Exit python program when argument is less than 0
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Published on 2010-03-30T23:01:16Z
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2010/03/30
23:03 UTC
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python
I'd like the program to exit if the input number is less than 0, but sys.exit() isn't doing the trick. This is what I have now:
if len( sys.argv ) > 1:
number = sys.argv[1]
if number <= 0:
print "Invalid number! Must be greater than 0"
sys.exit()
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