Search Results

Search found 8411 results on 337 pages for 'django shell'.

Page 97/337 | < Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >

  • Grub: Legacy 'ask' parameter no longer supported

    - by leeand00
    I'm trying to change the resolution on my base shell (the Ctrl+Alt+1) shell in Debian so that it supports my ViewSonic monitor. The shell appears really fuzzy when it is displayed on my lcd monitor, but GRUB looks fine when it's displayed. In I tried changing part of the GRUB_CMDLINE_LINUX_DEFAULT to 'vga=ask', and now I get the error on booting up 'Legacy 'ask' parameter no longer supported' Has this 'vga=ask' value been changed to something else? Note, I tried setting it to 'vga=782' after finding a list of screen modes here and the shell font got real huge for a few seconds during boot up, and then switched back to it's awful fuzzy self again, when I went to use the Debian Bash shell. UPDATE Tried suggestion in this question, it works without fuzziness until the last resolution change which displays the user login to the shell.

    Read the article

  • Matching blank entries in django queryset for optional field with corresponding ones in a required

    - by gramware
    I have a django queryset in my views whose values I pack before passing to my template. There is a problem when the queryset returns none since associated values are not unpacked. the quersyet is called comments. Here is my views.py def forums(request ): post_list = list(forum.objects.filter(child='0')&forum.objects.filter(deleted='0').order_by('postDate')) user = UserProfile.objects.get(pk=request.session['_auth_user_id']) newpostform = PostForm(request.POST) deletepostform = PostDeleteForm(request.POST) DelPostFormSet = modelformset_factory(forum, exclude=('child','postSubject','postBody','postPoster','postDate','childParentId')) readform = ReadForumForm(request.POST) comments =list( forum.objects.filter(deleted='0').filter(child='1').order_by('childParentId').values('childParentId').annotate(y=Count('childParentId'))) if request.user.is_staff== True : staff = 1 else: staff = 0 staffis = 1 if newpostform.is_valid(): topic = request.POST['postSubject'] poster = request.POST['postPoster'] newpostform.save() return HttpResponseRedirect('/forums') else: newpostform = PostForm(initial = {'postPoster':user.id}) if request.GET: form = SearchForm(request.GET) if form.is_valid(): query = form.cleaned_data['query'] post_list = list((forum.objects.filter(child='0')&forum.objects.filter(deleted='0')&forum.objects.filter(Q(postSubject__icontains=query)|Q(postBody__icontains=query)|Q(postDate__icontains=query)))or(forum.objects.filter(deleted='0')&forum.objects.filter(Q(postSubject__icontains=query)|Q(postBody__icontains=query)|Q(postDate__icontains=query)).values('childParentId'))) if request.method == 'POST': delpostformset = DelPostFormSet(request.POST) if delpostformset.is_valid(): delpostformset.save() return HttpResponseRedirect('/forums') else: delpostformset = DelPostFormSet(queryset=forum.objects.filter(child='0', deleted='0')) """if readform.is_valid(): user=get_object_or_404(UserProfile.objects.all()) readform.save() else: readform = ReadForumForm()""" post= zip( post_list,comments, delpostformset.forms) paginator = Paginator(post, 10) # Show 10 contacts per page # Make sure page request is an int. If not, deliver first page. try: page = int(request.GET.get('page', '1')) except ValueError: page = 1 # If page request (9999) is out of range, deliver last page of results. try: post = paginator.page(page) except (EmptyPage, InvalidPage): post = paginator.page(paginator.num_pages) return render_to_response('forum.html', {'post':post, 'newpostform': newpostform,'delpost':delpostformset, 'username':user.username, 'comments':comments, 'user':user, },context_instance = RequestContext( request )) I realised that the issue was with the comments queryset comments =list( forum.objects.filter(deleted='0').filter(child='1').order_by('childParentId').values('childParentId').annotate(y=Count('childParentId'))) which will only returns values for posts that have comments. so i now need a way to return 0 comments when a value in post-list post_list = list(forum.objects.filter(child='0')&forum.objects.filter(deleted='0').order_by('postDate')) does not have any comments (optional field). Here is my models.py class forum(models.Model): postID = models.AutoField(primary_key=True) postSubject = models.CharField(max_length=100) postBody = models.TextField() postPoster = models.ForeignKey(UserProfile) postDate = models.DateTimeField(auto_now_add=True) child = models.BooleanField() childParentId = models.ForeignKey('self',blank=True, null=True) deleted = models.BooleanField() def __unicode__(self): return u' %d' % ( self.postID)

    Read the article

  • Django : presenting a form very different from the model and with multiple field values in a Django-

    - by sebpiq
    Hi ! I'm currently doing a firewall management application for Django, here's the (simplified) model : class Port(models.Model): number = models.PositiveIntegerField(primary_key=True) application = models.CharField(max_length=16, blank=True) class Rule(models.Model): port = models.ForeignKey(Port) ip_source = models.IPAddressField() ip_mask = models.IntegerField(validators=[MaxValueValidator(32)]) machine = models.ForeignKey("vmm.machine") What I would like to do, however, is to display to the user a form for entering rules, but with a very different organization than the model : Port 80 O Not open O Everywhere O Specific addresses : --------- delete field --------- delete field + add address field Port 443 ... etc Where Not open means that there is no rule for the given port, Everywhere means that there is only ONE rule (0.0.0.0/0) for the given port, and with specific addresses, you can add as many addresses as you want (I did this with JQuery), which will make as many rules. Now I did a version completely "handmade", meaning that I create the forms entirely in my templates, set input names with a prefix, and parse all the POSTed stuff in my view (which is quite painful, and means that there's no point in using a web framework). I also have a class which aggregates the rules together to easily pre-fill the forms with the informations "not open, everywhere, ...". I'm passing a list of those to the template, therefore it acts as an interface between my model and my "handmade" form : class MachinePort(object): def __init__(self, machine, port): self.machine = machine self.port = port @property def fully_open(self): for rule in self.port.rule_set.filter(machine=self.machine): if ipaddr.IPv4Network("%s/%s" % (rule.ip_source, rule.ip_mask)) == ipaddr.IPv4Network("0.0.0.0/0"): return True else : return False @property def partly_open(self): return bool(self.port.rule_set.filter(machine=self.machine)) and not self.fully_open @property def not_open(self): return not self.partly_open and not self.fully_open But all this is rather ugly ! Do anyone of you know if there is a classy way to do this ? In particular with the form... I don't know how to have a form that can have an undefined number of fields, neither how to transform these fields into Rule objects (because all the rule fields would have to be gathered from the form), neither how to save multiple objects... Well I could try to hack into the Form class, but seems like too much work for such a special case. Is there any nice feature I'm missing ?

    Read the article

  • Django: Grouping by Dates and Servers

    - by TheLizardKing
    So I am trying to emulate google app's status page: http://www.google.com/appsstatus#hl=en but for backups for our own servers. Instead of service names on the left it'll be server names but the dates and hopefully the pagination will be there too. My models look incredibly similar to this: from django.db import models STATUS_CHOICES = ( ('UN', 'Unknown'), ('NI', 'No Issue'), ('IS', 'Issue'), ('NR', 'Not Running'), ) class Server(models.Model): name = models.CharField(max_length=32) def __unicode__(self): return self.name class Backup(models.Model): server = models.ForeignKey(Server) created = models.DateField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) status = models.CharField(max_length=2, choices=STATUS_CHOICES, default='UN') issue = models.TextField(blank=True) def __unicode__(self): return u'%s: %s' % (self.server, self.get_status_display()) My issue is that I am having a hell of a time displaying the information I need. Everyday a little after midnight a cron job will run and add a row for each server for that day, defaulting on status unknown (UN). My backups.html: {% extends "base.html" %} {% block content %} <table> <tr> <th>Name</th> {% for server in servers %} <th>{{ created }}</th> </tr> <tr> <td>{{ server.name }}</td> {% for backup in server.backup_set.all %} <td>{{ backup.get_status_display }}</td> {% endfor %} </tr> {% endfor %} </table> {% endblock content %} This actually works but I do not know how to get the dates to show. Obviously {{ created }} doesn't do anything but the servers don't have create dates. Backups do and because it's a cron job there should only be X number of rows with any particular date (depending on how many servers we are following for that day). Summary I want to create a table, X being server names, Y being dates starting at today while all the cells being the status of a backup. The above model and template should hopefully give you an idea what my thought process but I am willing to alter anything. Basically I am create a fancy excel spreadsheet.

    Read the article

  • getting Cannot identify image file when trying to create thumbnail in django

    - by Mo J. Mughrabi
    Am trying to create a thumbnail in django, am trying to build a custom class specifically to be used for generating thumbnails. As following from StringIO import StringIO from PIL import Image class Thumbnail(object): source = '' size = (50, 50) output = '' def __init__(self): pass @staticmethod def load(src): self = Thumbnail() self.source = src return self def generate(self, size=(50, 50)): if not isinstance(size, tuple): raise Exception('Thumbnail class: The size parameter must be an instance of a tuple.') self.size = size # resize properties box = self.size factor = 1 fit = True image = Image.open(self.source) # Convert to RGB if necessary if image.mode not in ('L', 'RGB'): image = image.convert('RGB') while image.size[0]/factor > 2*box[0] and image.size[1]*2/factor > 2*box[1]: factor *=2 if factor > 1: image.thumbnail((image.size[0]/factor, image.size[1]/factor), Image.NEAREST) #calculate the cropping box and get the cropped part if fit: x1 = y1 = 0 x2, y2 = image.size wRatio = 1.0 * x2/box[0] hRatio = 1.0 * y2/box[1] if hRatio > wRatio: y1 = int(y2/2-box[1]*wRatio/2) y2 = int(y2/2+box[1]*wRatio/2) else: x1 = int(x2/2-box[0]*hRatio/2) x2 = int(x2/2+box[0]*hRatio/2) image = image.crop((x1,y1,x2,y2)) #Resize the image with best quality algorithm ANTI-ALIAS image.thumbnail(box, Image.ANTIALIAS) # save image to memory temp_handle = StringIO() image.save(temp_handle, 'png') temp_handle.seek(0) self.output = temp_handle return self def get_output(self): return self.output.read() the purpose of the class is so i can use it inside different locations to generate thumbnails on the fly. The class works perfectly, I've tested it directly under a view.. I've implemented the thumbnail class inside the save method of the forms to resize the original images on saving. in my design, I have two fields for thumbnails. I was able to generate one thumbnail, if I try to generate two it crashes and I've been stuck for hours not sure whats the problem. Here is my model class Image(models.Model): article = models.ForeignKey(Article) title = models.CharField(max_length=100, null=True, blank=True) src = models.ImageField(upload_to='publication/image/') r128 = models.ImageField(upload_to='publication/image/128/', blank=True, null=True) r200 = models.ImageField(upload_to='publication/image/200/', blank=True, null=True) uploaded_at = models.DateTimeField(auto_now=True) Here is my forms class ImageForm(models.ModelForm): """ """ class Meta: model = Image fields = ('src',) def save(self, commit=True): instance = super(ImageForm, self).save(commit=True) file = Thumbnail.load(instance.src) instance.r128 = SimpleUploadedFile( instance.src.name, file.generate((128, 128)).get_output(), content_type='image/png' ) instance.r200 = SimpleUploadedFile( instance.src.name, file.generate((200, 200)).get_output(), content_type='image/png' ) if commit: instance.save() return instance the strange part is, when i remove the line which contains instance.r200 in the form save. It works fine, and it does the thumbnail and stores it successfully. Once I add the second thumbnail it fails.. Any ideas what am doing wrong here? Thanks Update: I tried earlier doing the following but I still got the same error class ImageForm(models.ModelForm): """ """ class Meta: model = Image fields = ('src',) def save(self, commit=True): instance = super(ImageForm, self).save(commit=True) instance.r128 = SimpleUploadedFile( instance.src.name, Thumbnail.load(instance.src).generate((128, 128)).get_output(), content_type='image/png' ) instance.r200 = SimpleUploadedFile( instance.src.name, Thumbnail.load(instance.src).generate((200, 200)).get_output(), content_type='image/png' ) if commit: instance.save() return instance

    Read the article

  • Does pdksh (public domain korn shell) support associative arrays?

    - by George Jempty
    I recently ran up against a wall doing some bash shell programming where an associative array would have solved my problems. I googled about features of the Korn shell and learned that it supports associative arrays, so I installed Cygwin's pdksh (public domain korn shell). However, when trying to create an associative array in the prescribed manner (typeset -A varName), I received the following errors, so I'm beginning to suspect pdksh does not support associative arrays. ./find_actions.ksh: line 2: typeset: -A: invalid option typeset: usage: typeset [-afFirtx] [-p] name[=value] ... Guess I'll be considering Perl instead, but I really wanted a good excuse to learn a dialect/language new to me

    Read the article

  • How to bundle C/C++ code with C-shell-script?

    - by eSKay
    I have a C shell script that calls two C programs - one after the another with some file handling before, in-between and afterwards. Now, as such I have three different files - one C shell script and 2 .c files. I need to give this script to other users. The problem is that I have to distribute three files - which the users must keep in the same folder and then execute the script. Is there some better way to do this? [I know I can make one C code file out of those two... but I will still be left with a shell script and a C code. Actually, the two C codes do entirely different things... so I want them to be separate]

    Read the article

  • How to bundle C code in C shell script?

    - by eSKay
    I have a C shell script that calls two C programs - one after the another with some file handling before, in-between and afterwards. Now, as such I have three different files - one C shell script and 2 .c files. I need to give this script to other users. The problem is that I have to distribute three files - which the users must keep in the same folder and then execute the script. Is there some better way to do this? [I know I can make one C code file out of those two... but I will still be left with a shell script and a C code. Actually, the two C codes do entirely different things... so I want them to be separate]

    Read the article

  • how to concatenate two strings in shell script in 3.13.0-34-generic kernel

    - by saikrishna
    I want to concatenate two strings for the shell file im getting error when i have created the shell file in following manner could you please suggest how to get it set export APP_HOME="/home/sfptladmin/ArchivalDaemon" export JAVA_HOME="/usr/lib/jvm/java-7-oracle/jre" export LIBPATH="/home/sfptladmin/ArchivalDaemon/lib" export CPATH=$APP_HOME/conf export CPATH=$CPATH:$LIBPATH/commons-beanutils-core-1.7.0.jar export CPATH=$CPATH:$LIBPATH/commons-collections-3.2.jar export CPATH=$CPATH:$LIBPATH/commons-io-1.4.jar export CPATH=$CPATH:$LIBPATH/commons-lang.jar export CPATH=$CPATH:$LIBPATH/commons-net.jar export CPATH=$CPATH:$LIBPATH/dataloader-27.0.1-uber.jar export CPATH=$CPATH:$LIBPATH/dom4j-1.6.1.jar export CPATH=$CPATH:$LIBPATH/log4j-1.2.15.jar export CPATH=$CPATH:$LIBPATH/opencsv2.3.jar export CPATH=$CPATH:$LIBPATH/poi-3.7.jar export CPATH=$CPATH:$LIBPATH/poi-ooxml-3.7.jar export CPATH=$CPATH:$LIBPATH/poi-ooxml-schemas-3.7.jar export CPATH=$CPATH:$LIBPATH/wsc-23-min.jar export CPATH=$CPATH:$LIBPATH/xmlbeans-2.5.0.jar export CPATH=$CPATH:$LIBPATH/archival-daemon-main.jar export CPATH=$CPATH:$LIBPATH/sbmclasspath.jar export CPATH=$CPATH java -Xms256m -Xmx512m -classpath $CPATH "-Dfile.encoding=UTF-8" com.genpact.proflow.daemon.archival.manager.ArchivalManager echo $CPATH

    Read the article

  • Apache cannot find mysql database modules

    - by user809857
    I've created a simple django project and setup a mysql database. My simple project just creates an entry on the database. The project works fine when I use the built in development server provided by django (runserver) and it works well. But when I deployed the project on Apache and mod_Wsgi (Ubuntu server), django could not find 'books', which is in this case my table in the database. The mysql database that I use in runserver and apache are just the same. I also did rebuild the database using sqlall,validate and syncdb of django but still i get the error. What could be wrong with what I'm doing? Thanks

    Read the article

  • Apache cannot find mysql database modules

    - by user809857
    I've created a simple django project and setup a mysql database. My simple project just creates an entry on the database. The project works fine when I use the built in development server provided by django (runserver) and it works well. But when I deployed the project on Apache and mod_Wsgi (Ubuntu server), django could not find 'books', which is in this case my table in the database. The mysql database that I use in runserver and apache are just the same. I also did rebuild the database using sqlall,validate and syncdb of django but still i get the error. What could be wrong with what I'm doing? Thanks

    Read the article

  • How do I create a "here document" within a shell function?

    - by BenU
    I'm working my way through William Shotts Jr.'s great The Linux Command Line on my Mac OSX 10.7.5 system. 90% of the linux that Shotts covers is close enough to Darwin that I can figure out or GTEM to figure out what's going on. I've made it to chapter 27 on "Writing Shell Scripts" and am getting hung up creating "here files" within a function. I get an syntax error: unexpected end of file error when I include the following function: report_uptime () { cat <<- _EOF_ <H2>System Uptime</H2> <PRE>$(uptime)</PRE> _EOF_ return } The error goes away if I use the following function placeholder: report_uptime () { return } Also, elsewhere in the script, outside of a function I use the cat << _EOF_ format to create a "here file" with no trouble: cat << _EOF_ <HTML> <HEAD> <TITLE>$TITLE</TITLE> </HEAD> <BODY> <H1>$TITLE</H1> <P>$TIME_STAMP</P> $(report_uptime) $(report_disk_space) $(report_home_space) </BODY> </HTML> _EOF_ If anyone has any idea what I'm doing wrong I would be grateful!

    Read the article

  • Ubuntu boots up maintenance shell?

    - by Andrew
    Any time I try to start up my computer it goes to a screen titled GNU GRUB version 1.99-12ubuntu5 I can then choose from 5 different options. If I try to just boot Ubuntu, with Linux 3.0.0-20-generic it then goes to a screen saying: mountall: /lib/x86_64-linux-gnu/libc.so.6: version 'GLIBC_2.14' not found (required by /lib/libply.so.2) General error mounting filesystems. A maintenance shell will now be started. CONTROL-D will terminate this shell and reboot the system. root@Brown126:~# Control-D just brings me back to the first screen. And nothing works in recovery mode. How can I fix this?

    Read the article

  • No longer able to boot stuck in busybox shell

    - by Chris J. Lee
    I've installed win 7 and ubuntu 11.04. After a storm killed the power. i'm unable to boot. I'm stuck in the busybox shell (ash). Here's what happens when i boot: Bios loads Grub displays option to load: ubuntu ubuntu recovery memtest another memtest option win7 win 7 recovery I load Ubuntu This cause it to load and i see no normal ubuntu screen just the busybox shell I try loading ubuntu via fsck -l; and it returns me a /bin/sh not found error. I load windows 7 and i'm unable to boot. I get a blue screen of death I then load ubuntu recovery and i don't have any luck either. Any ideas where to go from here?

    Read the article

  • How to negate current window in gnome shell?

    - by k0pernikus
    I dislike that most websites use a black font on white background for their sites, as it gets too tiresome for me to read. Back in the days of 11.04, using Gnome2 with compiz, there actually was a Negative feature that could negate the content of any window, making the background black and the font white. Much easier on the eyes for me. Yet since 11.10, using gnome shell with mutter, I have no idea if there is something alike out there. Hence my question: How do I negate the currently active window in gnome shell? I am not interested in alternative methods, e.g. user styles. I am aware of their existence but I find it much easier to just invert the screen by the hit of a key shortcut. I also want the solution to be application-agnostic. As I also from time to time would want to invert libre-office or some other glaringly white application.

    Read the article

  • Quantal upgrade broke my gnome-shell!

    - by hwjp
    Just updated to quantal 12.10, and Unity works fine, but and I can't get gnome-shell to work :( Some symptoms: when using gdm as the default, it decided to display everything in chinese. When attempting to log in, it accepts the password, and then seems to crash when trying to load my desktop, and seems to restart gdm and send me back to the login screen when switching to lightdm as the window manager, it gets a little further (and in english), bringing up a desktop, but a broken one -- the propeller key doesn't bring up a menu, there's no menubar or notifactions area. i can do a few things, like bring up a terminal with ctrl+alt+t, and launch eg firefox from there, but not much else. I have tried uninstalling gnome-shell, deleting /etc/gdm, and reinstalling Any other suggestions? Which log files to look at for example?

    Read the article

  • UI font has rendering glitches in GNOME Shell

    - by user353889
    I don't really know how to describe this problem in English. A picture can say more words - look at the tabs at the top of the linked image. The current font settings are shown as well. I don't know what basic info I should provide so if something missing, please tell me. Ubuntu 12.04 GNOME Shell 3.4.1 I know, a reboot can make everything normal but I'm looking for a more permanent solution that can fix this problem (or bug). Update Thanks for Fitoschido, I finally know what keyword I could use for googling. I think it's a bug of gnome shell. https://bugs.archlinux.org/task/34847

    Read the article

  • 12.04 gnome shell broken after updates

    - by nat
    I'm running Ubuntu 12.04, and using gnome shell. I've had my machine running for the last few days, and I've been installing updates as the update manager bugs me. I just rebooted, and now gnome won't start. I can use gnome classic and unity, but gnome 3 isn't working at all. When I log in, the screen is black for maybe 20 seconds, but the cursor shows. Then, my wallpaper, but nothing else shows up. I can get a terminal with ctrl+alt+t, and I tried to run gnome-shell, but it segfaulted.

    Read the article

  • Run two shell file with thread

    - by user1149157
    How i can run two file shell in parallel and do not shared the same jvm. may be i use thread but how i run two file shell bu two thread ? File 1: #!/bin/bash # # Script for running several experimentations one the same JVM # Usage : TRACE_DIR NB_EXPE Factories... # param="parameter1" another="parameter2" for ((i = 10; i >= 0; i -= 1)) do echo "run my file with param another " done File 2 : #!/bin/bash # # Script for running several experimentations one the same JVM # Usage : TRACE_DIR NB_EXPE Factories... # a="101" b="400" c="500" echo "run my programme with a b c "

    Read the article

  • MySQL efficiency as it relates to the database/table size

    - by mlissner
    I'm building a system using django, Sphinx and MySQL that's very quickly becoming quite large. The database currently has about 2000 rows, and I've written a program that's going to populate it with another 40,000 rows in a couple days. Since the database is live right now, and since I've never had a database with this much information in it, I'm worried about some things: Is adding all these rows going to seriously degrade the efficiency of my django app? Will I need to go back through it and optimize all my database calls so they're doing things more cleverly? Or will this make the database slow all around to the extent that I can't do anything about it at all? If you scoff at my 40k rows, then, my next question is, at what point SHOULD I be concerned? I will likely be adding another couple hundred thousand soon, so I worry, and I fret. How is sphinx going to feel about all this? Is it going to freak out when it realizes it has to index all this data? Or will it be fine? Is this normal for it? If it is, at what point should I be concerned that it's too much data for Sphinx? Thanks for any thoughts.

    Read the article

  • Select those objects whose related objects IDs are *all* in given string

    - by Jannis
    Hi Django people, I want to build a frontend to a recipe database which enables the user to search for a list of recipes which are cookable with the ingredients the user supplies. I have the following models class Ingredient(models.Model): name = models.CharField(max_length=100, unique=True) slug = models.SlugField(max_length=100, unique=True) importancy = models.PositiveSmallIntegerField(default=4) […] class Amount(models.Model): recipe = models.ForeignKey('Recipe') ingredient = models.ForeignKey(Ingredient) […] class Rezept(models.Model): name = models.CharField(max_length=100) slug = models.SlugField() instructions = models.TextField() ingredients = models.ManyToManyField(Ingredient, through=Amount) […] and a rawquery which does exactly what I want: It gets all the recipes whose required ingredients are all contained in the list of strings that the user supplies. If he supplies more than necessary, it's fine too. query = "SELECT *, COUNT(amount.zutat_id) AS selected_count_ingredients, (SELECT COUNT(*) FROM amount WHERE amount.recipe_id = amount.id) AS count_ingredients FROM amount LEFT OUTER JOIN amount ON (recipe.id = recipe.recipe_id) WHERE amount.ingredient_id IN (%s) GROUP BY amount.id HAVING count_ingredient=selected_count_ingredient" % ",".join([str(ingredient.id) for ingredient in ingredients]) rezepte = Rezept.objects.raw(query) Now, what I'm looking for is a way that does not rely on .raw() as I would like to do it purely with Django's queryset methods. Additionally, it would be awesome if you guys knew a way of including the ingredient's importancy in the lookup so that a recipe is still shown as a result even though one of its ingredients (that has an importancy of 0) is not supplied by the user.

    Read the article

  • Dynamically setting the queryset of a ModelMultipleChoiceField to a custom recordset

    - by Daniel Quinn
    I've seen all the howtos about how you can set a ModelMultipleChoiceField to use a custom queryset and I've tried them and they work. However, they all use the same paradigm: the queryset is just a filtered list of the same objects. In my case, I'm trying to get the admin to draw a multiselect form that instead of using usernames as the text portion of the , I'd like to use the name field from my account class. Here's a breakdown of what I've got: # models.py class Account(models.Model): name = models.CharField(max_length=128,help_text="A display name that people understand") user = models.ForeignKey(User, unique=True) # Tied to the User class in settings.py class Organisation(models.Model): administrators = models.ManyToManyField(User) # admin.py from django.forms import ModelMultipleChoiceField from django.contrib.auth.models import User class OrganisationAdminForm(forms.ModelForm): def __init__(self, *args, **kwargs): from ethico.accounts.models import Account self.base_fields["administrators"] = ModelMultipleChoiceField( queryset=User.objects.all(), required=False ) super(OrganisationAdminForm, self).__init__(*args, **kwargs) class Meta: model = Organisation This works, however, I want queryset above to draw a selectbox with the Account.name property and the User.id property. This didn't work: queryset=Account.objects.all().order_by("name").values_list("user","name") It failed with this error: 'tuple' object has no attribute 'pk' I figured that this would be easy, but it's turned into hours of dead-ends. Anyone care to shed some light?

    Read the article

  • Blocking error in celery

    - by dmitry
    I have no idea what's this. Python 2.7 + django-1.5.1 + httpd + rabbitmq + django-celery==3.0.17 Tasks are not executed because of some error. Below is celery's log. Maybe someone has faced it before. [2013-06-24 17:10:03,792: CRITICAL/MainProcess] Can't decode message body: AttributeError("'JoinInfo' object has no attribute '__dict__'",) (type:u'application/x-python-serialize' encoding:u'binary' raw:'\'\\x80\\x02}q\\x01(U\\x07expiresq\\x02NU\\x03utcq\\x03\\x88U\\x04argsq\\x04cdjango.contrib.auth.models\\nUser\\nq\\x05)\\x81q\\x06}q\\x07(U\\x08usernameq\\x08X\\x19\\x00\\x00\\[email protected]\\nfirst_nameq\\tX\\x05\\x00\\x00\\x00BibbyU\\tlast_nameq\\nX\\x08\\x00\\x00\\x00OffshoreU\\r_client_cacheq\\x0bccopy_reg\\n_reconstructor\\nq\\x0ccbongoregistration.models\\nClient\\nq\\rc__builtin__\\nobject\\nq\\x0eN\\x87Rq\\x0f}q\\x10(h\\nX\\x08\\x00\\x00\\x00OffshoreU\\x1bpurchase_confirmation_emailq\\x11X\\x1f\\x00\\x00\\[email protected]\\x1dpurchase_confirmation_email_1q\\x12X!\\x00\\x00\\[email protected]\\x06_stateq\\x13cdjango.db.models.base\\nModelState\\nq\\x14)\\x81q\\x15}q\\x16(U\\x06addingq\\x17\\x89U\\x02dbq\\x18U\\x07defaultq\\x19ubU\\x0buser_ptr_idq\\x1aJ\\xb4\\xa2\\x03\\x00U\\x08is_staffq\\x1b\\x89U\\x08postcodeq\\x1cX\\x08\\x00\\x00\\x00AB11 5BSU\\x0cdegree_limitq\\x1dK\\x06U\\x07messageq\\x1eX\\xd1E\\x00\\x00<table id="container" style="margin: 0px; padding: 0px; width: 100%; background-color: #ffffff;" cellspacing="0" cellpadding="0"... (22911b)'') Traceback (most recent call last): File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/messaging.py", line 556, in _receive_callback decoded = None if on_m else message.decode() File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/transport/base.py", line 147, in decode self.content_encoding, accept=self.accept) File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/serialization.py", line 187, in decode return decode(data) File "/opt/www/MyProject-main/eggs/kombu-2.5.10-py2.7.egg/kombu/serialization.py", line 74, in pickle_loads return load(BytesIO(s)) AttributeError: 'JoinInfo' object has no attribute '__dict__'

    Read the article

  • Firefox handles xxx.submit(), Safari doesn't ... what can be done?

    - by Prairiedogg
    I'm trying to make a pull down menu post a form when the user selects (releases the mouse) on one of the options from the menu. This code works fine in FF but Safari, for some reason, doesn't submit the form. I re-wrote the code using jquery to see if jquery's .submit() implementation handled the browser quirks better. Same result, works in FF doesn't work in safari. The following snippets are from the same page, which has some django template language mixed in. Here's the vanilla js attempt: function formSubmit(lang) { if (lang != '{{ LANGUAGE_CODE }}') { document.getElementById("setlang_form").submit(); } } Here's the jquery attempt: $(document).ready(function() { $('#lang_submit').hide() $('#setlang_form option').mouseup(function () { if ($(this).attr('value') != '{{ LANGUAGE_CODE }}') { $('#setlang_form').submit() } }); }); and here's the form: <form id="setlang_form" method="post" action="{% url django.views.i18n.set_language %}"> <fieldset> <select name="language"> {% for lang in interface_languages %} <option value="{{ lang.code }}" onmouseup="formSubmit('{{ lang.name }}')" {% ifequal lang.code LANGUAGE_CODE %}selected="selected"{% endifequal %}>{{ lang.name }}</option> {% endfor %} </select> </fieldset> </form> My question is, how can I get this working in Safari?

    Read the article

< Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >