Python - compare nested lists and append matches to new list?

Posted by Seafoid on Stack Overflow See other posts from Stack Overflow or by Seafoid
Published on 2010-03-29T14:36:17Z Indexed on 2010/03/29 14:43 UTC
Read the original article Hit count: 377

Filed under:
|
|
|

Hi,

I wish to compare to nested lists of unequal length. I am interested only in a match between the first element of each sub list. Should a match exist, I wish to add the match to another list for subsequent transformation into a tab delimited file. Here is an example of what I am working with:

x = [['1', 'a', 'b'], ['2', 'c', 'd']]

y = [['1', 'z', 'x'], ['4', 'z', 'x']]

match = []

def find_match():
    for i in x:
        for j in y:
            if i[1] == j[1]:
                 match.append(j)
            return match

This results in a series of empty lists.

Is it better to use tuples and/or tuples of tuples for the purposes of comparison?

Any help is greatly appreciated.

Regards, Seafoid.

© Stack Overflow or respective owner

Related posts about python

Related posts about compare