How to call Twiter's Streaming/Filter Feed with urllib2/httplib?
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by Simon
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Published on 2010-03-30T06:56:26Z
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2010/03/30
18:03 UTC
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Update:
I switched this back from answered as I tried the solution posed in cogent Nick's answer and switched to Google's urlfetch:
logging.debug("starting urlfetch for http://%s%s" % (self.host, self.url))
result = urlfetch.fetch("http://%s%s" % (self.host, self.url), payload=self.body, method="POST", headers=self.headers, allow_truncated=True, deadline=5)
logging.debug("finished urlfetch")
but unfortunately finished urlfetch
is never printed - I see the timeout happen in the logs (it returns 200 after 5 seconds), but execution doesn't seem tor return.
Hi All-
I'm attempting to play around with Twitter's Streaming (aka firehose) API with Google App Engine (I'm aware this probably isn't a great long term play as you can't keep the connection perpetually open with GAE), but so far I haven't had any luck getting my program to actually parse the results returned by Twitter.
Some code:
logging.debug("firing up urllib2")
req = urllib2.Request(url="http://%s%s" % (self.host, self.url), data=self.body, headers=self.headers)
logging.debug("called urlopen for %s %s, about to call urlopen" % (self.host, self.url))
fobj = urllib2.urlopen(req)
logging.debug("called urlopen")
When this executes, unfortunately, my debug output never shows the called urlopen
line printed. I suspect what's happening is that Twitter keeps the connection open and urllib2 doesn't return because the server doesn't terminate the connection.
Wireshark shows the request being sent properly and a response returned with results.
I tried adding Connection: close
to my request header, but that didn't yield a successful result.
Any ideas on how to get this to work?
thanks
-Simon
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