SQL to get list of dates as well as days before and after without duplicates

Posted by Nathan Koop on Stack Overflow See other posts from Stack Overflow or by Nathan Koop
Published on 2010-03-11T17:48:04Z Indexed on 2010/03/11 17:49 UTC
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I need to display a list of dates, which I have in a table

SELECT mydate AS MyDate, 1 AS DateType
FROM myTable
WHERE myTable.fkId = @MyFkId;

Jan 1, 2010 - 1
Jan 2, 2010 - 1
Jan 10, 2010 - 1

No problem. However, I now need to display the date before and the date after as well with a different DateType.

Dec 31, 2009 - 2
Jan 1, 2010 - 1
Jan 2, 2010 - 1
Jan 3, 2010 - 2
Jan 9, 2010 - 2
Jan 10, 2010 - 1
Jan 11, 2010 - 2

I thought I could use a union

SELECT MyDate, DateType
FROM (
    SELECT mydate - 1 AS MyDate, 2 AS DateType
    FROM myTable
    WHERE myTable.fkId = @MyFkId;

    UNION

    SELECT mydate + 1 AS MyDate, 2 AS DateType
    FROM myTable
    WHERE myTable.fkId = @MyFkId;

    UNION

    SELECT mydate AS MyDate, 1 AS DateType
    FROM myTable
    WHERE myTable.fkId = @MyFkId;
) AS myCombinedDateTable

This however includes duplicates of the original dates.

Dec 31, 2009 - 2
Jan 1, 2009 - 2
Jan 1, 2010 - 1
Jan 2, 2010 - 2
Jan 2, 2010 - 1
Jan 3, 2010 - 2
Jan 9, 2010 - 2
Jan 10, 2010 - 1
Jan 11, 2010 - 2

How can I best remove these duplicates? I am considering a temporary table, but am unsure if that is the best way to do it.

This also appears to me that it may provide performance issues as I am running the same query three separate times.

What would be the best way to handle this request?

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