How to find validity of a string of parentheses, curly brackets and square brackets?
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by Rajendra
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Published on 2010-03-24T16:16:55Z
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2010/03/24
16:23 UTC
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I recently came in contact with this interesting problem. You are given a string containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, for example, "[{()}]"
, you need to write a function which will check validity of such an input string, function may be like this:
bool isValid(char* s);
these brackets have to close in the correct order, for example "()"
and "()[]{}"
are all valid but "(]"
, "([)]"
and "{{{{"
are not!
I came out with following O(n) time and O(n) space complexity solution, which works fine:
- Maintain a stack of characters.
- Whenever you find opening braces
'('
,'{'
OR'['
push it on the stack. - Whenever you find closing braces
')'
,'}'
OR']'
, check if top of stack is corresponding opening bracket, if yes, then pop the stack, else break the loop and return false. - Repeat steps 2 - 3 until end of the string.
This works, but can we optimize it for space, may be constant extra space, I understand that time complexity cannot be less than O(n) as we have to look at every character.
So my question is can we solve this problem in O(1) space?
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