jQuery toggle() with unknown initial state
Posted
by Jason Morhardt
on Stack Overflow
See other posts from Stack Overflow
or by Jason Morhardt
Published on 2010-03-11T18:14:10Z
Indexed on
2010/03/11
18:19 UTC
Read the original article
Hit count: 171
jQuery
I have a project that I am working on that uses a little image to mark a record as a favorite on multiple rows in a table. The data gets pulled from a DB and the image is based on whether or not that item is a favorite. One image for a favorite, a different image if not a favorite. I want the user to be able to toggle the image and make it a favorite or not. Here's my code:
$(function () {
$('.FavoriteToggle').toggle(
function () {
$(this).find("img").attr({src:"../../images/icons/favorite.png"});
var ListText = $(this).find('.FavoriteToggleIcon').attr("title");
var ListID = ListText.match(/\d+/);
$.ajax({
url: "include/AJAX.inc.php",
type: "GET",
data: "action=favorite&ItemType=0&ItemID=" + ListID,
success: function () {}
});
},
function () {
$(this).find("img").attr({src:"../../images/icons/favorite_not.png"});
var ListText = $(this).find('.FavoriteToggleIcon').attr("title");
var ListID = ListText.match(/\d+/);
$.ajax({
url: "include/AJAX.inc.php",
type: "GET",
data: "action=favorite&ItemType=0&ItemID=" + ListID,
success: function () {}
});
}
);
});
Works great if the initial state is not a favorite. But you have to double click to get the image to change if it IS a favorite initially. This causes the AJAX to fire twice and essentially make it a favorite then not a favorite before the image responds. The user thinks he's made it a favorite because the image changed, but in fact, it's not. Help anybody?
© Stack Overflow or respective owner