but feedback on design in similar projects is welcome.

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