Setcookie > sniff > output on same page
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by lokust
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Published on 2010-03-24T19:35:28Z
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2010/03/24
19:43 UTC
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Hi, I wonder if someone can help shed some light on this:
I drop a cookie if a user arrives to the site with a specific key/value in query string. i.e.: http://www.somesite.com?key=hmm01
The cookie code exists at top of the template before <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML ) :
<?php
header("Content-Type: text/html; charset=utf-8");
ob_start();
if (isset($_GET['key'])) {
setcookie("cookname", $_GET['key'], time()+2592000); /* Expires in a month */
}
ob_end_flush();
?>
On the same page though within the : I have the following php code that sniffs the cookie and outputs some text:
`
switch ($cookievalue) { case hmm01: echo "abc"; break; case hmm02: echo "def"; break; case hmm03: echo "ghi"; break; default: echo "hello"; } ?>`
-- Problem is when the user first arrives the sniffer script doesn't detect the cookie and outputs the default text: hello Only when user refreshes page or navigates to a different page does the sniffer detect the cookie.
Any ideas on how to drop the cookie and output the correct text without a page refresh?
Many thanks.
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