Default value for file path in function gives SyntaxError. Work around?
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by LtPinback
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Published on 2010-03-18T11:52:38Z
Indexed on
2010/03/18
12:01 UTC
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for this,
import os.path
def f(data_file_path=os.path.join(os.getcwd(),'temp'),type):
...
return data
I get this,
SyntaxError: non-default argument follows default argument
Is there a way to make this work or do I have to define a variable such as,
rawdata_path = os.path.join(os.getcwd(),'temp')
and then plug that into the function?
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