jQuery .each() with multiple selectors - skip, then .empty() elements

Posted by joe on Stack Overflow See other posts from Stack Overflow or by joe
Published on 2010-03-19T21:50:17Z Indexed on 2010/03/19 21:51 UTC
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I'd like to remove all matching elements, but skip the first instance of each match:

// Works as expected: removes all but first instance of .a
jQuery ('.a', '#scope')
    .each ( function (i) { 
        if (i > 0) jQuery (this).empty();
    });

// Expected: removal of all but first instance of .a and .b
// Result: removal of *all* instances of both .a and .b
jQuery ('.a, .b', '#scope')
    .each ( function (i) { 
        if (i > 1) jQuery (this).empty();
    });

<div id="scope">

    <!-- Want to keep the first instance of .a and .b -->

    <div class="a">[bla]</span>
    <div class="b">[bla]</span>

    <!-- Want to remove all the others -->

    <div class="a">[bla]</span>
    <div class="b">[bla]</span

    <div class="a">[bla]</span>
    <div class="b">[bla]</span
    ...
</div>

Any suggestions?

  • Using jQuery() rather than $() because of conflict with 'legacy' code
  • Using .empty() because .a contains JS I'd like to disable
  • Stuck with jQuery 1.2.3

Thanks you!

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