A Question about using jython when run a receving socket in python
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Published on 2010-03-28T12:54:43Z
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2010/03/28
13:53 UTC
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Hi,
I have not a lot of knowledge of python and network programming. Currently I am trying to implement a simple application which can receive a text message sent by the user, fetch some information from the google search api, and return the results via text message to the user. This application will continue to listening to the users messages and reply immediately.
How I get the text short message sent by the user? It's a program named fetion from the mobile supplier in China. The client side fetion, just like a instant communication tool, can send/receive messages to/from other people who are using mobile to receive/send SMS.
I am using a open source python program that simulates the fetion program. So basically I can use this python program to communate with others who using cell phone via SMS.
My core program is based on java, so I need to take this python program into java environment. I am using jython, and now I am available to send messages to users by some lines of java codes.
But the real question is the process of receving from users via SMS. In python code, a new thread is created to continuously listen to the user. It should be OK in Python, but when I run the similar process in Jython, the following exception occurs:
Exception in thread Thread:Traceback (most recent call last):
File "D:\jython2.5.1\Lib\threading.py", line 178, in _Thread__bootstrap
self.run()
File "<iostream>", line 1389, in run
File "<iostream>", line 1207, in receive
File "<iostream>", line 1207, in receive
File "<iostream>", line 150, in recv
File "D:\jython2.5.1\Lib\select.py", line 223, in native_select
pobj.register(fd, POLLIN)
File "D:\jython2.5.1\Lib\select.py", line 104, in register
raise _map_exception(jlx)
error: (20000, 'socket must be in non-blocking mode')
The line 150 in the python code is as follows:
def recv(self,timeout=False):
if self.login_type == "HTTP":
time.sleep(10)
return self.get_offline_msg()
pass
else:
if timeout:
infd,outfd,errfd = select([self.__sock,],[],[],timeout)//<---line 150 here
else:
infd,outfd,errfd = select([self.__sock,],[],[])
if len(infd) != 0:
ret = self.__tcp_recv()
num = len(ret)
d_print(('num',),locals())
if num == 0:
return ret
if num == 1:
return ret[0]
for r in ret:
self.queue.put(r)
d_print(('r',),locals())
if not self.queue.empty():
return self.queue.get()
else:
return "TimeOut"
Because of I am not very familiar with python, especially the socket part, and also new in Jython use, I really need your help or only advice or explanation.
Thank you very much!
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