What rules govern the copying of variables in Javascript closures?
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by int3
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Published on 2010-03-21T17:52:54Z
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2010/03/21
18:01 UTC
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JavaScript
|closures
I'd just like to check my understanding of variable copying in Javascript. From what I gather, variables are passed/assigned by reference unless you explicitly tell them to create a copy with the new
operator. But I'm a little uncertain when it comes to using closures. Say I have the following code:
var myArray = [1, 5, 10, 15, 20];
var fnlist = [];
for (var i in myArray) {
var data = myArray[i];
fnlist.push(function() {
var x = data;
console.log(x);
});
}
fnlist[2](); // returns 20
I gather that this is because fnlist[2]
only looks up the value of data
at the point where it is invoked. So I tried an alternative tack:
var myArray = [1, 5, 10, 15, 20];
var fnlist = [];
for (var i in myArray) {
var data = myArray[i];
fnlist.push(function() {
var x = data;
return function() {
console.log(x);
}
}());
}
fnlist[2](); // returns 10
So now it returns the 'correct' value. Am I right to say that it works because a function resolves all variable references to their 'constant' values when it is invoked? Or is there a better way to explain it?
Any explanations / links to explanations regarding this referencing / copying business would be appreciated as well. Thanks!
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