Batch files - number of command line arguments

Posted by pyko on Stack Overflow See other posts from Stack Overflow or by pyko
Published on 2009-08-18T05:19:54Z Indexed on 2010/03/22 4:31 UTC
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Just converting some shell scripts into batch files and there is one thing I can't seem to find...and that is a simple count of the number of command line arguments.

eg. if you have:

myapp foo bar

In Shell:

  • $# -> 2
  • $* -> foo bar
  • $0 -> myapp
  • $1 -> foo
  • $2 -> bar

In batch

  • ?? -> 2 <---- what command?!
  • %* -> foo bar
  • %0 -> myapp
  • %1 -> foo
  • %2 -> bar

So I've looked around, and either I'm looking in the wrong spot or I'm blind, but I can't seem to find a way to get a count of number of command line arguments passed in.

Is there a command similar to shell's "$#" for batch files?

ps. the closest i've found is to iterate through the %1s and use 'shift', but I need to refernece %1,%2 etc later in the script so that's no good.

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