Fastest algorithm to check if a number is pandigital?
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by medopal
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Published on 2010-03-20T21:43:45Z
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2010/03/20
21:51 UTC
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Pandigital number is a number that contains the digits 1..number length.
For example 123, 4312 and 967412385.
I have solved many Project Euler problems, but the Pandigital problems always exceed the one minute rule.
This is my pandigital function:
private boolean isPandigital(int n){
Set<Character> set= new TreeSet<Character>();
String string = n+"";
for (char c:string.toCharArray()){
if (c=='0') return false;
set.add(c);
}
return set.size()==string.length();
}
Create your own function and test it with this method
int pans=0;
for (int i=123456789;i<=123987654;i++){
if (isPandigital(i)){
pans++;
}
}
Using this loop, you should get 720 pandigital numbers. My average time was 500 millisecond.
I'm using Java, but the question is open to any language.
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