"A reference to a volatile field will not be treated as volatile" implications
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by estourodepilha.com
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Published on 2009-01-08T17:24:40Z
Indexed on
2010/03/19
22:31 UTC
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The following code
using System.Threading;
class Test
{
volatile int counter = 0;
public void Increment()
{
Interlocked.Increment(ref counter);
}
}
Raises the following compiler warning:
"A reference to a volatile field will not be treated as volatile"
Am I doing something wrong here to raise this warning? Why does the compiler me warn about this?
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