idiomatic way to take groups of n items from a list in Python?
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Published on 2010-03-17T10:35:13Z
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2010/03/17
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Given a list
A = [1 2 3 4 5 6]
Is there any idiomatic (Pythonic) way to iterate over it as though it were
B = [(1, 2) (3, 4) (5, 6)]
other than indexing? That feels like a holdover from C:
for a1,a2 in [ (A[i], A[i+1]) for i in range(0, len(A), 2) ]:
I can't help but feel there should be some clever hack using itertools or slicing or something.
(Of course, two at a time is just an example; I'd like a solution that works for any n.)
Edit: related http://stackoverflow.com/questions/1162592/iterate-over-a-string-2-or-n-characters-at-a-time-in-python but even the cleanest solution (accepted, using zip) doesn't generalize well to higher n without a list comprehension and *-notation.
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