BASH: Find highest numbered filename in a directory where names start with digits (ls, sed)
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by Jake
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Published on 2009-10-19T05:09:04Z
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2010/03/17
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I have a directory with files that look like this:
001_something.php 002_something_else.php
004_xyz.php 005_do_good_to_others.php
I ultimately want to create a new, empty PHP file whose name starts with the next number in the series.
LIST=`exec ls $MY_DIR | sed 's/\([0-9]\+\).*/\1/g' | tr '\n' ' '`
The preceding code gives me a string like this:
LIST='001 002 004 005 '
I want to grab that 005, increment by one, and then use that number to generate the new filename. How do I do that in BASH?
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