Why is XmlSerializer throwing an InvalidOperationException?
Posted
by qster
on Stack Overflow
See other posts from Stack Overflow
or by qster
Published on 2010-03-23T07:31:14Z
Indexed on
2010/03/23
7:33 UTC
Read the original article
Hit count: 990
public void Save() {
XmlSerializer Serializer = new XmlSerializer(typeof(DatabaseInformation));
/*
A first chance exception of type 'System.IO.FileNotFoundException' occurred in mscorlib.dll
A first chance exception of type 'System.IO.FileNotFoundException' occurred in mscorlib.dll
A first chance exception of type 'System.InvalidOperationException' occurred in System.Xml.dll
*/
// ....
}
This is the whole class if you need it:
public class DatabaseInformation
{
/* Create new database */
public DatabaseInformation(string name) {
mName = name;
NeedsSaving = true;
mFieldsInfo = new List<DatabaseField>();
}
/* Read from file */
public static DatabaseInformation DeserializeFromFile(string xml_file_path)
{
XmlSerializer Serializer = new XmlSerializer(typeof(DatabaseInformation));
TextReader r = new StreamReader(xml_file_path);
DatabaseInformation ret = (DatabaseInformation)Serializer.Deserialize(r);
r.Close();
ret.NeedsSaving = false;
return ret;
}
/* Save */
public void Save() {
XmlSerializer Serializer = new XmlSerializer(typeof(DatabaseInformation));
if (!mNeedsSaving)
return;
TextWriter w = new StreamWriter(Path.Combine(Program.MainView.CommonDirectory.Get(), Name + ".xml"), false);
Serializer.Serialize(w, this);
w.Close();
NeedsSaving = false;
}
private string mName;
public string Name { get { return mName; } }
private bool mNeedsSaving;
public bool NeedsSaving { get { return mNeedsSaving; } set { mNeedsSaving = value; Program.MainView.UpdateTitle(value); } }
private bool mHasId;
public bool HasId { get { return mHasId; } }
List<DatabaseField> mFieldsInfo;
}
© Stack Overflow or respective owner