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  • jqgrid modify data returned from ajax call before display in table

    - by user954211
    I have to display some data that I receive from the server as json object like this {"rowndx":"0","rows":"25","rowstotal":"100","rowsdata":[ ["00","DEVICE001","T0_IHOME","1","***","1","10"], ["01","DEVICE002","NO_DEVICE","1","***","1","10"], ["02","DEVICE003","NO_DEVICE","0","***","1","10"], ..... Before displaying the received data in a table I would like to make changes where necessary adding units to the numbers or replacing the numbers with words (eg 0 -OFF 1- ON) To do this I have associated at the ajax option "success" my encoding function. In this case, however, remains always visible the message "Loading ..." and no other action is permitted. I moved my re-encoding procedure to the "complete" ajax option and this time it seems to work. But I did not understand what was my mistake and I do not know if my procedure can work. This is my table ajax configuration url : "devtbl.json", mtype : "POST", datatype : "json", postData : ...... ajaxGridOptions: { type : 'post', contentType: 'application/json', async : false, complete : DEVparse_serverdata, error : function() { alert('Something bad happened. Stopping');}, }, jsonReader : { root : "tablerows", page : "currentpage", total : "totalpages", records : "totalrecords", cell : "", id : "0", userdata : "userdata", repeatitems : true }, and my coding function function DEVparse_serverdata(js , textStatus) { var jsontablereply = {} ; var rowsxpage_int = parseInt(UB.rowsxpage.DEVtable) ; var jsonreply = jQuery.parseJSON(js.responseText) ; jsontablereply.currentpage = "" + (1 + (parseInt(jsonreply.rowndx) / rowsxpage_int)); jsontablereply.totalpages = "" + parseInt((parseInt(jsonreply.rowstotal) + (rowsxpage_int-1)) / rowsxpage_int) ; jsontablereply.totalrecords = jsonreply.rowstotal; jsontablereply.tablerows = [] ; $.each(jsonreply.rowsdata, function(ndx, row) { var rowarray = [] ; rowarray[0] = row[0] ; rowarray[1] = row[1] ; rowarray[2] = row[2] ; rowarray[3] = row[3] ; rowarray[4] = row[4] ; switch (row[2]) { case "NO_DEVICE": rowarray[5] = "***" ; break ; case "T0_IHOME": rowarray[5] = "T=" + row[5] + "°C" ; break ; } jsontablereply.tablerows[ndx] = rowarray ; }) ; // each jQuery("#DEVtbl")[0].addJSONData(jsontablereply); } (I am a beginner with Jquery my coding style is poor)

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