Search Results

Search found 6796 results on 272 pages for 'cakephp forms'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 94/272 | < Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101  | Next Page >

  • Find value of selected item in Drop down menu.

    - by Ozaki
    I have a drop down menu in an ASPX page along the lines of: <form> <select name="cars"> <option value="volvo">Volvo</option> <option value="saab">Saab</option> <option value="fiat" selected="selected">Fiat</option> <option value="audi">Audi</option> </select> </form> That is dynamically generated from another controller (value and label). After the user selects one of the options I need to find out what the selected value/label (will be the same) is so I can hit an update button and retrieve the data on that option. What would be the easiest way to find out the value of the user "selected" option?

    Read the article

  • Resize form based on if subform visible

    - by dmr
    I have a form with a subform on it. If subform contains no records, it's visible property is false. In that case, I'd like the outer form to shrink so that there isn't a big empty space where the subform was. The long way to do this would be by setting the position for all the controls on the form based on whether the subform is visible. However, is there an easier way to do this (maybe with the can grow/ can shrink property)?

    Read the article

  • Problem Passing Variable to Submit Form in Firefox

    - by George
    In the following example, I have a link that sends a variable to a function which checks if the variable is true and, if so, submits a form on the page. This has been tested and works in IE, Safari, and Chrome, but not Firefox. Trying to figure out what's wrong in Firefox. The function which checks 'action' and then submits form 'login' : function submit(action) { if (action == "submit") { document.login.submit(); } } Link to pass action variable and submit form: <a href="javascript:submit('submit');">SEND FORM</a> When I remove the check and just have the following, it works fine in Firefox: function submit() { document.login.submit(); } <a href="javascript:submit();">SEND FORM</a>

    Read the article

  • Using hash to check if page with $_POST values was refreshed

    - by Dieseltime
    When posting a form to the same PHP page, what is the correct method to find if the page was accidentally refreshed instead of submitted again? Here's what I'm using right now: $tmp = implode('',$_POST); $myHash = md5($tmp); if(isset($_SESSION["myHash"]) && $_SESSION["myHash"] == $myHash) { header("Location: index.php"); // page refreshed, send user somewhere else die(); } else { $_SESSION["myHash"] = $myHash; } // continue processing... Is there anything wrong with this solution?

    Read the article

  • PHP OOP Design Patterns: Should I Create two seperate classes for registration and form validation?

    - by Joshua Poshua
    So here's my problem: I have two types of registration, registration A and registration B, each will have some of the same fields and some different fields. I was going to create abstract class registration and both A and B would have their own classes that extend from registration. My question is, should I create a seperate Validation class with seperate A and B validation classes that extend? or is there a better pattern to use for something like this? Thanks

    Read the article

  • Problem passing variables in php form.

    - by Joshxtothe4
    I have the following php form. I am trying to make it so that when the form is loaded, the values will be assigned the appropriate check- variable. This variable will contain either "checked or "". If it contains checked, the way it is displayed with the html should cause the relevant checkbox to be checked. As it is, the variables do not seem to be being passed. When I echo out $deleted or $notice from within the submitinfo branch, they are blank. Furthermore, nothing is being inserted into the database, and I am not getting any database error. How can I check this? <?php if (isset($_GET["cmd"])) $cmd = $_GET["cmd"]; else if (isset($_POST["cmd"])) $cmd = $_POST["cmd"]; else die("Invalid URL"); if (isset($_GET["pk"])) { $pk = $_GET["pk"]; } if (isset($_POST["deleted"])) { $deleted = $_POST["deleted"]; } if (isset($_POST["notice"])) { $notice = $_POST["notice"]; } $con = mysqli_connect("localhost","user","password", "db"); if (!$con) { echo "Can't connect to MySQL Server. Errorcode: %s\n". mysqli_connect_error(); exit; } $con->set_charset("utf8"); $getformdata = $con->query("select * from STATUS where ARTICLE_NO = '$pk'"); $checkDeleted = ""; $checkNotice = ""; while ($row = mysqli_fetch_assoc($getformdata)) { $checkDeleted = $row['deleted']; $checkNotice = $row['notice']; } if($cmd=="submitinfo") { $statusQuery = "INSERT INTO STATUS VALUES (?, ?)"; if ($statusInfo = $con->prepare($statusQuery)) { $statusInfo->bind_param("ss", $deleted, $notice); $statusInfo->execute(); $statusInfo->close(); echo "true"; } else { echo "false"; } print_r($con->error); } if($cmd=="EditStatusData") { echo "<form name=\"statusForm\" action=\"test.php\" method=\"post\" enctype=\"multipart/form-data\"> <h1>Editing information for auction: ".$pk."</h1> Löschung Ebay: <input type=\"checkbox\" name=\"deleted\" value=\"checked\" ".$checkDeleted." /> <br /> Abmahnung: <input type=\"checkbox\" name=\"notice\" value=\"checked\" ".$checkNotice." /> <br /> <input type=\"hidden\" name=\"cmd\" value=\"submitinfo\" /> <input name=\"Submit\" type=\"submit\" value=\"submit\" /> </form>"; } else { print_r($con->error); }

    Read the article

  • Mysql query trouble: uploading

    - by Jakub Zak
    I'm trying for last hour solve this problem. I have a long form and I'm trying to upload info into mysql database. Into table I made. This is the mysql query I'm using: mysql_query("INSERT INTO `users_temp`(`first_name`, `surname`, `birthday`, `nationality`, `email`, `mobile`, `landline`, `address`, `town`, `post_code`, `country`, `password`, `code_conf`) VALUES ([$f_name],[$s_name],[$bday],[$nationality],[$email],[$mobile],[$landline],[$address],[$town],[$post_code],[$country],[$pass],[$conf_code])"); If anyone see any problem why it doesn't work pls let me know. Thank you...

    Read the article

  • How do I protect Dynamic data pages using ASP.NET Authentication?

    - by ProfK
    I have a site where most of my pages are arranged in business area folders, e.g. Activations, Outdoors, Branding. Each folder has a small web.config that protects the contents against access by people without a role for that business area. However, basic admin for most business areas is done via Dynamic Data pages. These are only basically protected by not appearing in the menu unless the user has the correct role, but they are still accessible directly via URL, because of the {table}/{Action} routing used by Dynamic Data. What can I do to protect these pages against direct access?

    Read the article

  • Rails - Help scoring an online quiz in RoR

    - by ChrisWesAllen
    I'm trying to grade a quiz application I would like to make. I have a questions model with and ask(the actual question), 4 choices(a-d), and a correct answer(string). In the view I have the 4 question being diplayed then the correct answer choice (This is just a test for functionality) and then I created a text_field to accept the users answer choice and a button to refresh the index action which has the scoring logic, for now.. --Do I need to put the text_field within a form_tag? <p>1. <%= h @question.q1 %></p> <p>2. <%= h @question.q2 %></p> <p>3. <%= h @question.q3 %></p> <p>4. <%= h @question.q4 %></p> <p>Answer: <%= h @question.correct %></p> <%= text_field_tag :choice, params[:choice] %> <%= button_to "Grade", {:controller => 'site', :action => "index"} %> <p> <%= @answer %></p> Heres the index controller action def index @question = Question.find(1) if @question.correct == params[:choice] @answer = 'right' else @answer = 'wrong' end end Its not really working. The textfield is supposed to take a letter choice like 'a' or 'c' and compare it with the correct answer in the database. I would love this to work by radiobuttons, but I'm a newbie to rails so I thought I'd take baby steps. So if anyone can help me with how to fix this by string, or preferably by radiobuttons, I'd really appreciate it.

    Read the article

  • Get the last checked checkboxes...

    - by Sara
    Hi everyone, I'm not sure how to accomplish this issue which has been confusing me for a few days. I have a form that updates a user record in MySQL when a checkbox is checked. Now, this is how my form does this: if (isset($_POST['Update'])) { $paymentr = $_POST['paymentr']; //put checkboxes array into variable $paymentr2 = implode(', ', $paymentr); //implode array for mysql $query = "UPDATE transactions SET paymentreceived=NULL"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentdate='0000-00-00'"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentreceived='Yes' WHERE id IN ($paymentr2)"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentdate=NOW() WHERE id IN ($paymentr2)"; $result = mysql_query($query); foreach ($paymentr as $v) { //should collect last updated records and put them into variable for emailing. $query = "SELECT id, refid, affid FROM transactions WHERE id = '$v'"; $result = mysql_query($query) or die("Query Failed: ".mysql_errno()." - ".mysql_error()."<BR>\n$query<BR>\n"); $trans = mysql_fetch_array($result, MYSQL_ASSOC); $transactions .= '<br>User ID:'.$trans['id'].' -- '.$trans['refid'].' -- '.$trans['affid'].'<br>'; } } Unfortunately, it then updates ALL the user records with the latest date which is not what I want it to do. The alternative I thought of was, via Javascript, giving the checkbox a value that would be dynamically updated when the user selected it. Then, only THOSE checkboxes would be put into the array. Is this possible? Is there a better solution? I'm not even sure I could wrap my brain around how to do that WITH Javascript. Does the answer perhaps lie in how my mysql code is written? Thanks - I sincerely appreciate it!!!

    Read the article

  • PHP SQL Form Insert

    - by Prateek Sachan
    I've developed a form that inserts many things into the database. But somehow, when the page is filled up; it inserts only the user_password that too of the database admin. here is the code. Any help would be great. Invalid Name: We want names with more than 3 letters. Invalid E-mail: Type a valid e-mail please. Passwords are invalid: Passwords doesnt match or are invalid! Please enter your contact number. Please enter your age Congratulations! All fields are OK ;)

    Read the article

  • replace values in form.data when form fails validation

    - by John
    Hi I have a form field which requires a json object as its value when it is rendered. When the form is submitted it returns a comma seperated string of ids as its value (not a json string). however if the form does not validate i want to turn this string of ids back into a json string so it will display properly (is uses jquery to render the json object correctly). how would i do this? I was thinking of overwriting the form.clean method but when I tried to change self.data['fieldname'] I got the error 'This QueryDict instance is immutable' and when i tried to change self.cleaned_data['fieldname'] it didn't make a difference to the value of the field. Thanks

    Read the article

  • My form submit button is not showing correctly

    - by JackR
    I have created an form that submits the contents to email. I have used the exact same coding in many other websites, but for my new website http://www.peterevansfuneraldirectors.co.uk/contact-us.html the submit button is just a grey square with text, rather than the usual button. Also the hand doesn't come up on hover. My form code is... <form action="php/FormToEmail.php" method="post" name="ContactForm" id="ContactForm" onsubmit="MM_validateForm('name','','R','email','','RisEmail','message subject','','R','message','','R');return document.MM_returnValue" > <div class="form-text"> <b>Name<span class="purple">*</span></b><br /> <input name="name" type="text" id="name" size="35" style="height:23px; background-color:#FFF; color:#000; border: 1px solid #CCC;" /> </div><br /> <div class="form-text"> <b>Email<span class="purple">*</span></b><br /> <input name="email" type="text" id="email" size="35" style="height:23px; background-color:#FFF; color:#000; border: 1px solid #CCC;" /> </div><br /> <div class="form-text"> <b>Message Subject<span class="purple">*</span></b><br /> <input name="message subject" type="text" id="message subject" size="35" style="height:23px; background-color:#FFF; color:#000; border: 1px solid #CCC;" /> </div><br /> <div class="form-text"> <b>Message<span class="purple">*</span></b><br /> <textarea name="message" type="text" id="message" rows="8" cols="55" style="background-color:#FFF; color:#000; border: 1px solid #CCC;" ></textarea> </div><br /> <div class="submit-button"> <input type="submit" name="submit" value="Submit" /> </div> </form> Thanks in advance! Jack.

    Read the article

  • How to keep PayPal variables secure

    - by dclowd9901
    I'm trying to link my 3rd party shopping cart to PayPal, and in the process I'm finding that my variables are extremely exposed, such that, if someone uses, say, Firebug, to manipulate the values of my variables, they can change the cost of the items in the transaction. I'm very new to online carts and shopping, so my question is how do I keep this layer of exposure away from users and secure for the website?

    Read the article

  • Aligning inputs on bootstrap using the Fluid Grid System

    - by sguha
    I am creating a form that requires the user to input their name and email address. The first line of the form has two inputs side by side for each part of the name and the 2nd line has one input for the email address that should be the same width as the first line combined. I'm trying to use the fluid grid system but can't line up the 2nd row with the first. <form action="/subscriptions" method="post"> <fieldset> <div class="control-group"> <label class="control-label" for="name">Name</label> <div class="controls row-fluid"> <input class="span2" id="first_name" name="first_name" placeholder="First" required="required" type="text"> <input class="span2" id="last_name" name="last_name" placeholder="Last" required="required" type="text"> </div> </div> <div class="control-group"> <label class="control-label" for="email">Email</label> <div class="controls row-fluid"> <input class="span4" id="email" name="email" type="email"> </div> </div> </fieldset> </form>? http://jsfiddle.net/sguha095/v4amX/

    Read the article

  • What is the recommended way to handle different user roles in a C# application?

    - by Sergio Tapia
    I'm going to make a small application for a business that will be used locally for scanning, and storing documents in a database located on the local machine or on a machine located in the same LAN. I could create a table called Users with username and password and according to the usertype ID show a form, or another form. But I'm more interested in the recommended approach by seasoned programmers. Any advice?

    Read the article

  • JS Display Content based on Dropdown User input

    - by Thomas
    I am working on a search box that displays different options based on a users selection via dropdown box. Basically I need a really clean, light-weight method for switching out different divs without reloading the page. Im new to JS, but I know enough that there should be some really simple way of setting the display property using JS - Im just not totally sure how to go about it. Any help would be really appreciated, thanks.

    Read the article

  • Loop throught form inputs

    - by Victor
    I have a form with lots of inputs. I want to get each id and value and then put them in $.load method. I tried this: $("#form input").each(function() { var name = $(this).attr("id"); var value = $(this).attr("value"); $.extend(params, { name, value }); }); and then use $.load("script.php", params); But obviously it doesn't work. In params I have only one element "name". And I'm not sure I should use extend method too.

    Read the article

  • Google App Engine django model form does not pick up BlobProperty

    - by Wes
    I have the following model: class Image(db.Model): auction = db.ReferenceProperty(Auction) image = db.BlobProperty() thumb = db.BlobProperty() caption = db.StringProperty() item_to_tag = db.StringProperty() And the following form: class ImageForm(djangoforms.ModelForm): class Meta: model = Image When I call ImageForm(), only the non-Blob fields are created, like this: <tr><th><label for="id_auction">Auction:</label></th><td><select name="auction" id="id_auction"> <option value="" selected="selected">---------</option> <option value="ahRoYXJ0bWFuYXVjdGlvbmVlcmluZ3INCxIHQXVjdGlvbhgKDA">2010-06-19 11:00:00</option> </select></td></tr> <tr><th><label for="id_caption">Caption:</label></th><td><input type="text" name="caption" id="id_caption" /></td></tr> <tr><th><label for="id_item_to_tag">Item to tag:</label></th><td><input type="text" name="item_to_tag" id="id_item_to_tag" /></td></tr> I want the Blob fields to be included in the form as well (as file inputs). What am I doing wrong?

    Read the article

  • IsAuthenticated is false!

    - by Naor
    This is how I login ('user' holds the data of the user): HttpResponse Response = HttpContext.Current.Response; HttpRequest Request = HttpContext.Current.Request; FormsAuthenticationTicket ticket = new FormsAuthenticationTicket(1, user.UserId.ToString(), DateTime.Now, DateTime.Now.AddHours(12), false, UserResolver.Serialize(user)); HttpCookie cookie = new HttpCookie(FormsAuthentication.FormsCookieName, FormsAuthentication.Encrypt(ticket)); cookie.Path = FormsAuthentication.FormsCookiePath; Response.Cookies.Add(cookie); string redirectUrl = user.HomePage; Response.Redirect(redirectUrl); After this login I get IsAuthenticated == false. Why?? It worked for me before an hour but I don't know what is wrong now.

    Read the article

  • jQuery when div is clicked update input field issue

    - by stogdilla
    Hello, I'm rather new to jquery so this may be the issue. I have a script that outputs several divs all with different text data in them. I would like it when I click one of them that an input field's value is updated to that text currently I have: <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("a.results]").click(function() { data= this.text(); $("#updateme").val(data); }); }); </script> <p> <label>Field <input type="text" name="updateme" id="updateme"> </label> </p> <a href="#" class="results">Florida</a> <a href="#" class="results">Florida 2</a> <a href="#" class="results">Florida 3</a> How can I make it so that whatever link is clicked that is the data that gets updated into the input's value? I can get it to take one or I can script out different cases of each changing the class name but I think there has to be a way where it references whatever link is being clicked instead of what it's currently doing. Thanks in advance!

    Read the article

  • JQuery Autocomplete - Stop mouseover+Return submitting data

    - by ILT
    I'm using JQuery Autocomplete (bassistance) and have run into a problem. If the mouse rolls over one of the autocomplete suggestions and the user hits the return key (rather than clicking to make selection), the form is submitted and goes to whatever link was rolled over at the time. This is a problem as people click in the textbox, and when typing their search, leave the pointer where the autocomplete popup appears. So when they hit enter, it doesn't do the search for whatever they typed in the box but whatever was highlighted in the autocomplete suggestions. Is there a way to stop this? Using Google as the functionality I'm after... So just to clarify - I want selections via mouse and keyboard to go to the same place, but if the UP or DOWN arrow has not been pressed (user not selected an autocomplete option via the keyword), dont go to the URL specified in the autosuggest - instead submit the form (traditional method without JQuery) based on what has been typed in the textbox. I hope I'm explaining this clearly? :S

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101  | Next Page >