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  • XML Schema: Namespace issues when importing shared elements

    - by netzwerg
    When trying to import shared definitions from a XML Schema, I can properly reference shared types, but referencing shared elements causes validation errors. This is the schema that imports the shared definitions (example.xsd): <?xml version="1.0" encoding="UTF-8"?> <xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:shared="http://shared.com"> <xs:import namespace="http://shared.com" schemaLocation="shared.xsd"/> <xs:element name="example"> <xs:complexType> <xs:sequence> <xs:element ref="importedElement"/> <xs:element ref="importedType"/> </xs:sequence> </xs:complexType> </xs:element> <xs:element name="importedElement"> <xs:complexType> <xs:sequence> <xs:element ref="shared:fooElement"/> </xs:sequence> </xs:complexType> </xs:element> <xs:element name="importedType"> <xs:complexType> <xs:sequence> <xs:element name="bar" type="shared:barType"/> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> These are the shared definitions (shared.xsd): <?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://shared.com" targetNamespace="http://shared.com"> <xs:element name="fooElement"> <xs:simpleType> <xs:restriction base="xs:integer"/> </xs:simpleType> </xs:element> <xs:simpleType name="barType"> <xs:restriction base="xs:integer"/> </xs:simpleType> </xs:schema> Now consider this XML instance: <?xml version="1.0"?> <example xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="example.xsd"> <importedElement> <fooElement>42</fooElement> </importedElement> <importedType> <bar>42</bar> </importedType> </example> When validated, the "importedType" works perfectly fine, but the "importedElement" gives the following error: Invalid content was found starting with element 'fooElement'. One of '{"http://shared.com":fooElement}' is expected I would guess that my troubles are related to namespace issues (hence the somehow misleading "got fooElement but was expecting fooElement") -- any hints on what's wrong here?

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  • Java+DOM: How do I convert a DOM tree without namespaces to a namespace-aware DOM tree?

    - by java.is.for.desktop
    Hello, everyone! I receive a Document (DOM tree) from a certain API (not in JDK). Sadly, this Document is not namespace-aware. As far as I know DOM, once generated, namespace-awareness can't be "added" afterwards. When converting this Document using a Transformer to a string, the XML is correct. Elements have xmlns:... attributes and name prefixes. But from the DOM point of view, there are no namespaces and no prefixes. I need to be able to convert this Document into a new Document which is namespace-aware. Yes, I could do this by just converting it to a string and back to DOM with namespaces enabled. But: nodes of the original tree have user-objects set. Converting to string and back would make a mapping of these user-objects to the new Document very complicated, if not impossible. So I really need a way to convert non-namespace DOM to namespace DOM. Are there any more-or-less straightforward solutions for this? Worst case (what I'm hoping to avoid) would be to manually iterate through old Document tree and create new namespace-aware Node for each old Node. Doing so, one had to manually "parse" namespace prefixes, watch out for xmlns-attributes, and maintain a mapping between prefixes and namespace-URIs. Lots of things to go wrong.

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  • Alternative for namespaces in xml

    - by mridul4c
    I have a web-service which gives a xml feed for number of clients of us, our clients consumes the xml in different types of devices. In our XML we have some namespaces also. But one of our clients can't detect namespaces because of some limitation at their end. But I can't provide a new xml for him as well. Please suggest me something so that I can satisfy the needs of namespaces without using that, so that i can change my xml to be usable by all of them. Thanks in advance.

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  • Use XQuery to Access XML in Emacs

    - by Gregory Burd
    There you are working on a multi-MB/GB/TB XML document or set of documents, you want to be able to quickly query the content but you don't want to load the XML into a full-blown XML database, the time spent setting things up is simply too expensive. Why not combine a great open source editor, Emacs, and a great XML XQuery engine, Berkeley DB XML? That is exactly what Donnie Cameron did. Give it a try.

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  • Validating an XML document fragment against XML schema

    - by shylent
    Terribly sorry if I've failed to find a duplicate of this question. I have a certain document with a well-defined document structure. I am expressing that structure through an XML schema. That data structure is operated upon by a RESTful service, so various nodes and combinations of nodes (not the whole document, but fragments of it) are exposed as "resources". Naturally, I am doing my own validation of the actual data, but it makes sense to validate the incoming/outgoing data against the schema as well (before the fine-grained validation of the data). What I don't quite grasp is how to validate document fragments given the schema definition. Let me illustrate: Imagine, the example document structure is: <doc-root> <el name="foo"/> <el name="bar"/> </doc-root> Rather a trivial data structure. The schema goes something like this: <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <xsd:element name="doc-root"> <xsd:complexType> <xsd:sequence> <xsd:element name="el" type="myCustomType" /> </xsd:sequence> </xsd:complexType> </xsd:element> <xsd:complexType name="myCustomType"> <xsd:attribute name="name" use="required" /> </xsd:complexType> </xsd:schema> Now, imagine, I've just received a PUT request to update an 'el' object. Naturally, I would receive not the full document or not any xml, starting with 'doc-root' at its root, but the 'el' element itself. I would very much like to validate it against the existing schema then, but just running it through a validating parser wouldn't work, since it will expect a 'doc-root' at the root. So, again, the question is, - how can one validate a document fragment against an existing schema, or, perhaps, how can a schema be written to allow such an approach. Hope it made sense.

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  • Perl XML SAX parser emulating XML::Simple record for record

    - by DVK
    Short Q summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog - due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. What I'm looking for is an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is - e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • Perl XML SAX parser emulating XML::Simple record for record

    - by DVK
    Short Q summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog - due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. What I'm looking for is an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been.

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  • gwt+xml- can i read through incomplete XML using the GWT XML Parser

    - by Arvind
    I have a requirement where a user is typing in XML in a text area, and I want to show the various nodes in a tree...But as the user is typing in the xml, it wont be a complete xml (since he is still typing in the XML)... How do I read an incomplete XML and correctly generate the tree? I understand how to read an xml and generate nodes in the tree, what I want to know is, how to read the incomplete XML as it is being typed in

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  • Why isn't the Spring AOP XML schema properly loaded when Tomcat loads & reads beans.xml

    - by chrisbunney
    I'm trying to use Spring's Schema Based AOP Support in Eclipse and am getting errors when trying to load the configuration in Tomcat. There are no errors in Eclipse and auto-complete works correctly for the aop namespace, however when I try to load the project into eclipse I get this error: 09:17:59,515 WARN XmlBeanDefinitionReader:47 - Ignored XML validation warning org.xml.sax.SAXParseException: schema_reference.4: Failed to read schema document 'http://www.springframework.org/schema/aop/spring-aop-2.5.xsd', because 1) could not find the document; 2) the document could not be read; 3) the root element of the document is not . Followed by: SEVERE: StandardWrapper.Throwable org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 39 in XML document from /WEB-INF/beans.xml is invalid; nested exception is org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'aop:config'. Caused by: org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'aop:config'. Based on this, it seems the schema is not being read when Tomcat parses the beans.xml file, leading to the <aop:config> element not being recognised. My beans.xml file is as follows: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jaxws="http://cxf.apache.org/jaxws" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://cxf.apache.org/jaxws http://cxf.apache.org/schemas/jaxws.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd"> <!--import resource="classpath:META-INF/cxf/cxf.xml" /--> <!--import resource="classpath:META-INF/cxf/cxf-extension-soap.xml" /--> <!--import resource="classpath:META-INF/cxf/cxf-servlet.xml" /--> <!-- NOTE: endpointName attribute maps to wsdl:port@name & should be the same as the portName attribute in the @WebService annotation on the IWebServiceImpl class --> <!-- NOTE: serviceName attribute maps to wsdl:service@name & should be the same as the serviceName attribute in the @WebService annotation on the ASDIWebServiceImpl class --> <!-- NOTE: address attribute is the actual URL of the web service (relative to web app location) --> <jaxws:endpoint xmlns:tns="http://iwebservices.ourdomain/" id="iwebservices" implementor="ourdomain.iwebservices.IWebServiceImpl" endpointName="tns:IWebServiceImplPort" serviceName="tns:IWebService" address="/I" wsdlLocation="wsdl/I.wsdl"> <!-- To have CXF auto-generate WSDL on the fly, comment out the above wsdl attribute --> <jaxws:features> <bean class="org.apache.cxf.feature.LoggingFeature" /> </jaxws:features> </jaxws:endpoint> <aop:config> <aop:aspect id="myAspect" ref="aBean"> </aop:aspect> </aop:config> </beans> The <aop:config> element in my beans.xml file is copy-pasted from the Spring website to try and remove any possible source of error Can anyone shed any light on why this error is occurring and what I can do to fix it?

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  • Create an XML file using Datasets Using info from XML Schema

    - by Voulnet
    Hello there, I have been thinking about the optimal way to create an XML file using data from a Dataset AND according to the rules of an XML schema. I've been searching around for a bit, and I failed to find a way in which I only take the data from the Dataset and put it inside a XML tags, with the tags being defined by an already-existing schema. So it might go like this: 1- Create Dataset and fill its rows with data. 2- Create an XML according to an XML schema rules. 3- Fill said XML file with data from Dataset such that data is taken from the Dataset while structure of the XML file is taken from the XML schema.

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  • XML Serialization in C# without XML attribute nodes

    - by Alex Marshall
    Hello, I have an XML document format from a legacy system that I have to support in a future application. I want to be able to both serialize and deserialize the XML between XML and C# objects, however, using the objects generated by xsd.exe, the C# serialization includes the xmlns:xsi..., xsi:... etc XML attributes on the root element of the document that gets generated. Is there anyway to disable this so that absolutely no XML attribute nodes get put out in the resulting XML ? The XML document should be elements only. Duplicate? XmlSerializer: remove unnecessary xsi and xsd namespaces

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  • <?xml version=“1.0” encoding=“UTF-8”?> not <?xml version='1.0' encoding='UTF-8'?>

    - by user2446702
    I am using lxml with tree.write(xmlFileOut, pretty_print = True, xml_declaration = True, encoding='UTF-8' to write out my opened and edited xml file, but I absolutely need to have the xml declaration as <?xml version=“1.0” encoding=“UTF-8”?> and NOT <?xml version='1.0' encoding='UTF-8'?> Now I know they are exactly the same when it comes to xml, but I am dealing with a very tricky customer who absolutely has to have " in the declaration and not '. I have searched everywhere but can't find the answer. Could I create it and add it in myself to the head of the xml somehow? Could I tell lxml that this is what I need as an xml declaration?

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  • mysql to xml (DOM question)

    - by Jerry
    Hello guys I am new to php dom and trying to get the mysql data transfer into xml. My current xml output is like this <markers> <city> <name>Seattle</name> <size>medium</size> <name>New York</name> <size>big</size> <city> <markers> but I want to change it to <markers> <city> <name>Seattle</name> <size>medium</size> <city> <city> <name>New York</name> <size>big</size> </city> <city> <markers> my php $dom=new DOMDocument("1.0"); $node=$dom->createElement("markers"); $parnode=$dom->appendChild($node); $firstElement=$dom->createElement("city"); $parnode->appendChild($firstElement); $getLocationQuery=mysql_query("SELECT * FROM location",$connection); header("Content-type:text/xml"); while($row=mysql_fetch_assoc($getLocationQuery)){ foreach ($row as $fieldName=>$value){ $child=$dom->createElement($fieldName); $value=$dom->createTextNode($value); $child->appendChild($value); $firstElement->appendChild($child); } } I can't figure out how to change my php code. Please help me about it. Thanks a lot.

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  • Using VTD-XML to modify element text only

    - by Algorist
    Hi, I want to achieve below thing in vtd-xml xml modifier class. Original xml <xml> <element attr1='1' attr2='2' attr3='3'>text</element> </xml> int p = vn.getText() xm.updateToken(p, "new text"); But the code here is not modifying the text to new text. Any idea how to achieve this? Other option is to call xm.remove() and then add tag. But, I am not able to retain the attributes. Thank you Bala

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  • Wrapping Arbitrary XML within XML

    - by Marc C
    I need to embed arbitrary (syntactically valid) XML documents within a wrapper XML document. The embedded documents are to be regarded as mere text, they do not need to be parseable when parsing the wrapper document. I know about the "CDATA trick", but I can't use that if the inner XML document itself contains a CDATA segment, and I need to be able to embed any valid XML document. Any advice on accomplishing this--or working around the CDATA limitation--would be appreciated.

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  • XML Parsing from Non-XML Document

    - by Neel Basu
    in a xml/non-xml File there may exist some XML Block that I need to parse and replace with some other string.. The Scenario is something like this.. Some Text <cnt:use name="abc" call="xyz"> <cnt:param name="x" value="2" /> </cnt:use> Some Text There is no guarantee that the document is a proper XML document. (there may exist some unclosed Tags. or some other common mistakes that a Stupid people can make while typing HTML). so I can't use SAX or DOM. I can't even pass it to XSLT (am I right ?). So Whats the best way to extract the <cnt:*> part from the non-xml Document. and read it then replace with something else.

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  • How to transport an XML fragment in an XML Document

    - by mrwayne
    Hi, I'm using an AJAX system on a web application, and for one of the objects i return, it needs to contain an xml fragment. Unfortunately, being AJAX, i'm sending the values back via XML already. So, at the moment, i have something that looks like this (ignoring the fact the tags arent perfect. <Transport> <Message> <Content><[CDATA...] XML Content in here </Cdata></Content> </Message> </Transport> This has worked pretty well for the last few years, however, now the XML content itself needs to contain its own CDATA tags and its causing me grief because you cannot nest CDATA sections. Is there another way to encode the 'XML Content' internally?

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  • Programatically determining which node in an XML document caused validation against its XML Schema t

    - by jd1212
    My input is a well-formed XML document and a corresponding XML Schema document. What I would like to do is determine the location within the XML document that causes it to fail validation against the XML Schema document. I could not figure out how to do this using the standard validation approach in Java: SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = schemaFactory.newSchema(... /* the .xsd source */); Validator validator = schema.newValidator(); DocumentBuilderFactory ... DocumentBuilder ... Document document = DocumentBuilder.parse(... /* the .xml source */); try { validator.validate(new DOMSource(document)); ... } catch (SAXParseException e) { ... } I have toyed with the idea of getting at least the line and column number from SAXParseException, but they're always set to -1, -1 on validation error.

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  • DOM: element created with cloneNode(true) missing element when added to DOM

    - by user149327
    I'm creating a tree control and I'm attempting to use a parent element as a template for its children. To this end I'm using the element.cloneNode(true) method to deep clone the parent element. However when I insert the cloned element into the DOM it is missing certain inner elements despite having an outerHTML value identical to its parent. Surprisingly I observe the same behavior is in IE, Firefox, and Chrome leading me to believe that it is by design. This is the HTML for the node I'm attempting to clone. <SPAN class=node><A class=nodeLink href="/SparklerRestService2.aspx?q={0}" name=http://dbpedia.org/data/Taylor_Swift.rdf> <IMG class=nodeIcon alt="Taylor Swift" src="images/node.png"><SPAN class=nodeText>Taylor Swift</SPAN></A><SPAN class=nodeDescription>Taylor Swift is a swell gall who is realy great.</SPAN></SPAN> Once I've cloned the node using cloneNode(true) I examine the outerHTML property and find that it is indeed identical to the original. <SPAN class=node><A class=nodeLink href="/SparklerRestService2.aspx?q={0}" name=http://dbpedia.org/data/Taylor_Swift.rdf><IMG class=nodeIcon alt="Taylor Swift" src="images/node.png"><SPAN class=nodeText>Taylor Swift</SPAN></A><SPAN class=nodeDescription>Taylor Swift is a swell gall who is realy great.</SPAN></SPAN> However when I insert it into the DOM and inspect the result using FireBug I find that the element has been transformed: <span class="node" style="top: 0px; left: 0px;"<a class=nodeLink href="/SparklerRestService2.aspx?q={0}" name=http://dbpedia.org/data/Taylor_Swift.rdf>Taylor Swift</a><span class="nodeDescription">It's great</span></span> Notice that the grandchildren of the node (the image tag and the span tag surrounding "Taylor Swift") are missing, although strangely the great grandchild "Taylor Swift" text node has made it into the tree. Can anyone shed some light on this behavior? Why would nodes disappear after insertion into the DOM, and why am I seeing the same result in all three major browser engines?

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  • Free lightweight XML text editor to include with an application

    - by Heinzi
    Our application uses a XML configuation file. I thought that it would be nice to distribute some small, lightweight XML editor with our application that the user can use to edit the config file. Features should be: Small and lightweight (ideally, a small .exe that does not require installation), free, with license terms that permit distributing it with a commercial application, understands XML schemas (auto-completion, show validation errors). Does anyone know of such an editor?

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  • A doubt on DOM parser used with Python

    - by fixxxer
    I'm using the following python code to search for a node in an XML file and changing the value of an attribute of one of it's children.Changes are happening correctly when the node is displayed using toxml().But, when it is written to a file, the attributes rearrange themselves(as seen in the Source and the Final XML below). Could anyone explain how and why this happen? Python code: #!/usr/bin/env python import xml from xml.dom.minidom import parse dom=parse("max.xml") #print "Please enter the store name:" for sku in dom.getElementsByTagName("node"): if sku.getAttribute("name") == "store": sku.childNodes[1].childNodes[5].setAttribute("value","Delhi,India") print sku.toxml() xml.dom.ext.PrettyPrint(dom, open("new.xml", "w")) a part of the Source XML: <node name='store' node_id='515' module='mpx.lib.node.simple_value.SimpleValue' config_builder='' inherant='false' description='Configurable Value'> <match> <property name='1' value='point'/> <property name='2' value='0'/> <property name='val' value='Store# 09204 Staten Island, NY'/> <property name='3' value='str'/> </match> </node> Final XML : <node config_builder="" description="Configurable Value" inherant="false" module="mpx.lib.node.simple_value.SimpleValue" name="store" node_id="515"> <match> <property name="1" value="point"/> <property name="2" value="0"/> <property name="val" value="Delhi,India"/> <property name="3" value="str"/> </match> </node>

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  • A question about DOM parser used with Python

    - by fixxxer
    I'm using the following python code to search for a node in an XML file and changing the value of an attribute of one of it's children.Changes are happening correctly when the node is displayed using toxml().But, when it is written to a file, the attributes rearrange themselves(as seen in the Source and the Final XML below). Could anyone explain how and why this happen? Python code: #!/usr/bin/env python import xml from xml.dom.minidom import parse dom=parse("max.xml") #print "Please enter the store name:" for sku in dom.getElementsByTagName("node"): if sku.getAttribute("name") == "store": sku.childNodes[1].childNodes[5].setAttribute("value","Delhi,India") print sku.toxml() xml.dom.ext.PrettyPrint(dom, open("new.xml", "w")) a part of the Source XML: <node name='store' node_id='515' module='mpx.lib.node.simple_value.SimpleValue' config_builder='' inherant='false' description='Configurable Value'> <match> <property name='1' value='point'/> <property name='2' value='0'/> <property name='val' value='Store# 09204 Staten Island, NY'/> <property name='3' value='str'/> </match> </node> Final XML : <node config_builder="" description="Configurable Value" inherant="false" module="mpx.lib.node.simple_value.SimpleValue" name="store" node_id="515"> <match> <property name="1" value="point"/> <property name="2" value="0"/> <property name="val" value="Delhi,India"/> <property name="3" value="str"/> </match> </node>

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  • Store XML,update record in XML,retrive a specific record in XML stored on BB device

    - by user469999
    I am writing a blackberry application where i want to store the data returned by a web service in my BB device.Earlier i was going to use SQLite for storing the data in mobile but as i googled and also did programming using SQLite and found that some BB devices dont support SQLite library and fail to create the database.Then i decided to keep the data returned by webservice in a XML format on my BB device. I just want to know is there any method or way in blackberry through which i can parse the data stored in xml,update it,or directly access a particular record stored in the xml instead of traversing the whole xml n times and finding the matched record. Please guide me as i am new to storing data in BB device.Is the approach which i am thinking to store data in XML right or shall i use something else Thanks in advance Yogesh Chaudhari

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  • Linq to XML - update/alter the nodes of an XML Document

    - by knox
    Hello! If got 2 Questions: 1. I've sarted working around with Linq to XML and i'm wondering if it is possible to change a XML document via Linq. I mean, is there someting like XDocument xmlDoc = XDocument.Load("sample.xml"); update item in xmlDoc.Descendants("item") where (int)item .Attribute("id") == id ... 2. I already know how to create and add a new XMLElement by simply using xmlDoc.Element("items").Add(new XElement(......); but how can i remove a single entry. XML sample data: <items> <item id="1" name="sample1" info="sample1 info" web="" /> <item id="2" name="sample2" info="sample2 info" web="" /> </itmes>

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