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  • Keep a javascript variable after an ajax call

    - by Guillaume le Floch
    I'm new in javascript and jQuery. I'm using ajax calls to get data from my server. The fact is, I'm losing my javascript variables after the call .. Here is what I did : the variable is define outside any function and treat in an other function. var a = 0; function myfunction(url){ $.ajax({ url: url, timeout: 20000, success: function(data){ // Do some stuff // The a variable is now undefined }, error: function(){ // Do some stuff } }); } Everything is working fine, the only thing is that I need to keep my variables ... but it looks like it's gone .. Does anyone know why? Thanks

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  • JQuery Ajax Updating MySQL Database, But Not Running Success Function

    - by myrmidon16
    I am currently using the JQuery ajax function to call an exterior PHP file, in which I select and add data in a database. Once this is done, I run a success function in JavaScript. What's weird is that the database is updating successfully when ajax is called, however the success function is not running. Here is my code: <!DOCTYPE html> <head> <script type="text/javascript" src="jquery-1.6.4.js"></script> </head> <body> <div onclick="addtask();" style="width:400px; height:200px; background:#000000;"></div> <script> function addtask() { var tid = (Math.floor(Math.random() * 3)) + 1; var tsk = (Math.floor(Math.random() * 10)) + 1; if(tsk !== 1) { $.ajax({ type: "POST", url: "taskcheck.php", dataType: "json", data: {taskid:tid}, success: function(task) {alert(task.name);} }); } } </script> </body> </html> And the PHP file: session_start(); $connect = mysql_connect('x', 'x', 'x') or die('Not Connecting'); mysql_select_db('x') or die ('No Database Selected'); $task = $_REQUEST['taskid']; $uid = $_SESSION['user_id']; $q = "SELECT task_id, taskname FROM tasks WHERE task_id=" .$task. " LIMIT 1"; $gettask = mysql_fetch_assoc(mysql_query($q)); $q = "INSERT INTO user_tasks (ut_id, user_id, task_id, taskstatus, taskactive) VALUES (null, " .$uid. ", '{$gettask['task_id']}', 0, 1)"; $puttask = mysql_fetch_assoc(mysql_query($q)); $json = array( "name" => $gettask['taskname'] ); $output = json_encode($json); echo $output; Let me know if you have any questions or comments, thanks.

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  • Permalink Ajax Issue Wordpress

    - by Soumya
    function AjaxRequest(section,divName) { var pageurl = fullPath+"/ajaxrequest.php?section="+section+"&divName="+divName; //alert(pageurl); var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById(divName).innerHTML=''; document.getElementById(divName).innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET",pageurl,true); xmlhttp.send(); } I have a Code like that in wordpress which is calling a page using ajax. It is working fine when the page are coming in ID like ?page_id=37 but stop working when I am activating Permalink like /overview/ajaxpage. I am getting 404 pafe error on xmlhttp.readyState. Can any one help me to solve it. I know its a permalink Problem probably this code of ajax is not sufficient for transmuting Permalink.

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  • refresh page with ajax jquery without use of reload function

    - by Ronak Patel
    I am performing delete records by using jquery ajax in php. I want to refresh that content without the use of location.reload() function. I tried this, $("#divSettings").html(this); but, it's not working. What's the correct logic to get updated content in div. Thanks. Code: function deletePoll(postId){ $.ajax({ type: "POST", url: "../internal_request/ir_display_polls.php", data: { postId: postId }, success: function(result) { location.reload(); //$("#divSettings").html(this); } }); }

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  • How do I Reload Ajax Call Parameters without Reloading the webpage

    - by Snowright
    I'm working with Extjs 2.2.1 with Alfresco 3.2 enterprise. I would like to update the ticket that handles authentication to the alfresco server on components that have been loaded during login. This ticket expires after a set time and this is why I will need to update the ticket. Options that do not seem viable for me(but please let me know if I'm wrong): Reload the components to reload the call parameters - I can't do this because it resets whatever the user was previously working on (ie. Tree panel gets reloaded, grid filters reset, etc). The actual webpage never reloads as everything uses ajax calls to update things on the page. Create a global variable that stores the ticket and attach it as a call parameter with any ajax calls - Any components that were loaded during login will still use the original ticket to make calls to the server.

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  • JQUERY ajax passing null value from MVC View to Controller

    - by Piyush Sardana
    hi guys i'm posting some data to controller using jquery ajax, but i am getting null values in my controller, jQuery code is: $('#registerCompOff').click(function() { var compOff = []; $('div').each(function() { var curRow = {}; curRow.Description = $(this).find('.reason').val(); curRow.CompOffDate = $(this).find('.datefieldWithWeekends').val(); if (curRow.Description != null && curRow.CompOffDate != null) { compOff.push(curRow); } }); $.ajax({ type: 'POST', url: this.href, dataType: 'json', data: compOff }); return $('form').valid(); });? compOff is not null I have checked that... controller is: [HttpPost] public ActionResult RegisterCompOff(RegisterCompOff[] registerCompOff) { //return View(); } can you tell me where i'm going wrong?

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  • Sequencing ajax requests

    - by Scott Evernden
    I find I sometimes need to iterate some collection and make an ajax call for each element. I want each call to return before moving to the next element so that I don't blast the server with requests - which often leads to other issues. And I don't want to set async to false and freeze the browser. Usually this involves setting up some kind of iterator context that i step thru upon each success callback. I think there must be a cleaner simpler way? Does anyone have a clever design pattern for how to neatly work thru a collection making ajax calls for each item?

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  • jQuery Photo Search Results Pagination using AJAX and JSON

    - by Mark Richman
    I have a "photo search" page that needs to present search results in a 5x5 grid of photo thumbnails. I'd like to populate this grid using the JSON results of a jQuery $.ajax() call to my ASP.NET web service. Where I'm struggling is with pagination, where clicking [First][Prev][1][2][3]...[20][21][Next][Last] will call back again via ajax and repopulate the results with the appropriate images. So I need to find a solution to both the pagination control itself and the search results. Is there a jQuery plugin for this, or something I can easily adapt for my purposes?

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  • JQuery: After adding some AJAX, some of the jquery code no longer works

    - by fwaokda
    Here's a pastebin link to my entire jQuery code. [ http://pastebin.com/w57ma5Gx ] The "Thumbnails" section was working fine before I added the ajax sections. Anyone can help me with why it quit working? And if I need to I can post another question but figured I'd try it here first. Whats a better way of writing the ajax code where it executes once upon loading the page and then every time I click the $("a#next") link afterwards? Right now I just repasted the code outside of the next link and that works, but seems silly to have the same code in two different places like that. Thanks!

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  • Get html that is generated via AJAX in C# webclient

    - by WebDevHobo
    I often go to a site to look stuff up. I thought to myself: "Hold on. I can program. Why am I going to this site manually when I can write a piece of software that does it for me?". And so I started. I'm using C#, so I found WebClient and Uri. I've managed to get the source code for the site, yet the problem occurred that the specific data I'm looking for is generated via AJAX, after the source code has loaded. So that's my problem. How can I get that code, if it needs to be requested via an AJAX call first?

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  • jqgrid modify data returned from ajax call before display in table

    - by user954211
    I have to display some data that I receive from the server as json object like this {"rowndx":"0","rows":"25","rowstotal":"100","rowsdata":[ ["00","DEVICE001","T0_IHOME","1","***","1","10"], ["01","DEVICE002","NO_DEVICE","1","***","1","10"], ["02","DEVICE003","NO_DEVICE","0","***","1","10"], ..... Before displaying the received data in a table I would like to make changes where necessary adding units to the numbers or replacing the numbers with words (eg 0 -OFF 1- ON) To do this I have associated at the ajax option "success" my encoding function. In this case, however, remains always visible the message "Loading ..." and no other action is permitted. I moved my re-encoding procedure to the "complete" ajax option and this time it seems to work. But I did not understand what was my mistake and I do not know if my procedure can work. This is my table ajax configuration url : "devtbl.json", mtype : "POST", datatype : "json", postData : ...... ajaxGridOptions: { type : 'post', contentType: 'application/json', async : false, complete : DEVparse_serverdata, error : function() { alert('Something bad happened. Stopping');}, }, jsonReader : { root : "tablerows", page : "currentpage", total : "totalpages", records : "totalrecords", cell : "", id : "0", userdata : "userdata", repeatitems : true }, and my coding function function DEVparse_serverdata(js , textStatus) { var jsontablereply = {} ; var rowsxpage_int = parseInt(UB.rowsxpage.DEVtable) ; var jsonreply = jQuery.parseJSON(js.responseText) ; jsontablereply.currentpage = "" + (1 + (parseInt(jsonreply.rowndx) / rowsxpage_int)); jsontablereply.totalpages = "" + parseInt((parseInt(jsonreply.rowstotal) + (rowsxpage_int-1)) / rowsxpage_int) ; jsontablereply.totalrecords = jsonreply.rowstotal; jsontablereply.tablerows = [] ; $.each(jsonreply.rowsdata, function(ndx, row) { var rowarray = [] ; rowarray[0] = row[0] ; rowarray[1] = row[1] ; rowarray[2] = row[2] ; rowarray[3] = row[3] ; rowarray[4] = row[4] ; switch (row[2]) { case "NO_DEVICE": rowarray[5] = "***" ; break ; case "T0_IHOME": rowarray[5] = "T=" + row[5] + "°C" ; break ; } jsontablereply.tablerows[ndx] = rowarray ; }) ; // each jQuery("#DEVtbl")[0].addJSONData(jsontablereply); } (I am a beginner with Jquery my coding style is poor)

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  • jquery, ajax, load post result to div

    - by mike
    Hello, I have a form that I need to post and show the result in a div. I'm not having any problems making the ajax call but I can't seem to figure out how to load the result to a div. I have tried: $.ajax({ type: 'POST', data: $('#someForm').serialize(), url: 'http://somedomain.com/my/url', success: function(data) { $('#someDiv').load(data); } }); but it does not seem to work properly. I'm nit sure if this should even work but the result is the the page i'm posting from being loaded into the div and not the url I'm posting to. Any help would be great! Thanks!

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  • Ajax response seems to be getting lost

    - by Ringo Blancke
    I'm using the ddslick jquery dropdown plugin in conjunction with my Rails app. In view1, I have $('#challenges_dropdown').ddslick({ <snipped> onSelected: function (data) { $.ajax({ url: "/load_data", type: "GET", data: {"id": data.selectedData.value} }); } }); I.e., I make a call to my controller to load_data. The controller receives this correctly and then at the end, makes a call to render a separate view render "data" This view contains a script snippet that needs to run in order to update some elements of my original view. For some reason, this script snippet is just not running. I'm very confused. When I use a regular link with data-remote="true", then the whole process works perfectly. However, when I make an AJAX call, it fails. What's going on?? Thanks! Ringo

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  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

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  • $.ajax is not working

    - by Geetha
    Hi All, In my web page there is a textbox to get the scanned barcode value. Once we scan the barcode it has to get details from the database. I am creating the change event for the textbox. Problem: $.ajax is not working. Code: var target = $('#txtBarcode'), val = target.val(); target.change(monitor()); function monitor() { var xx = $('#txtBarcode').val(); $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", data: "{}", url: "HomePage.aspx/SearchProduct", dataType: "json", success: function(data) { alert("Success!!!"); } }); }

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  • Using JQuery Lightbox within AJAX loaded content

    - by James
    Hey. So this is probably a very noob problem but I'm not good enough to fix it. Basically... I have a gallery that I am loading into the page via AJAX. It looks simply like this: <div id="gallery"> <a href="Image1.jpg"><img src="Image1Thumb.jpg" /></a> <a href="Image2.jpg" title=""><img src="Image2Thumb.jpg" /></a> </div> But because it's being loaded in as AJAX content, JQuery/Lightbox is not working and I've no idea how can I get the script to run/recognise this newly loaded content. Thanks! [Note: The JQuery Lightbox I am using.]

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  • IE not triggering jQuery Ajax success

    - by dayosuperstar
    Hello all, I'm working on a script to load some images async using jQuery. Here is a code snippet of the function that loads the images - try{ for(img in imgsArray){ $.ajax({ async: false, type: "get", url:imgsArray[img], success:function(imgFile){ alert("success"); //do something useful }, error:function(XMLHttpRequest,status,error){ //do nothing } });//ajax } } catch(e){ //oops } I have tested this in Firefox, Webkit (Safari,Chrome) and it works. The images are in a folder on the server and I'm using jQuery 1.3. any ideas? Much appreciated.

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  • jquery $.ajax call succeeds but returns nothing. (jsonp)

    - by Shawn
    $(document).ready(function() { $('#button').click(function() { try { var json = $.ajax({url : 'http://www.example.com/experimental/service.php', type : 'jsonp', success : function() {alert('success')}}); alert(json); } catch(err) { alert(err.description) } var sjson = JSON.stringify(json); $('#display').html(sjson); }) }) After a button is pressed I get an alert message that says "success" and also one that says undefined, referring to the fact that nothing was returned from the ajax call. I checked the firebug 'net' tab and indeed i get a succesful response from the server of "jsonp1272724228884( {} );" Any ideas?

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  • Jquery ajax and php die()

    - by BizMark
    Hi, I have an IE problem. I am using the jquery ajax method to call a php script. The php script just calls die(). In firefox, the error message is displayed, but in IE the success message is displayed without any data. I would prefer the error function to be called. Is there any way to fix this? I'm guessing my javascript code needs change somehow. Thanks! <?php die() ?> $.ajax({ url: "phps/php.php?id="+the_id, dataType: "json", error: function(){ alert('error'); }, success: function(data){ alert("SUCCESS"); } });

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  • Show AJAX content after images have loaded

    - by Ben4Himv
    I am developing my own lightbox kind of jquery plugin. Everything works but I want to hide the loaded content until the images have loaded in the browser from the AJAX call. I found a similar post and I am using the following script but the setTimeout function is what reveals the content and not the .load function. Am I trying to achieve the impossible? $.ajax({ url: 'meet/'+ pLoad + '.html', success: function(data) { var imageCount = $(data).filter('img').length; var imagesLoaded = 0; $(data).hide() .appendTo('#zoom_inner') .filter('img') .load( function() { ++imagesLoaded; if (imagesLoaded >= imageCount) { $('#zoom_inner').children().show(); } }); setTimeout( function() { $('#zoom_inner').children().show() }, 5000 ); } });

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  • using ajax url to call function

    - by Steven Vanerp
    Hopefully I can ask this correctly cuz I know what I want it to do but can't seem to find any answers from searching. I have a func.php page where I have all my functions and I want ajax to use one function from that page. func.php function toptable() { echo"something happens in here"; } index.php <?php include 'func.php'; ?> <script type="text/javascript"> function check_username() { uname=document.getElementById("username").value; var params = "user_id="+uname; var url = "topoftable()"; $.ajax({ type: 'POST', url: url, dataType: 'html', data: params, beforeSend: function() { document.getElementById("right").innerHTML= 'checking' ; }, complete: function() { }, success: function(html) { document.getElementById("right").innerHTML= html ; } }); } </script> Make sense?

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  • Download content of the page using ajax jquery

    - by niao
    Greetings, how can I download some page content using ajax and jquery: I am doing something like that (2 versions inside one script): $("p").click(function() { $('#result').load('http://google.com'); $.ajax({ url='www.google.com', success: function(data) { $("result").html(data); alert('Load was performed.'); var url = 'www.wp.pl'; $('div#result').load(url); //var content = $.load(url); //alert(content); //$("#result").html("test"); } }); }); but it does not return any content

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