Why does jQuery do this in its constructor function implementation?
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by mattcodes
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Published on 2010-03-19T12:52:29Z
Indexed on
2010/03/19
13:01 UTC
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jQuery
|JavaScript
If we look at the latest jQuery source at http://code.jquery.com/jquery-latest.js we see the following:
var jQuery = function( selector, context ) {
// The jQuery object is actually just the init constructor 'enhanced'
return new jQuery.fn.init( selector, context );
}
My understanding of the new keyword in Javascript is essentially JavaScript passes the function an empty object {}
and the function sets stuff on it via this.blah
.
Also from my understanding new
differs from .call
/.apply
etc.. in that the return object also has the prototype set to that of the function. So the return value should have a prototype that the same as jQuery.prototype.init.prototype
(or jQuery.fn.init.prototype
). However from what I see its prototype is set to jQuery.prototype
thus all the commands available to work on the set.
Why is this? What am I missing in my understanding?
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