why can't i bind ipv6 socket to a linklocal address
Posted
by Haiyuan Zhang
on Stack Overflow
See other posts from Stack Overflow
or by Haiyuan Zhang
Published on 2010-03-16T15:39:34Z
Indexed on
2010/03/16
15:41 UTC
Read the original article
Hit count: 253
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#include <stdio.h>
void error(char *msg)
{
perror(msg);
exit(0);
}
int main(int argc, char *argv[])
{
int sock, length, fromlen, n;
struct sockaddr_in6 server;
struct sockaddr_in6 from;
int portNr = 5555;
char buf[1024];
length = sizeof (struct sockaddr_in6);
sock=socket(AF_INET6, SOCK_DGRAM, 0);
if (sock < 0) error("Opening socket");
bzero((char *)&server, length);
server.sin6_family=AF_INET6;
server.sin6_addr=in6addr_any;
server.sin6_port=htons(portNr);
inet_pton( AF_INET6, "fe80::21f:29ff:feed:2f7e", (void *)&server.sin6_addr.s6_addr);
//inet_pton( AF_INET6, "::1", (void *)&server.sin6_addr.s6_addr);
if (bind(sock,(struct sockaddr *)&server,length)<0)
error("binding");
fromlen = sizeof(struct sockaddr_in6);
while (1) {
n = recvfrom(sock,buf,1024,0,(struct sockaddr *)&from,&fromlen);
if (n < 0) error("recvfrom");
write(1,"Received a datagram: ",21);
write(1,buf,n);
n = sendto(sock,"Got your message\n",17,
0,(struct sockaddr *)&from,fromlen);
if (n < 0) error("sendto");
}
}
when I compile and run the above code I got :
binding: Invalid argument
and if change to bind the ::1
and leave other thing unchanged in the source code, the code
works! so could you tell me what's wrong with my code ? thanks in advance.
© Stack Overflow or respective owner