How to differentiate between method and function in a decorator?
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Published on 2010-03-12T20:45:32Z
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I want to write a decorator that acts differently depending on whether it is applied to a function or to a method.
def some_decorator(func):
if the_magic_happens_here(func): # <---- Point of interest
print 'Yay, found a method ^_^ (unbound jet)'
else:
print 'Meh, just an ordinary function :/'
return func
class MyClass(object):
@some_decorator
def method(self):
pass
@some_decorator
def function():
pass
I tried inspect.ismethod()
, inspect.ismethoddescriptor()
and inspect.isfunction()
but no luck. The problem is that a method actually is neither a bound nor an unbound method but an ordinary function as long as it is accessed from within the class body.
What I really want to do is to delay the actions of the decorator to the point the class is actually instantiated because I need the methods to be callable in their instance scope. For this, I want to mark methods with an attribute and later search for these attributes when the .__new__()
method of MyClass
is called. The classes for which this decorator should work are required to inherit from a class that is under my control. You can use that fact for your solution.
In the case of a normal function the delay is not necessary and the decorator should take action immediately. That is why I wand to differentiate these two cases.
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