What's the fastest way using lsof to find a single open file?
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Published on 2010-03-26T21:56:42Z
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2010/03/26
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I'm trying to test a single file if it is open using lsof. Is there a faster way than this?
$result = exec('lsof | grep filename | wc -l');
if($result > 0) {
//file is open
}
I'm thinking their must be a way to just test for one file if you know the filename. All I really need is a true or false.
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