How do I bring forward the SELECTED option in PHP from MySQL?

Posted by Derek on Stack Overflow See other posts from Stack Overflow or by Derek
Published on 2010-03-18T23:13:49Z Indexed on 2010/03/18 23:41 UTC
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Hi all,

In my update form, I want the fields to recall the values that are already stored. This is very simple in a text field, but for my drop down () I'm having trouble with PHP reading the already stored name of user. Here is my query and code:

$sql = "SELECT users.user_id, users.name FROM users";
                $result = mysql_query($sql, $connection)
                or die ("Couldn't perform query $sql <br />".mysql_error());
                $row = mysql_fetch_array($result);?>

        <label>Designated Person:</label> <select name="name" id="name">

        <option value="<?php echo $row['user_id']?>" SELECTED><?php echo $row['name']?> - Current</option>

         <?php    
              while($row = mysql_fetch_array($result))
        { ?>                        <option value="<?php echo $row['user_id']; if (isset($_POST['user_id']));?>"><?php echo $row['fullname']?></option>
        <?php } ?>

The result of this displays all of the users (as required) and lets me select a user then perform the change successfully...however the 'SELECTED' is always the first one in my database and never the user that was selected when my activity was added :( !!!

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