How are java.lang.Object's protected methods protected from subclasses?
Posted
by Adrian Lang
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Published on 2009-01-16T19:32:12Z
Indexed on
2010/03/16
14:26 UTC
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The keyword protected
grants access to classes in the same package and subclasses (http://java.sun.com/docs/books/tutorial/java/javaOO/accesscontrol.html).
Now, every class has java.lang.Object
as superclass (http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Object.html).
Hence I conclude that every class may access java.lang.Object
's methods even if they are protected
.
Take a look at the following example:
public class Testclass { public Object getOne() throws CloneNotSupportedException { return this.clone(); } public Object getTwo() throws CloneNotSupportedException { return ((Object) this).clone(); } }
While getOne()
compiles fine, getTwo()
gives
Testclass.java:6: clone() has protected access in java.lang.Object return ((Object) this).clone();
I neither understand why getTwo()
doesn't compile nor what's the difference (regarding the access of java.lang.Object
s members) with getOne()
.
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