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  • Improved technique to store a filename in a variable?

    - by SDGuero
    Greetings, I need to store the filename of a log into a variable so my script can perform some checks on the daily log files. These logs always have a different name because they have a timestamp in the name. Currently I'm using a hodge podged method that pipes an ls command to sed, sort, cut, and tail in order to get the name out. CRON_LOG=$(ls -1 $LOGS_DIR/fetch_cron_{true,false}_$CRON_DATE*.log 2> /dev/null | sed 's/^[^0-9][^0-9]*\([0-9][0-9]*\).*/\1 &/' | sort -n | cut -d ' ' -f2- | tail -1 ) UPDATE: $CRON_DATE is supplied as an argument to the script. It is the date (to the day) that the log was created on. Sometimes multiple logs will exist for the same day so I want this to get the most recent one. A typical filename is fetch_cron_false_031810090452.log I'm pretty sure I kluged this together from some stuff I found google a few months ago. it works now but I'm not really happy with the technique. I have some ideas about how to do this better but I have had great success on this site before and thought it might be best to refer to the stackoverflow gods first. All answers are greatly appreciated. Thanks, Ryan

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  • Shell Sort problem

    - by user191603
    Show the result of running Shell Sort on the input 9,8,7,6,5,4,3,2,1 using increments { 1,3,7 }. I have done this part. the result is: 9 8 7 6 5 4 3 2 1 (original) 2 1 7 6 5 4 3 9 8 ( 7-sort ) 2 1 4 3 5 7 6 9 8 ( 3-sort ) 1 2 3 4 5 6 7 8 9 ( 1-sort ) Then the question requires me to determine the running time of Shell Sort using Shell's increments of N/2, N/4, ..., 1 for sorted input. I am not quite sure how to answer the second question as I don't understand the requirement of this question. So, would anyone give some hints to let me finish this question? Thank you for your help first!

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  • Splitting values into groups evenly

    - by Paul Knopf
    Let me try to explain the situation the best I can. Lets say I have 3 values 1, 2, 3 I tell an algorithm to split this values into x columns. Lets say x = 2 for clarification. The algorithm determines that the group of values is best put into two columns the following way. 1st column 2nd column --------------------------- 1 3 2 Each column has an even number (totals, not literals) value. Now lets say I have the following values 7, 8, 3, 1, 4 I tell the algorithm that I want the values split into 3 columns. The algorithm now tells me that the following is the best fit. 1st column 2nd column 3rd column 8 7 3 1 4 Notice how the columns arent quiet even, but it is as close as it can get. A little over and a little under is considered ok, as long as the list is AS CLOSE TO EVEN AS IT CAN BE. Anybody got any suggestions? Know any good methods of doing this?

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  • How can I get running totals of integer values from a SortedDictionary?

    - by user578083
    SortedDictionary<int, string> typeDictionary = new SortedDictionary<int, string>(); SortedDictionary<int, int> lengthDictionary = new SortedDictionary<int, int>(); lengthDictionary has values in key value pair as follows: <1,20> <2,8> <3,10> <4,5> i want LINQ query which will return me new list like as follows <1,20> <2,20+8=28> // 20 from key 1 <3,28+10=38> // 28 from key 2 <4,38+5=43> // 38 from key 3 Result should like this: <1,20> <2,28> <3,38> <4,43>

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  • how to sort an existing table in greasemonkey ?

    - by user570512
    i'm writing a greasemonkey user.js for a page with a table in it. (table is 100 rows by 18 columns.) now what i want to do is to make it sortable on column. and also have it run in both chrome and firefox. all searches for answers sofar resulted in suggestions to use jquery/dojo or something alike. can i be done without any external code? after all it's just a matter of replacing the row's in a different order, right? or is that a silly thing to say? the thing is that i'm already using dojo for some query needs but since i want it to run in both firefox and chrome, i just copy paste the whole dojo thing in my script.. also, most of the solutions i found sofar seem to be more for use when building a table. not for altering an existing one. any help is appreciated.

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  • Mysql select most frequent and sort alphabetically

    - by user2605793
    I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

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  • More than one unique key for HashMap problem (Java)

    - by Alex Cheng
    This question is a continuation of this thread: In short: To solve my problem, I want to use Map<Set<String>, String>. However, after I sort my data entries in Excel, remove the unnecessary parameters, and the following came out: flow content ==> content content flow content ==> content depth distance flow content ==> content depth within flow content ==> content depth within distance flow content ==> content within flow content ==> content within distance I have more than one unique key for the hashmap if that is the case. How do I go around this... anyone have any idea? I was thinking of maybe Map<Set <String>, List <String>> so that I can do something like: Set <flow content>, List <'content content','content depth distance','content depth within ', ..., 'content within distance'> But because I am parsing the entries line by line I can't figure out the way how to store values of the same repeated keys (flow content) into the same list and add it to the map. Anyone have a rough logic on how can this be done in Java? Thanks in advance.

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  • How to let the UITable sorted by number?

    - by Tattat
    I loaded a plist from the UITable, but there is something wrong. my plist file is some data like that: 3 3uyyhuhu34 ..... 5 5uyyhuhu34 ..... 11 11uyyhuhu34 ..... I found that the list is sorted from 11, then 3, after that is 5. But I want to sorted from 3, 5 to 11. What can I do to change the behaviors? thx

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  • How do i sort by: most viewed, most commented, most popular, best rating, etc?

    - by MrRioku
    Pretty basic question.. I kno.., I just don't know how its done. I see it everywhere. I want to be able to sort out my content in my websites by most viewed, most commented, most popular, best rating, etc...with a drop down list, check box, etc... but I don't know how "sort by" works? Which scripting language should it be written in? Javascript? PHP? Can it be done with XML? Do I have to have a database set up like MySQL? Is there a good tutorial anywhere that explains it? I need to be explained the exact process of how it works. As you can see I really need direction.. Your help is much appreciated :D

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  • What is a better way to sort by a 5 star rating?

    - by Vizjerai
    I'm trying to sort a bunch of products by customer ratings using a 5 star system. The site I'm setting this up for does not have a lot of ratings and continue to add new products so it will usually have a few products with a low number of ratings. I tried using average star rating but that algorithm fails when there is a small number of ratings. Example a product that has 3x 5 star ratings would show up better than a product that has 100x 5 star ratings and 2x 2 star ratings. Shouldn't the second product show up higher because it is statistically more trustworthy because of the larger number of ratings?

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  • Algorithm of JavaScript "sort()" Function

    - by Knowledge Craving
    Recently when I was working with JavaScript "sort()" function, I found in one of the tutorials that this function does not sort the numbers properly. Instead to sort numbers, a function must be added that compares numbers, like the following code:- <script type="text/javascript"> function sortNumber(a,b) { return a - b; } var n = ["10", "5", "40", "25", "100", "1"]; document.write(n.sort(sortNumber)); </script> The output then comes as:- 1,5,10,25,40,100 Now what I didn't understand is that why is this occurring & can anybody please tell in details as to what type of algorithm is being used in this "sort()" function? This is because for any other language, I didn't find this problem where the function didn't sort the numbers correctly. Any help is greatly appreciated.

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  • Sort an object by an other one.

    - by kevinb92
    Here's the deal : I have Publication objets in my application. I also have Vote objet. I can add votes on publication. A vote is defined like this, forOrAgainst, LinkedPublication, date, author etc etc... I want to sort Publication list by number of vote. What is the best way to link them ? Should i return a hashmap ? a treeset ? How do i add votes to publication. It's kinda messy in my brain now...

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  • Sort vector<int>(n) in O(n) time using O(m) space?

    - by Adam
    I have a vector<unsigned int> vec of size n. Each element in vec is in the range [0, m], no duplicates, and I want to sort vec. Is it possible to do better than O(n log n) time if you're allowed to use O(m) space? In the average case m is much larger than n, in the worst case m == n. Ideally I want something O(n). I get the feeling that there's a bucket sort-ish way to do this: unsigned int aux[m]; aux[vec[i]] = i; Somehow extract the permutation and permute vec. I'm stuck on how to do 3. In my application m is on the order of 16k. However this sort is in the inner loops and accounts for a significant portion of my runtime.

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  • Sort List based on dynamically generated numbers in C++

    - by user367322
    I have a list of objects ("Move"'s in this case) that I want to sort based on their calculated evaluation. So, I have the List, and a bunch of numbers that are "associated" with an element in the list. I now want to sort the List elements with the first element having the lowest associated number, and the last having the highest. Once the items are order I can discard the associated number. How do I do this? This is what my code looks like (kind've): list<Move> moves = board.getLegalMoves(board.turn); for(i = moves.begin(); i != moves.end(); ++i) { //... a = max; // <-- number associated with current Move }

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  • C++ sort method

    - by qwead
    I want to sort a vector using std::sort, but my sort method is a static method of a class, and I want to call std::sort outside it, but it seems to be trouble doing it this way. On the class: static int CompareIt(void *sol1, void *sol2) { ... } std::sort call: sort(distanceList.at(q).begin(), distanceList.at(q).end(), &DistanceNodeComparator::CompareIt); Shouldn't it be possible to do this way?

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  • sort list(of string()) using a variable index into string() as key - vb.net

    - by tullynyguy
    I have a List(of String()). I have written a custom comparer (implements IComparer(of string)) to do an alphanumeric sort. Is there a way to sort the List using a given index to determine which position in the String() to sort by? In other words one time I might sort by Index = 0 and another time by Index = 3. The length of all String() in the list is the same. For reference this question is similar to Sort List<String[]> except I am using VB.net and that question is hardwired to Index=0.

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  • Need to sync two lists with atrribute time, but times aren't equal

    - by virgula24
    I gonna try to describe my problem the best i can. I have two lists, one with audio frames and other with color frames (not relevant). Both of them have timestamps, they were captured at the same moment but at different instants. So, i have like this: index COLOR AUDIO 0 841 846 1 873 897 2 905 948 3 940 1000 the frames start at high numbers because they were captured and then trimmed to specific parts, but im shot, frame 0 is synced with only 5ms apart(timestamp in ms). On every case i have, the audio frames count is less than the color count. I need to make them have the same count. The stating frames may be coloraudio, color

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  • How to sort a hash by value in descending order and output a hash in ruby?

    - by tipsywacky
    output.sort_by {|k, v| v}.reverse and for keys h = {"a"=>1, "c"=>3, "b"=>2, "d"=>4} => {"a"=>1, "c"=>3, "b"=>2, "d"=>4} Hash[h.sort] Right now I have these two. But I'm trying to sort hash in descending order by value so that it will return => {"d"=>4, "c"=>3, "b"=>2, "a"=>1 } Thanks in advance. Edit: let me post the whole code. def count_words(str) # YOUR CODE HERE output = Hash.new(0) sentence = str.gsub(/,/, "").gsub(/'/,"").gsub(/-/, "").downcase words = sentence.split() words.each do |item| output[item] += 1 end puts Hash[output.sort_by{ |_, v| -v }] return Hash[output.sort_by{|k, v| v}.reverse] end

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  • Drupal: Exposing a module's data to Views2 using its API

    - by Sepehr Lajevardi
    I'm forking the filefield_stats module to provide it with the ability of exposing data into the Views module via the API. The filefield_stats module db table schema is as follow: <?php function filefield_stats_schema() { $schema['filefield_stats'] = array( 'fields' => array( 'fid' => array('type' => 'int', 'unsigned' => TRUE, 'not null' => TRUE, 'description' => 'Primary Key: the {files}.fid'), 'vid' => array('type' => 'int', 'unsigned' => TRUE, 'not null' => TRUE, 'description' => 'Primary Key: the {node}.vid'), 'uid' => array('type' => 'int', 'unsigned' => TRUE, 'not null' => TRUE, 'description' => 'The {users}.uid of the downloader'), 'timestamp' => array('type' => 'int', 'unsigned' => TRUE, 'not null' => TRUE, 'description' => 'The timestamp of the download'), 'hostname' => array('type' => 'varchar', 'length' => 128, 'not null' => TRUE, 'default' => '', 'description' => 'The hostname downloading the file (usually IP)'), 'referer' => array('type' => 'text', 'not null' => FALSE, 'description' => 'Referer for the download'), ), 'indexes' => array('fid_vid' => array('fid', 'vid')), ); return $schema; } ?> Well, so I implemented the hook_views_api() in filefield_stats.module & added a filefield_stats.views.inc file in the module's root directory, here it is: <?php // $Id$ /** * @file * Provide the ability of exposing data to Views2, for filefield_stats module. */ function filefield_stats_views_data() { $data = array(); $data['filefield_stats']['table']['group'] = t('FilefieldStats'); // Referencing the {node_revisions} table. $data['filefield_stats']['table']['join'] = array( 'node_revisions' => array( 'left_field' => 'vid', 'field' => 'vid', ), /*'files' => array( 'left_field' => 'fid', 'field' => 'fid', ), 'users' => array( 'left_field' => 'uid', 'field' => 'uid', ),*/ ); // Introducing filefield_stats table fields to Views2. // vid: The node's revision ID which wrapped the downloaded file $data['filefield_stats']['vid'] = array( 'title' => t('Node revision ID'), 'help' => t('The node\'s revision ID which wrapped the downloaded file'), 'relationship' => array( 'base' => 'node_revisions', 'field' => 'vid', 'handler' => 'views_handler_relationship', 'label' => t('Node Revision Reference.'), ), ); // uid: The ID of the user who downloaded the file. $data['filefield_stats']['uid'] = array( 'title' => t('User ID'), 'help' => t('The ID of the user who downloaded the file.'), 'relationship' => array( 'base' => 'users', 'field' => 'uid', 'handler' => 'views_handler_relationship', 'label' => t('User Reference.'), ), ); // fid: The ID of the downloaded file. $data['filefield_stats']['fid'] = array( 'title' => t('File ID'), 'help' => t('The ID of the downloaded file.'), 'relationship' => array( 'base' => 'files', 'field' => 'fid', 'handler' => 'views_handler_relationship', 'label' => t('File Reference.'), ), ); // hostname: The hostname which the file has been downloaded from. $data['filefield_stats']['hostname'] = array( 'title' => t('The Hostname'), 'help' => t('The hostname which the file has been downloaded from.'), 'field' => array( 'handler' => 'views_handler_field', 'click sortable' => TRUE, ), 'sort' => array( 'handler' => 'views_handler_sort', ), 'filter' => array( 'handler' => 'views_handler_filter_string', ), 'argument' => array( 'handler' => 'views_handler_argument_string', ), ); // referer: The referer address which the file download link has been triggered from. $data['filefield_stats']['referer'] = array( 'title' => t('The Referer'), 'help' => t('The referer which the file download link has been triggered from.'), 'field' => array( 'handler' => 'views_handler_field', 'click sortable' => TRUE, ), 'sort' => array( 'handler' => 'views_handler_sort', ), 'filter' => array( 'handler' => 'views_handler_filter_string', ), 'argument' => array( 'handler' => 'views_handler_argument_string', ), ); // timestamp: The time of the download. $data['filefield_stats']['timestamp'] = array( 'title' => t('Download Time'), 'help' => t('The time of the download.'), 'field' => array( 'handler' => 'views_handler_field_date', 'click sortable' => TRUE, ), 'sort' => array( 'handler' => 'views_handler_sort_date', ), 'filter' => array( 'handler' => 'views_handler_filter_date', ), ); return $data; } // filefield_stats_views_data() ?> According to the Views2 documentations this should work as a minimum, I think. But it doesn't! Also there is no error of any kind, when I come through the views UI, there's nothing about filefield_stats data. Any idea?

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  • [Ubuntu 10.04] mdadm - Can't get RAID5 Array To Start

    - by Matthew Hodgkins
    Hello, after a power failure my RAID array refuses to start. When I boot I have to sudo mdadm --assemble --force /dev/md0 /dev/sdb1 /dev/sdc1 /dev/sdd1 /dev/sde1 /dev/sdf1 /dev/sdg1 to get mdadm to notice the array. Here are the details (after I force assemble). sudo mdadm --misc --detail /dev/md0: /dev/md0: Version : 00.90 Creation Time : Sun Apr 25 01:39:25 2010 Raid Level : raid5 Used Dev Size : 1465135872 (1397.26 GiB 1500.30 GB) Raid Devices : 6 Total Devices : 6 Preferred Minor : 0 Persistence : Superblock is persistent Update Time : Thu Jun 17 23:02:38 2010 State : active, Not Started Active Devices : 6 Working Devices : 6 Failed Devices : 0 Spare Devices : 0 Layout : left-symmetric Chunk Size : 128K UUID : 44a8f730:b9bea6ea:3a28392c:12b22235 (local to host hodge-fs) Events : 0.1249691 Number Major Minor RaidDevice State 0 8 65 0 active sync /dev/sde1 1 8 81 1 active sync /dev/sdf1 2 8 97 2 active sync /dev/sdg1 3 8 49 3 active sync /dev/sdd1 4 8 33 4 active sync /dev/sdc1 5 8 17 5 active sync /dev/sdb1 mdadm.conf: # by default, scan all partitions (/proc/partitions) for MD superblocks. # alternatively, specify devices to scan, using wildcards if desired. DEVICE partitions /dev/sdb1 /dev/sdb1 # auto-create devices with Debian standard permissions CREATE owner=root group=disk mode=0660 auto=yes # automatically tag new arrays as belonging to the local system HOMEHOST <system> # definitions of existing MD arrays ARRAY /dev/md0 level=raid5 num-devices=6 UUID=44a8f730:b9bea6ea:3a28392c:12b22235 Any help would be appreciated.

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  • Move an existing RAID 5 array from Ubuntu to Gentoo

    - by Cocoabean
    I have a 64-bit Ubuntu machine with a 4-disk RAID 5 using software raid (md). I've been able to boot an Ubuntu LiveCD and recognize the array with a simple mdadm -A /dev/md0. It was easy to mount after that and nothing had to rebuild. I'm installing Gentoo on this box now (multi-boot, non-RAID root partition) and I have md auto-detect turned on in the kernel. When I boot Gentoo I get: "invalid superblock magic on sdd" for each of the drives in the array. I boot back to Ubuntu and they mount no problem. I tried copying the mdadm.conf that works in Ubuntu to Gentoo, and then ran mdadm -A /dev/md0 but it reports that there is no array named md0. I don't want to lose data (obviously) and I don't want to have to let the RAID rebuild every time I switch between OSes. Any help is appreciated. Both are using mdadm 3.1.4 Both are running 64-bit kernels. mdadm -D /dev/md0 from Ubuntu yields: http://pastebin.com/5gj2QNkV UPDATE: After rebooting I noticed that it still complains about invalid blocks, but cat /proc/mdstat shows an inactive /dev/md127 with the same disks as my raid. I want to mount it but I don't want to get stuck waiting for a rebuild or destroying it inadvertently. mdadm -D /dev/md127 Here is pastebin of mdadm -D /dev/md127 on gentoo: http://pastebin.com/gDCWn0Rn UPDATE II: dmesg output about 'invalid raid superblocks' http://paste.ubuntu.com/885471/ fdisk -l from Ubuntu, /dev/md0 does not have any partitions but I do have it mounted and accessible: http://paste.ubuntu.com/885475/

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  • Can one build a single disk RAID 1 array?

    - by Core Xii
    I have an Nvidia hardware RAID 1 array and need to reformat. But I don't have any spare storage media, so I need to get along with the 2 disks in the array. I figured I'd do as follows: Delete the array, so I have 2 separate but identical disks, A and B, with my files Put disk B aside Reformat disk A, build RAID 1 array with it, install Windows XP Put disk B back in Boot to Windows on disk A, copy my files from disk B to disk A Add disk B to the RAID 1 array, rebuild array And now I'd have a new RAID 1 array, fresh install and all my files intact (the ones I copied). Here are the parts I'm unsure about: Can I build a RAID 1 array using just one disk, then add the other one later? Can Windows on disk A see disk B and allow me to copy my files over?

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  • Move OS from RAID5 array to RAID 1 arrays

    - by Antoine
    I want to give a last boost to my old ProLiant ML350 G5 server which just needs to be reliable for a few more year only ! With a defined budget of about 1500$ (I do not have more), i plan to replace the CPU (+ adding a second one), the battery cache of my raid controller (E200i), double the RAM, and change all hard drives. I have 7 HDD (SAS 10krpm, 72Gb) + 1 spare in RAID5, and my system is all FULL (no empty tray, full disks). in my current RAID5 array, I have 2 partitions: - 1 OS partition, 20Gb - 1 data partition, 350 Gb I plan to replace these 8 disks with : - 2 x 300Gb SAS 15krpm in RAID 1 (= 1 partition for OS) - 2 x 2Tb SATA 7.2krpm in RAID 1 (= 1 partition for DATA) My biggest constraint is that I have only 01 day to upgrade my server. Therefore, I'm looking for cloning all my files (OS + data partition) to my new arrays, i.e : - the OS partition shall be cloned to the RAID1 "2x300Gb array" - the data partition shall be cloned to the RAID1 "2x2Tb array" My second problem is that I need to physically remove all the old hard drives before inserting the new ones. I'm running Windows Server 2003 R2, and even if MS support will expire soon, I cannot buy a new licence and spent time in configuration. Obviously, with 1500$, I cannot also buy a new server that I could start configuring from now ! Thought about ASR (NTBackup), but I have no floppy drive (and do not really want to invest in one !) Thought about a clonezilla clone, and read this interesting link : Windows Server 2003 - move C: partition to a new SAS disk , but i'm not so confident in using Clonezilla with RAID5. What should be the best option to quickly and easily (if possible!) "copy/paste" my OS (so no need to reinstall and reconfigure all) and DATA / programs / services, etc... ? Thanks for your comments

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