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  • Move MySQL master

    - by Noodles
    I currently have a master db server (lets call it db1) and 6 slaves (slave1-6). I've setup a new server (db2) as a slave of db1 and it's in sync. I want to change all the slaves to use db2 instead of db1, but with minimal downtime/data loss. At the moment the only way I can think of doing it is shutting down our website (so data stops being written to db1), waiting until all the slaves are up to date, flush logs on db1, shut it down. Reset master on db2, change all slaves to point to db2 with log position = 0. Is this the right way to do it or is there a way to do it without taking the site offline?

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  • setting my mysql server - limiting domains that can connect

    - by Alex
    I am trying to setup a mysql server on my machine. I would like to limit the domains that it listens for connections to. My understanding is that you can either have it listen to 1 ip or all ip's. Therefore, if i want to connect remotely I have to say all ips. Then I would like to block all domains but the ones I know should actually be connecting.. I believe this is done through windows firewall. However, how do i do this by domain instead of IP?

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  • MySQL max_user_connections

    - by Sheriffen
    We're releasing a site in a couple of weeks that has been developed on a local machine but now when were testing on dev server we get MySQL error 'max_user_connections'. We have talked to the host company (biggest in sweden) and they say that we don't close our connections properly. But the thing is that we user the EXACT same code on another host where it works. And I also added echo "closed"; in the database_close function so that now in the very bottom of very page there is "closed". To me this means that we do close the connection, anyone got any idea of what could be wrong? We connect through the PHP PDO function and closes it by setting it to 'null', all according to the manual.

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  • MySql in Bash: Show only errors

    - by TRWTFCoder
    Let me first start off by saying I am not an experienced linux user. I am trying to debug a mysql script in linux, however, my issue is that most of the queries are successful so I can not see the error messages because they scroll off the screen. I am executing the queries from a large file using the \. command. I was wondering if there was a way to show ONLY the error messages when I exececute the sql file. Right now it is showing both error messages and Query OK,.... I don't really care about the queries that are ok, just the errors. Thanks!

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  • How to handle monetary values in PHP and MySql?

    - by Songo
    I've inherited a huge pile of legacy code written in PHP on top of a MySQL database. The thing I noticed is that the application uses doubles for storage and manipulation of data. Now I came across of numerous posts mentioning how double are not suited for monetary operations because of the rounding errors. However, I have yet to come across a complete solution to how monetary values should be handled in PHP code and stored in a MySQL database. Is there a best practice when it comes to handling money specifically in PHP? Things I'm looking for are: How should the data be stored in the database? column type? size? How should the data be handling in normal addition, subtraction. multiplication or division? When should I round the values? How much rounding is acceptable if any? Is there a difference between handling large monetary values and low ones? Note: A VERY simplified sample code of how I might encounter money values in everyday life: $a= $_POST['price_in_dollars']; //-->(ex: 25.06) will be read as a string should it be cast to double? $b= $_POST['discount_rate'];//-->(ex: 0.35) value will always be less than 1 $valueToBeStored= $a * $b; //--> any hint here is welcomed $valueFromDatabase= $row['price']; //--> price column in database could be double, decimal,...etc. $priceToPrint=$valueFromDatabase * 0.25; //again cast needed or not? I hope you use this sample code as a means to bring out more use cases and not to take it literally of course. Bonus Question If I'm to use an ORM such as Doctrine or PROPEL, how different will it be to use money in my code.

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  • How to differenciate the data when doing a UNION on 2 SELECTS ?

    - by wiooz
    If I have the following two tables : Employes Bob Gina John Customers Sandra Pete Mom I will do a UNION for having : Everyone Bob Gina John Sandra Pete Mom The question is : In my result, how can I creat a dumn column of differenciate the data from my tables ? Everyone Bob (Emp) Gina (Emp) John (Emp Sandra (Cus) Pete (Cus) Mom (Cus) I want to know from with table the entry is from withouth adding a new column in the database... SELECT Employes.name FROM Employes UNION SELECT Customers.name FROM Customers;

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  • How to avoid this PDO exception: Cannot execute queries while other unbuffered queries are active

    - by Vittorio Vittori
    Hi, I'd like to print a simple table in my page with 3 columns, building name, tags and architecture style. If I try to retrieve the list of building names and arch. styles there is no problem: SELECT buildings.name, arch_styles.style_name FROM buildings INNER JOIN buildings_arch_styles ON buildings.id = buildings_arch_styles.building_id INNER JOIN arch_styles ON arch_styles.id = buildings_arch_styles.arch_style_id LIMIT 0, 10 My problem starts on retreaving the first 5 tags for every building of the query I've just wrote. SELECT DISTINCT name FROM tags INNER JOIN buildings_tags ON buildings_tags.tag_id = tags.id AND buildings_tags.building_id = 123 LIMIT 0, 5 The query itself works perfectly, but not where I thought to use it: <?php // pdo connection allready active, i'm using mysql $pdo_conn->setAttribute(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY, true); $sql = "SELECT buildings.name, buildings.id, arch_styles.style_name FROM buildings INNER JOIN buildings_arch_styles ON buildings.id = buildings_arch_styles.building_id INNER JOIN arch_styles ON arch_styles.id = buildings_arch_styles.arch_style_id LIMIT 0, 10"; $buildings_stmt = $pdo_conn->prepare ($sql); $buildings_stmt->execute (); $buildings = $buildings_stmt->fetchAll (PDO::FETCH_ASSOC); $sql = "SELECT DISTINCT name FROM tags INNER JOIN buildings_tags ON buildings_tags.tag_id = tags.id AND buildings_tags.building_id = :building_id LIMIT 0, 5"; $tags_stmt = $pdo_conn->prepare ($sql); $html = "<table>"; // i'll use it to print my table foreach ($buildings as $building) { $name = $building["name"]; $style = $building["style_name"]; $id = $building["id"]; $tags_stmt->bindParam (":building_id", $id, PDO::PARAM_INT); $tags_stmt->execute (); // the problem is HERE $tags = $tags_stmt->fetchAll (PDO::FETCH_ASSOC); $html .= "... $name ... $style"; foreach ($tags as $current_tag) { $tag = $current_tag["name"]; $html .= "... $tag ..."; // let's suppose this is an area of the table where I print the first 5 tags per building } } $html .= "...</table>"; print $html; I'm not experienced on queries, so i though something like this, but it throws the error: PHP Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[HY000]: General error: 2014 Cannot execute queries while other unbuffered queries are active. Consider using PDOStatement::fetchAll(). Alternatively, if your code is only ever going to run against mysql, you may enable query buffering by setting the PDO::MYSQL_ATTR_USE_BUFFERED_QUERY attribute. What can I do to avoid this? Should I change all and search a different way to get this kind of queries?

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  • Dynamic Form Help for PHP and MySQL

    - by Tony
    The code below works as far as inserting records from a file into MySQL, but it only does so properly if the columns in the file are already ordered the same way as in the database. I would like for the user to be able to select the drop down the corresponds to each column in their file to match it up with the columns in the database (the database has email address, first name, last name). I am not sure how to accomplish this. Any ideas? <?php $lines =file('book1.csv'); foreach($lines as $data) { list($col1[],$col2[],$col3[]) = explode(',',$data); } $i = count($col1); if (isset($_POST['submitted'])) { DEFINE ('DB_USER', 'root'); DEFINE ('DB_PASSWORD', 'password'); DEFINE ('DB_HOST', 'localhost'); DEFINE ('DB_NAME', 'csvimport'); // Make the connection: $dbc = @mysqli_connect (DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); for($d=1; $d<$i; $d++) { $q = "INSERT into contacts (email, first, last) VALUES ('$col3[$d]', '$col1[$d]', '$col2[$d]')"; $r = @mysqli_query ($dbc, $q); } } echo "<form action =\"handle2.php\" method=\"post\">Email<br /> <select name =\"email\"> <option value='col1'>$col1[0]</option> <option value='col2'>$col2[0]</option> <option value='col3'>$col3[0]</option> </select><br /><br /> First Name <br /> <select name=\"field2\"> <option value='col1'>$col1[0]</option> <option value='col2'>$col2[0]</option> <option value='col3'>$col3[0]</option> </select><br /><br /> Last Name <br /> <select name=\"field3\"> <option value='col1'>$col1[0]</option> <option value='col2'>$col2[0]</option> <option value='col3'>$col3[0]</option> </select><br /><br /> <input type=\"submit\" name=\"submit\" value=\"Submit\" /> <input type=\"hidden\" name=\"submitted\" value=\"TRUE\" /> </form>"; ?>

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  • MySQL LEFT OUTER JOIN virtual table

    - by user1707323
    I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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  • MySQL search for user and their roles

    - by Jenkz
    I am re-writing the SQL which lets a user search for any other user on our site and also shows their roles. An an example, roles can be "Writer", "Editor", "Publisher". Each role links a User to a Publication. Users can take multiple roles within multiple publications. Example table setup: "users" : user_id, firstname, lastname "publications" : publication_id, name "link_writers" : user_id, publication_id "link_editors" : user_id, publication_id Current psuedo SQL: SELECT * FROM ( (SELECT user_id FROM users WHERE firstname LIKE '%Jenkz%') UNION (SELECT user_id FROM users WHERE lastname LIKE '%Jenkz%') ) AS dt JOIN (ROLES STATEMENT) AS roles ON roles.user_id = dt.user_id At the moment my roles statement is: SELECT dt2.user_id, dt2.publication_id, dt.role FROM ( (SELECT 'writer' AS role, link_writers.user_id, link_writers.publication_id FROM link_writers) UNION (SELECT 'editor' AS role, link_editors.user_id, link_editors.publication_id FROM link_editors) ) AS dt2 The reason for wrapping the roles statement in UNION clauses is that some roles are more complex and require a table join to find the publication_id and user_id. As an example "publishers" might be linked accross two tables "link_publishers": user_id, publisher_group_id "link_publisher_groups": publisher_group_id, publication_id So in that instance, the query forming part of my UNION would be: SELECT 'publisher' AS role, link_publishers.user_id, link_publisher_groups.publication_id FROM link_publishers JOIN link_publisher_groups ON lpg.group_id = lp.group_id I'm pretty confident that my table setup is good (I was warned off the one-table-for-all system when researching the layout). My problem is that there are now 100,000 rows in the users table and upto 70,000 rows in each of the link tables. Initial lookup in the users table is fast, but the joining really slows things down. How can I only join on the relevant roles? -------------------------- EDIT ---------------------------------- Explain above (open in a new window to see full resolution). The bottom bit in red, is the "WHERE firstname LIKE '%Jenkz%'" the third row searches WHERE CONCAT(firstname, ' ', lastname) LIKE '%Jenkz%'. Hence the large row count, but I think this is unavoidable, unless there is a way to put an index accross concatenated fields? The green bit at the top just shows the total rows scanned from the ROLES STATEMENT. You can then see each individual UNION clause (#6 - #12) which all show a large number of rows. Some of the indexes are normal, some are unique. It seems that MySQL isn't optimizing to use the dt.user_id as a comparison for the internal of the UNION statements. Is there any way to force this behaviour? Please note that my real setup is not publications and writers but "webmasters", "players", "teams" etc.

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  • php code is not fetching data from mysql database using wamp server

    - by john
    I want to display a table from database in phpMyAdmin by putting the following conditions that in every different options in drop down menu it displays different table from database by pressing the button of search. But it is not doing so. <p class="h2">Quick Search</p> <div class="sb2_opts"> <p></p> <form method="post" action="" > <p>Enter your source and destination.</p> <p>From:</p> <select name="from"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <p>To:</p> <select name="To"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <input type="submit" value="search" /> </form> </form> </table> <?php $con=mysqli_connect("localhost","root","","test"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } if(isset($_POST['from']) and isset($_POST['To'])) { $from = $_POST['from'] ; $to = $_POST['To'] ; $table = array($from, $to); switch ($table) { case array ("Islamabad", "Lahore") : $result = mysqli_query($con,"SELECT * FROM flights"); echo "</flights>"; //table name is flights break; case array ("Islamabad", "Murree") : $result = mysqli_query($con,"SELECT * FROM isb to murree"); echo "</isb to murree>"; //table name isb to murree ; break; case array ("Islamabad", "Muzaffarabad") : $result = mysqli_query($con,"SELECT * FROM isb to muzz"); echo "</isb to muzz>"; break; //..... //...... default: echo "Your choice is nor valid !!"; } } mysqli_close($con); ?>

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  • PHP: PDOStatement simple MySQL Select doesn't work.

    - by Alan
    Hi I have the following PHP code doing a very simple select into a table. $statement = $db->prepare("SELECT * FROM account WHERE fbid = :fbid"); $statement->bindParam(":fbid",$uid, PDO::PARAM_STR,45); $out = $statement->execute(); $row = $statement->fetch(); $out is true (success) yet $row is null. If I modify the code as follows: $statement = $db->prepare("SELECT * FROM account WHERE fbid = $uid"); $out = $statement->execute(); $row = $statement->fetch(); $row contains the record I'm expecting. I'm at a loss. I'm using the PDO::prepare(), bindParams() etc to protect against SQL Injection (maybe I'm mistaken on that). Please halp.

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  • mysqldb interfaceError

    - by Johanna
    I have a very weird probleme with mysqldb (mysql module for python). I have a file with queries for inserting records in tables. If I call the functions from the file, it works just fine. But when I try to call one of the functions from another file it throws me a _mysql_exception.InterfaceError: (0, '') I really don't get what I'm doing wrong here.. I call the function from buildDB.py : import create create.newFormat("HD", 0,0,0) The function newFormat(..) is in create.py (imported) : from Database import Database db = Database() def newFormat(name, width=0, height=0, fps=0): format_query = "INSERT INTO Format (form_name, form_width, form_height, form_fps) VALUES ('"+name+"',"+str(width)+","+str(height)+","+str(fps)+");" db.execute(format_query) And the class Databse is the following : import MySQLdb from MySQLdb.constants import FIELD_TYPE class Database(): def __init__(self): server = "localhost" login = "seq" password = "seqmanager" database = "Sequence" my_conv = { FIELD_TYPE.LONG: int } self.conn = MySQLdb.connection(host=server, user=login, passwd=password, db=database, conv=my_conv) # self.cursor = self.conn.cursor() def close(self): self.conn.close() def execute(self, query): self.conn.query(query) (I put only relevant code) Traceback : Z:\sequenceManager\mysql>python buildDB.py D:\ProgramFiles\Python26\lib\site-packages\MySQLdb\__init__.py:34: DeprecationWa rning: the sets module is deprecated from sets import ImmutableSet INSERT INTO Format (form_name, form_width, form_height, form_fps) VALUES ('HD',0 ,0,0); Traceback (most recent call last): File "buildDB.py", line 182, in <module> create.newFormat("HD") File "Z:\sequenceManager\mysql\create.py", line 52, in newFormat db.execute(format_query) File "Z:\sequenceManager\mysql\Database.py", line 19, in execute self.conn.query(query) _mysql_exceptions.InterfaceError: (0, '') The warning has never been a problem before so I don't think it's related.

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  • Nested mysql select statements

    - by Jimmy Kamau
    I have a query as below: $sult = mysql_query("select * from stories where `categ` = 'businessnews' and `stryid`='".mysql_query("SELECT * FROM comments WHERE `comto`='".mysql_query("select * from stories where `categ` ='businessnews'")." ORDER BY COUNT(comto) DESC")."' LIMIT 3") or die(mysql_error()); while($ow=mysql_fetch_array($sult)){ The code above should return the top 3 'stories' with the most comments {count(comto)}. The comments are stored in a different table from the stories. The code above does not return any values and doesn't show any errors. Could someone please help?

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  • I have created a PHP script and I am lacking to extract the primary key, I have given flow below, pl

    - by Parth
    I am using MySQL DB, working for Joomla, My requirement is tracking the activity like insert/update/delete on any table and store it in another audit table using triggers, i.e. I am doing Auditing. DB's table structure: Few tables dont have any PK nor auto increment key Flow of my script is : I fetch out all table from DB. I check whether the table have any trigger or not. If yes then it moves to check nfor next table and so on. If it does'nt find any trigger then it creates the triggers for the table, such that, -it first checks if the table has any primary key or not(for inserting in Tracking audit table for every change made) if it has the primary key then it uses it further in creation of trigger. if it doesnt find any PK then it proceeds further in creating the trigger without inserting any id in audit table Now here, My problem is I need the PK every time so that I can record the id of any particular table in which the insert/update/delete is performed, so that further i can use this audit track table to replicate in production DB.. Now as I haave mentioned earlier that I am not available with PK/auto-incremented in some table, then what should I do get the particular id in which change is done? please guide me...GEEKS!!!

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  • 2 Select or 1 Join query ?

    - by xRobot
    I have 2 tables: book ( id, title, age ) ---- 100 milions of rows author ( id, book_id, name, born ) ---- 10 millions of rows Now, supposing I have a generic id of a book. I need to print this page: Title: mybook authors: Tom, Graham, Luis, Clarke, George So... what is the best way to do this ? 1) Simple join like this: Select book.title, author.name From book, author WHERE ( author.book_id = book.id ) AND ( book.id = 342 ) 2) For avoid the join, I could make 2 simple query: Select title FROM book WHERE id = 342 Select name FROM author WHERE book_id = 342 What is the most efficient way ?

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  • Select 2 Rows from Table when COUNT of another table

    - by Marcus
    Here is the code that I currently have: SELECT `A`.* FROM `A` LEFT JOIN `B` ON `A`.`A_id` = `B`.`value_1` WHERE `B`.`value_2` IS NULL AND `B`.`userid` IS NULL ORDER BY RAND() LIMIT 2 What it currently is supposed to do is select 2 rows from A when the 2 rows A_id being selected are not in value_1 or value_2 in B. And the rows in B are specific to individual users with userid. What I need to do is make it also so that also checks if there are already N rows in B matching a A_id (either in value_1, or value_2) and userid, and if there are more than N rows, it doesn't select the A row.

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  • How can I clean up this SELECT query?

    - by Cruachan
    I'm running PHP 5 and MySQL 5 on a dedicated server (Ubuntu Server 8.10) with full root access. I'm cleaning up some LAMP code I've inherited and I've a large number of SQL selects with this type of construct: SELECT ... FROM table WHERE LCASE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE( strSomeField, ' ', '-'), ',', ''), '/', '-'), '&', ''), '+', '') ) = $somevalue Ignoring the fact that the database should never have been constructed to require such a select in the first place, and the $somevalue field will need to be parameterised to plug the gaping security hole, what is my best option for fixing the WHERE condition into something less offensive? If I was using MSSQL or Oracle I'd simply put together a user-defined function, but my experience with MySQL is more limited and I've not constructed a UDF with it before, although I'm happy coding C. Update: For all those who've already raised their eyebrows at this in the original code, $somevalue is actually something like $GET['product']—there are a few variations on the theme. In this case the select is pulling the product back from the database by product name—after stripping out characters so it matches what could be previously passed as a URI parameter.

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  • Is this SQL select code following good practice?

    - by acidzombie24
    I am using sqlite and will port to mysql (5) later. I wanted to know if I am doing something I shouldnt be doing. I tried purposely to design so I'll compare to 0 instead of 1 (I changed hasApproved to NotApproved to do this, not a big deal and I haven't written any code). I was told I never need to write a subquery but I do here. My Votes table is just id, ip, postid (I don't think I can write that subquery as a join instead?) and that's pretty much all that is on my mind. Naming conventions I don't really care about since the tables are created via reflection and is all over the place. select id, name, body, upvotes, downvotes, (select 1 from UpVotes where IPAddr=? AND post=Post.id) as myup, (select 1 from DownVotes where IPAddr=@0 AND post=Post.id) as mydown from Post where flag = '0' limit ?, ?"

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  • Joining two select queries and ordering results

    - by user1
    Basically I'm just unsure as to why this query is failing to execute: (SELECT replies.reply_post, replies.reply_content, replies.reply_date AS d, members.username FROM (replies) AS a INNER JOIN members ON replies.reply_by = members.id) UNION (SELECT posts.post_id, posts.post_title, posts.post_date AS d, members.username FROM (posts) as b WHERE posts.post_set = 0 INNER JOIN members ON posts.post_by = members.id) ORDER BY d DESC LIMIT 5 I'm getting this error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'a INNER JOIN members ON replies.re' at line 2 All I'm trying to do is select the 5 most recent rows (dates) from these two tables. I've tried Join, union etc and I've seen numerous queries where people have put another query after the FROM statement and that just makes no logical sense to me as to how that works? Am I safe to say that you can join the same table from two different but joined queries? Or am I taking completely the wrong approach, because frankly I can't seem see how this query is failing despite reading the error message. (The two queries on there own work fine)

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  • Mysql SELECT with an OR across 2 columns

    - by Haroldo
    I'm creating a 'similar items' link table. i have a 2 column table. both columns contains product ids. The table is showing that these items are similar. However ids in the left column are more valuable. Say i want to select similar items to product '125b'. i only want 3 similar items to 125b. If there are any instances of 125b in col1 I would prefer these to finding 125b in col2. so i need a select statement along the lines of SELECT * FROM similar_items WHERE col_1={$id} OR col_2={$id} ORDER BY column(?) LIMIT 3 i do not want to do 2 separate queries ( ie query 2 if count(query1) <3 )

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  • insert into select from other table

    - by user3815079
    I need to add multiple records based on data from another table where the event is the same. I've found on this forum insert into table2(id,name) select "001",first_name from table1 where table1.id="001" as possible solution for my question. So I thought this should be the following syntax: insert into reservations(event,seat) select "99",id from seats where seats.id>0 to add all seats to event 99. However when I run this query mysql gives the message 'MySQL returned an empty resultset (0 rows). (query 0.0028 sec)' and no records were added. I translated the message so could be sligthly different. When I only use the "select "99",id from seats where seats.id0" query, it returns me 1080 rows.

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  • mysql select when matching multiple rows

    - by user1735943
    I have a project where I need to select only the users that answered to some questions in a certain way (based on a filter). The filter table (filter) looks like this question | answer Q1 | A Q2 | B The user table (answers) looks like this user | question | answer 1 | Q1 | A 1 | Q2 | D 2 | Q1 | A 2 | Q2 | B How can I select from the user table only the user(s) that match the filter? I tried "SELECT user FROM answers WHERE (question = Q1 AND answer = A) AND (question = Q2 AND answer = B)" and it doesn't work -- I get an empty result. Thank you.

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  • Select value from database and store into a temporary variable

    - by user1616230
    I want to select a stored value from database and then put it into a temporary variable. For example, I have a column called category, one value under it is m, so I want to select this m value from the database, let's say from a table of a database called user_info. Then I want to put it into a variable, let's name it $res. After that, I want to do some condition stuff, such as if $res=="m", Can anyone help me write a simple structure here? Here is the code: <?php $sql = "Select category FROM user_info WHERE user_name = '" .$_SESSION['username']."' and password = '".$_SESSION['password']."'"; $res = mysql_query($sql); if($res == "a"){ include('MPIncomeStrategy.php'); } if($res == "b"){ include('MPIncomeStrategy.php'); } But it seems that the code is not able to detect $res =="category value in database". Did I just use the wrong way to store the category value?

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  • CENTOS 6 - How to install php-mysql when php-common @remi is present?

    - by Multitut
    I am having troubles adding mysql support for my php installation, this installation was made using a ready to use-package that came with our VPS. This is my php.info: http://snake.quetzalcoatech.com/info.php I am trying to install php mysql using: yum install php-mysql And get this output: Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirrors.serveraxis.net * extras: mirror.fdcservers.net * updates: bay.uchicago.edu Setting up Install Process Resolving Dependencies --> Running transaction check ---> Package php-mysql.x86_64 0:5.3.3-14.el6_3 will be installed --> Processing Dependency: php-common = 5.3.3-14.el6_3 for package: php-mysql-5.3.3-14.el6_3.x86_64 --> Finished Dependency Resolution Error: Package: php-mysql-5.3.3-14.el6_3.x86_64 (updates) Requires: php-common = 5.3.3-14.el6_3 Installed: php-common-5.3.17-2.el6.remi.x86_64 (@remi) php-common = 5.3.17-2.el6.remi Available: php-common-5.3.3-3.el6_2.8.x86_64 (base) php-common = 5.3.3-3.el6_2.8 Available: php-common-5.3.3-14.el6_3.x86_64 (updates) php-common = 5.3.3-14.el6_3 You could try using --skip-broken to work around the problem You could try running: rpm -Va --nofiles --nodigest I am a noob using Linux, so could you tell me which command should I use to install a compatible php-mysql module? Thank you so much!

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