Correct syntax for php inside a feed request
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by Simon Hume
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Published on 2010-03-26T13:00:12Z
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2010/03/26
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Hi guys,
I have a very basic query string which passes a ID to a receiving page.
On that page, I need to dynamically call the YouTube API, giving my playlistID.
I'm having to use PHP for this, and it's a little out of my comfort zone, so hopefully someone can wade in with a quick fix for me.
Here is my variable
$playlist;
And I need to replace the 77DC230FBBCE4D58 below with that variable.
$feedURL = 'http://gdata.youtube.com/feeds/api/playlists/77DC230FBBCE4D58?v=2';
Any help, as always, greatly appreciated!
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