JsLint 'out of scope' error
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by Rajat
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Published on 2010-03-20T23:14:53Z
Indexed on
2010/03/20
23:21 UTC
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JavaScript
|jslint
function test(){
if(true){
var a = 5;
}
alert(a);
}
test();
I keep getting 'out of scope' errors in my JS code when I check with JsLint which make no sense to me.So I quickly created an example. Is there something actually wrong with this code piece, as the variable is eventually hoisted to the top of the function anyways.
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