Count Occurence of Needle String in Haystack String, most optimally?
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by Taranfx
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Published on 2010-03-25T13:26:11Z
Indexed on
2010/03/25
13:33 UTC
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The Problem is simple Find "ABC" in "ABCDSGDABCSAGAABCCCCAAABAABC"
Here is the solution I propose, I'm looking for any solutions that might be better than this one.
public static void main(String[] args) {
String haystack = "ABCDSGDABCSAGAABCCCCAAABAABC";
String needle = "ABC";
char [] needl = needle.toCharArray();
int needleLen = needle.length();
int found=0;
char hay[] = haystack.toCharArray();
int index =0;
int chMatched =0;
for (int i=0; i<hay.length; i++){
if (index >= needleLen || chMatched==0)
index=0;
System.out.print("\nchar-->"+hay[i] + ", with->"+needl[index]);
if(hay[i] == needl[index]){
chMatched++;
System.out.println(", matched");
}else {
chMatched=0;
index=0;
if(hay[i] == needl[index]){
chMatched++;
System.out.print("\nchar->"+hay[i] + ", with->"+needl[index]);
System.out.print(", matched");
}else
continue;
}
if(chMatched == needleLen){
found++;
System.out.println("found. Total ->"+found);
}
index++;
}
System.out.println("Result Found-->"+found);
}
It took me a while creating this one. Can someone suggest a better solution (if any) P.S. Drop the sysouts if they look messy to you.
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