iPhone: Activate UISlider and set its value to the location of the current touch programatically
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Published on 2010-03-18T00:55:14Z
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2010/03/18
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Is it possible to set an UISlider as first responder and set its current value to the location of the current touch programatically?
The way my app is set up I have a UIView container that takes up the whole screen. Inside the container I have another UIView offscreen at the bottom edge (I'll call this bottomBar). Inside the bottomBar there is a UISlider element.
Right now, when the user swipes along the bottom edge of the screen the bottomBar the slider it contains slide up. What I am trying to achieve is to activate the UISlider, and set the position of the slider (the value) to the position of the users touch. Is this possible? Could someone please point me in the right direction?
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