Search Results

Search found 5 results on 1 pages for 'ruhit'.

Page 1/1 | 1 

  • how to get response from remote server

    - by ruhit
    I have made a desktop application in asp.net using c# that connecting with remote server.I am able to connect but how do i show that my login is successful or not. After that i want to retrieve data from the remote server..........so plz help me.I have written the below code..............is there any better way try { string strId = UserId_TextBox.Text; string strpasswrd = Password_TextBox.Text; ASCIIEncoding encoding = new ASCIIEncoding(); string postData = "UM_email=" + strId; postData += ("&UM_password=" + strpasswrd); byte[] data = encoding.GetBytes(postData); MessageBox.Show(postData); // Prepare web request... //HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create("http://localhost/ruhit/basic_framework/index.php?menu=login=" + postData); HttpWebRequest myRequest =(HttpWebRequest)WebRequest.Create("http://www.facebook.com/login.php=" + postData); myRequest.Method = "POST"; myRequest.ContentType = "application/x-www-form-urlencoded"; myRequest.ContentLength = data.Length; Stream newStream = myRequest.GetRequestStream(); // Send the data. newStream.Write(data, 0, data.Length); MessageBox.Show("u r now connected"); HttpWebResponse response = (HttpWebResponse)myRequest.GetResponse(); // WebResponse response = myRequest.GetResponse(); StreamReader reader = new StreamReader(response.GetResponseStream()); string str = reader.ReadLine(); while (str != null) { str = reader.ReadLine(); MessageBox.Show(str); } reader.Close(); newStream.Close(); } catch { MessageBox.Show("error connecting"); }

    Read the article

  • text to image conversion with JSON response

    - by ruhit
    i have made an application to convert text into image and it working out fine,now i am using JSON for conversion,it also working but except only two fields.....why i dont know, my codes are given below...please help me , is there any better way? // img.html excoflare enter your text here: Font Size:          Color:               Font:                 Height:              Width:                                            img.php require_once 'JSON/JSON.php'; header('Content-type: application/json'); header ("Content-type: image/png"); $text =$_REQUEST['text']; $text=json_encode($text); $path="C:\wamp\www\image"; $height=$_REQUEST['height']; $width=$_REQUEST['width']; define("WIDTH", $width); json_encode(WIDTH); define("HEIGHT", $height); json_encode(HEIGHT); $img = imagecreate(WIDTH, HEIGHT); imagesavealpha($img, true); $trans_colour = imagecolorallocatealpha($img, 0, 0, 0, 127); imagefill($img, 0, 0, $trans_colour); $getcolor=$_REQUEST['color']; switch($getcolor) { case 'red': $red = imagecolorallocate($img, 223, 14, 91); $color=json_encode($red); break; case 'white': $white = imagecolorallocate($img, 255, 255, 255); $color=json_encode($white); break; case 'black': $black = imagecolorallocate($img, 0,0,0); $color=json_encode($black); break; case 'grey': $grey = imagecolorallocate($img, 128, 128, 128); $color=json_encode($grey); break; // default: // break; } //$background_color = imagecolorallocate ($img, 25, 25, 25); $font = $_REQUEST['font']; //$font=json_encode($font); $fontsize =$_REQUEST['size']; //$fontsize=json_encode($fontsize); imagettftext($img, $fontsize, 0, 20, 20, $color, $font, $text); //Create image imagepng($img); imagepng($img,"$path/img.png"); //destroy image ImageDestroy($img); //header ('Content-type: image/png'); ? Thanks in advance..

    Read the article

  • Converting the content of <div> Tag To An Image [closed]

    - by ruhit
    how to convert the content of tag into image fomat in php, please someone help me,I realy need it....... i have made this application... <?php if(!isset($_GET['text'])) { die("No text provided"); } header ("Content-type: image/png"); $text = $_GET['text'] ; $path="C:\wamp\www\image"; $bg = imagecreatetruecolor(350, 75); //This will make it transparent imagesavealpha($bg, true); $trans_colour = imagecolorallocatealpha($bg, 0, 0, 0, 127); imagefill($bg, 0, 0, $trans_colour); $white = imagecolorallocate($bg, 255, 255, 255); $grey = imagecolorallocate($bg, 128, 128, 128); $black = imagecolorallocate($bg, 0,0,0); $background_color = imagecolorallocate ($bg, 25, 25, 25); $font = 'arial.ttf'; $fontsize = 20; imagettftext($bg, $fontsize, 0, 20, 20, $grey, $font, $text); //Create image imagepng($bg); imagepng($bg,"$path/img.png"); //destroy image ImageDestroy($bg); ?> and the image source is <img src="img.php?text=helloworld"> now I want the text input from a tag field, so how to do this?Please help me..

    Read the article

  • submit a form and get json response

    - by ruhit
    I have made an application to convert text to image formate and its workingout well. Now I want json response when i fill the form of the html page, my html page is given below...Please help me to do this <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"> <html lang="en"> <head> <title>kandarpa</title> </head> <div> <form action="img.php" method="get"><b>enter your text here:</b><br/> <textarea id="text" name="text" style=" background-color:inherit" cols="50" rows="10"></textarea><br/><br/> <input type="submit" value="Text to Image" name="submit"> </div><br/> <div> <tr> <td>Font Size</td> <td><select name="size"> <option value="8">8</option> <option value="12">12</option> <option value="18">18</option> <option value="24">24</option> <option value="32" selected="selected">32</option> <option value="48">48</option> <option value="64">64</option> </select></td> </tr> </div><br/> <div> <td>Font </td> <td><select name="font" id="font"> <option value="Fonts/arial.ttf">Arial</option> <option value="Fonts/times.ttf">Times New Roman</option> <option value="Fonts/tahoma.ttf">Tahoma</option> <option value="Fonts/Grand Stylus.ttf">Grand Stylus</option> <option value="Fonts/GARAIT.ttf">G</option> </select></td> </tr> </div><br/> <div> <td>Choose your Color </td> <td><select name="color" id="color"> <option value="white">white</option> <option value="black">black</option> <option value="grey">grey</option> <option value="red">red</option> </select></td> </tr> </div> <br/> <div> <td>Height </td> <input type="text" id="height" name="height"> </td><br/><br/> <td>Width</td> <input type="text" id="width" name="width"> </div> </form> </body> </html>

    Read the article

  • upload file on database through php code

    - by ruhit
    hi all I have made an application to upload files and its workingout well.now I want to upload my files on database and I also want to display the uploaded files names on my listby accessing the database....so kindly help me. my codes are given below- function uploadFile() { global $template; //$this->UM_index = $this->session->getUserId(); switch($_REQUEST['cmd']){ case 'upload': $filename = array(); //set upload directory //$target_path = "F:" . '/uploaded/'; for($i=0;$i<count($_FILES['ad']['name']);$i++){ if($_FILES["ad"]["name"]) { $filename = $_FILES["ad"]["name"][$i]; $source = $_FILES["ad"]["tmp_name"][$i]; $type = $_FILES["ad"]["type"]; $name = explode(".", $filename); $accepted_types = array('text/html','application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/x-compressed'); foreach($accepted_types as $mime_type) { if($mime_type == $type) { $okay = true; break; } } $continue = strtolower($name[1]) == 'zip' ? true : false; if(!$continue) { $message = "The file you are trying to upload is not a .zip file. Please try again."; } $target_path = "F:" . '/uploaded/'.$filename; // change this to the correct site path if(move_uploaded_file($source, $target_path )) { $zip = new ZipArchive(); $x = $zip->open($target_path); if ($x === true) { $zip->extractTo("F:" . '/uploaded/'); // change this to the correct site path $zip->close(); unlink($target_path); } $message = "Your .zip file was uploaded and unpacked."; } else { $message = "There was a problem with the upload. Please try again."; } } } echo "Your .zip file was uploaded and unpacked."; $template->main_content = $template->fetch(TEMPLATE_DIR . 'donna1.html'); break; default: $template->main_content = $template->fetch(TEMPLATE_DIR . 'donna1.html'); //$this->assign_values('cmd','uploads'); $this->assign_values('cmd','upload'); } } my html page is <html> <link href="css/style.css" rel="stylesheet" type="text/css"> <!--<form action="{$path_site}{$index_file}" method="post" enctype="multipart/form-data">--> <form action="index.php?menu=upload_file&cmd=upload" method="post" enctype="multipart/form-data"> <div id="main"> <div id="login"> <br /> <br /> Ad No 1: <input type="file" name="ad[]" id="ad1" size="10" />&nbsp;&nbsp;Image(.zip)<input type="file" name="ad[]" id="ad1" size="10" /> Sponsor By : <input type="text" name="ad3" id="ad1" size="25" /> <br /> <br /> </div> </div> </form> </html>

    Read the article

1