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  • How to pass a resource file string to a function in an external .js file

    - by hima
    Hi , There is a Messages.resx file under App_GlobalResources in my solution. Everytime i create a string and give a value to the string internal static string Alert_EnterUserName { get { return ResourceManager.GetString("Alert_EnterUserName", resourceCulture); } } is created automatically. Can anybody guide me how to use this string in a function which is present in a seperate .js file? Thanks in advance

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  • Position of character in a string

    - by Irfan
    I have a string : var str = "12345a45";//position is 6 here now i want the position of 'a'(alphabet) in that string similarly i have few more string like this: var str1 = "1234567a45";//position is 8 here var str2 = "12345a4";//position is 6 here var str3 = "123a";//position is 4 here var str4 = "a45";//position is 1 here Now what i thought of doing is , just searching the string from last and know the occurrence of any alphabet in that strings. any help will be appreciated . thanks.

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  • Find a regular expression that matches a string?

    - by Mirai
    I need a model for finding all of the regular expressions that would match a particular string. Basically, I need an algorithm for doing what I do to generate a regex search string from some pattern. My purpose for this to create a list of potential regular expressions from a selection of text and order that list from least specific (i.e. string of characters with abitrary length) to most specific (i.e. the string itself) to be used in text editor.

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  • R - indirectly calling a matrix using a string

    - by Boris Senderovich
    Example: There is a matrix of data called VE There is a vector of string where the first element is the string VE. I need to indirectly call the string and be able to access data. For example if I need the 6th column of matrix VE then I want to do: Vector[1][,6] Essentially I need R to start reading those string as if they are the matrix names that are already in this page. I need this syntax to be dynamic because I am putting it in a loop.

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  • Java - String Pool

    - by Gogi
    What is meant by String Pool ? What is difference between the following declarations : String s="hello"; String s=new String("hello"); Is there any difference between the Storing of this two strings by JVM ?

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  • read lenght of string from stdin

    - by teoz
    I want to take a string from stdin but I don't want a static array of fixed size i knew that scanf need something where save the stdin input, but i can't do something like this: char string[10] scanf("%s",string); becouse i need to knew before how long will be the string in order to allocate the right memory space can you help me to resolve this problem?

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  • JavaScript regular expressions to validate string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

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  • how to read a string from a \n delimited file

    - by Matias
    I'm trying to read a return delimited file. full of phrases. I'm trying to put each phrase into a string. The problem is that when I try to read the file with fscanf(file,"%50s\n",string); the string only contains one word. when it bumps with a space it stops reading the string

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  • Validate a statment from string in JAVA

    - by Adnan
    I have a string; String allIn = "(50 > 100) AND (85< 100)"; Now I need to evaluate if the conditions inside are TRUE or FALSE, how can I do it? In real the string will be a value from a field in my DB, where I will substitute different values and they will form a string as shown above.

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  • Converting upper-case string into title-case using Ruby

    - by wsb3383
    Hi, all. I'm trying to convert an all-uppercase string in Ruby into a lower case one, but with each word's first character being upper case. Example: convert "MY STRING HERE" to "My String Here". I know I can use the .downcase method, but that would make everything lower case ("my string here"). I'm scanning all lines in a file and doing this change, so is there a regular expression I can use through ruby to achieve this? Thanks!

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  • JavaScript: add or subtract from number in string

    - by yoavf
    I have a string that looks like "(3) New stuff" where 3 can be any number. I would like to add or subtract to this number. I figured out the following way: var thenumber = string.match((/\d+/)); thenumber++; string = string.replace(/\(\d+\)/ ,'('+ thenumber +')'); Is there a more elegant way to do it?

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  • Validate a string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

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  • Use textbox value on submit as a query string variable

    - by Eric
    How would I take a text box value and use it in the query string on submit? I'd like it to start as this, /News?favorites=True and end up something like this after the user enters in a search and clicks search. /News?query=test&favorites=True The controller action looks like this public ActionResult Index(string query,bool favorites) { //search code } This question is something close to what I'd like to do, but I'd like to use the query string and maintain the existing values in the query string. Thanks.

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  • C++ class is not recognizing string data type

    - by reallythecrash
    I'm working on a program from my C++ textbook, and this this the first time I've really run into trouble. I just can't seem to see what is wrong here. Visual Studio is telling me Error: identifier "string" is undefined. I separated the program into three files. A header file for the class specification, a .cpp file for the class implementation and the main program file. These are the instructions from my book: Write a class named Car that has the following member variables: year. An int that holds the car's model year. make. A string that holds the make of the car. speed. An int that holds the car's current speed. In addition, the class should have the following member functions. Constructor. The constructor should accept the car's year and make as arguments and assign these values to the object's year and make member variables. The constructor should initialize the speed member variable to 0. Accessors. Appropriate accessor functions should be created to allow values to be retrieved from an object's year, make and speed member variables. There are more instructions, but they are not necessary to get this part to work. Here is my source code: // File Car.h -- Car class specification file #ifndef CAR_H #define CAR_H class Car { private: int year; string make; int speed; public: Car(int, string); int getYear(); string getMake(); int getSpeed(); }; #endif // File Car.cpp -- Car class function implementation file #include "Car.h" // Default Constructor Car::Car(int inputYear, string inputMake) { year = inputYear; make = inputMake; speed = 0; } // Accessors int Car::getYear() { return year; } string Car::getMake() { return make; } int Car::getSpeed() { return speed; } // Main program #include <iostream> #include <string> #include "Car.h" using namespace std; int main() { } I haven't written anything in the main program yet, because I can't get the class to compile. I've only linked the header file to the main program. Thanks in advance to all who take the time to investigate this problem for me.

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  • Look up or insert new element to string list in Haskell

    - by nightscream
    So I want to have a function that takes a String and a list as an argument, and checks if that element is already on the list, if it is, returns the same list, if it isnt, adds it to the list and returns it, 'im a begginer with haskell so heres what I have tried with no sucess: check:: String ->[String] ->[String] check x [] = []++[x] check x (y:xs) | x==y = (y:xs) | otherwise = check x xs Can someone point me the way ? thks

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  • On what basis would you split donation money among your open source team members without any strife?

    - by Vigneshwaran
    I am a developer of an open source project which is hosted in SourceForge. It started out as a little app then after some releases, it got more and more popular and it started consuming more time and responsibility from me. So I have enabled the donation option in SourceForge. I'm passionate to continue developing it for free but if (ever) any money comes in, how should I split it with my team? Should I split the amount equally among the number of team members? (50-50 as it is two-member team now) Number of classes, commits or any other valuable submissions by team members? Any other idea? What would you do in such situation? Please give your opinions. I hope this question will be useful for others.

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  • How to split currently used partition on Ubuntu server?

    - by KrizzzyS
    I would like to split a currently used partition that is mounted to /usr directory. I did this because / only had 1 gb of data allocated to it. Now, I did not account for the /home directory when I made this partition (or I would have made two partitions). So I have 14 gb mounted to usr/ with 12 gb free. Is there a way I can reclaim the free space on this partition to make another partition to mount to /home? Here is the result of a df -h: I have tried to split the /dev/mmcblk1p4 into 2 different partitions but I was not able to save the partition table correctly.

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  • Select dynamic string has a different value when referenced in Where clause

    - by David
    I dynamically select a string built using another string. So, if string1='David Banner', then MyDynamicString should be 'DBanne' Select ... , Left( left((select top 1 strval from dbo.SPLIT(string1,' ')) //first word ,1) //first character + (select top 1 strval from dbo.SPLIT(string1,' ') //second word where strval not in (select top 1 strval from dbo.SPLIT(string1,' '))) ,6) //1st character of 1st word, followed by up to 5 characters of second word [MyDynamicString] ,... From table1 Join table2 on table1pkey=table2fkey Where MyDynamicString <> table2.someotherfield I know table2.someotherfield is not equal to the dynamic string. However, when I replace MyDynamicString in the Where clause with the full left(left(etc.. function, it works as expected. Can I not reference this string later in the query? Do I have to build it using the left(left(etc.. function each time in the where clause?

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  • Obj-c Turning long string into multidimensional array

    - by Phil
    I have a long NSString, something like "t00010000t00020000t00030000" and so on. I need to split that up into each "t0001000". I'm using... NSArray *tileData = [[GameP objectForKey:@"map"] componentsSeparatedByString:@"t"]; And it splits it up, but the "t" is missing, which I need (although I think I could append it back on). The other way I guess would be to split it up by counting 8 char's, although not sure how to do that. But ideally I need it split into a [][] type array so I can get to each bit with something like... NSString tile = [[tileData objectAtIndex:i] objectAtIndex:j]]; I'm new to obj-c so thanks for any help.

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  • String.split() - matching leading empty String prior to first delimiter?

    - by tehblanx
    I need to be able to split an input String by commas, semi-colons or white-space (or a mix of the three). I would also like to treat multiple consecutive delimiters in the input as a single delimiter. Here's what I have so far: String regex = "[,;\\s]+"; return input.split(regex); This works, except for when the input string starts with one of the delimiter characters, in which case the first element of the result array is an empty String. I do not want my result to have empty Strings, so that something like, ",,,,ZERO; , ;;ONE ,TWO;," returns just a three element array containing the capitalized Strings. Is there a better way to do this than stripping out any leading characters that match my reg-ex prior to invoking String.split? Thanks in advance!

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