Cleanest/One-liner way to require all files in directory in Ruby?
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by viatropos
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Published on 2010-03-21T19:09:59Z
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2010/03/21
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When creating gems, I often have a directory structure like this:
|--lib
|-- helpers.rb
`-- helpers
|-- helper_a.rb
`-- helper_b.rb
Inside the helpers.rb, I'm just require-ing the files in the helpers directory. But I have to do things like this:
$:.push(File.dirname(__FILE__) + '/helpers')
require 'helper_a'
require 'helper_b'
Is there a way to make that one line so I never have to add to it? I just came up with this real quick:
dir = File.join(File.dirname(__FILE__), "helpers")
Dir.entries(dir)[2..-1].each { |file| require "#{dir}/#{file[0..-4]}" }
But it's two lines and ugly. What's a slick one liner to solve this problem?
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