How to deserialize implementation classes in OSGi
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by Daniel Schneller
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Published on 2010-03-18T22:33:10Z
Indexed on
2010/03/19
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In an eRCP OSGi based application the user can push a button and go to a lock screen similar to that of Windows or Mac OS X. When this happens, the current state of the application is serialized to a file and control is handed over to the lock screen. In this mobile application memory is very tight, so we need to get rid of the original view/controller when the lock screen comes up.
This works fine and we end up with a binary serialized file. Once the user logs back in, the file is read in again and the original state of the application restored. This works fine as well, except when the controller that was serialized contained a reference to an object which comes from a different bundle. In my concrete case the original controller (from bundle A) can call a web service and gets a result back. Nothing fancy, just some Strings and Numbers in a simple value holder class. However the controller only sees this as a Result
interface; the actual runtime object (ResultImpl
) is defined and created in a different bundle (bundle B, the webservice client implementation) and returned via a service call.
When the deserialization now tries to thaw the controller from the file, it throws a ClassNotFound
exception, complaining about not being able to deserialize the result object, because deserialization is called from bundle A, which cannot see the ResultImpl
class from bundle B.
Any ideas on how to work around that? The only thing I could come up with is to clone all the individual values into another object, defined in the controller's bundle, but this seems like quite a hassle.
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