Casting a char to an unsigned short: what happens behind the scenes?

Posted by hb on Stack Overflow See other posts from Stack Overflow or by hb
Published on 2008-12-31T09:41:09Z Indexed on 2010/03/26 21:23 UTC
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c

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c#

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casting

Given this field:

char lookup_ext[8192] = {0}; // Gets filled later

And this statement:

unsigned short *slt = (unsigned short*) lookup_ext;

What happens behind the scenes?

lookup_ext[1669] returns 67 = 0100 0011 (C), lookup_ext[1670] returns 78 = 0100 1110 (N) and lookup_ext[1671] returns 68 = 0100 0100 (D); yet slt[1670] returns 18273 = 0100 0111 0110 0001.

I'm trying to port this to C#, so besides an easy way out of this, I'm also wondering what really happens here. Been a while since I used C++ regularly.

Thanks!

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Developer IT

Casting a char to an unsigned short: what happens behind the scenes? - Developer IT

Casting a char to an unsigned short: what happens behind the scenes?

c

c#

casting

Related posts about c

Related posts about c#

.NET WebRequest.PreAuthenticate not quite what it sounds like

HttpWebRequest and Ignoring SSL Certificate Errors

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Finding a Relative Path in .NET

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