Would relational calculus be Turing-complete if it allowed unsafe queries?

Posted by Jason Baker on Stack Overflow See other posts from Stack Overflow or by Jason Baker
Published on 2010-03-27T14:33:20Z Indexed on 2010/03/27 14:43 UTC
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My understanding about Codd's concept of "safe queries" was created to ensure that a query would always terminate. One of the key ability of a Turing machine is that it can work on infinite calculations (and thus isn't guaranteed to terminate). If the safe query restriction were removed, would relational calculus be Turing-complete since that means it doesn't have to terminate?

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