Exit python program when argument is less than 0
Posted
by Sam
on Stack Overflow
See other posts from Stack Overflow
or by Sam
Published on 2010-03-30T23:01:16Z
Indexed on
2010/03/30
23:03 UTC
Read the original article
Hit count: 180
Filed under:
python
I'd like the program to exit if the input number is less than 0, but sys.exit() isn't doing the trick. This is what I have now:
if len( sys.argv ) > 1:
number = sys.argv[1]
if number <= 0:
print "Invalid number! Must be greater than 0"
sys.exit()
© Stack Overflow or respective owner
