"call" instruction that seemingly jumps into itself
Posted
by Checkers
on Stack Overflow
See other posts from Stack Overflow
or by Checkers
Published on 2010-03-31T06:04:02Z
Indexed on
2010/03/31
6:23 UTC
Read the original article
Hit count: 467
I have gcc 4 compiling some C++ code into the following (from objdump
):
00000030 <func()>:
30: 55 push %ebp
31: 89 e5 mov %esp,%ebp
33: 56 push %esi
34: 31 f6 xor %esi,%esi
36: 53 push %ebx
37: bb 00 00 00 00 mov $0x0,%ebx
3c: 83 ec 40 sub $0x40,%esp
3f: c7 04 24 01 00 00 00 movl $0x1,(%esp)
46: e8 fc ff ff ff call 47 <func()+0x17>
4b: 8d 55 ec lea 0xffffffec(%ebp),%edx
4e: 89 14 24 mov %edx,(%esp)
51: 89 5c 24 04 mov %ebx,0x4(%esp)
55: 89 74 24 08 mov %esi,0x8(%esp)
59: 89 44 24 0c mov %eax,0xc(%esp)
; the rest of the function is omitted
I can't understand the operand of call
instruction here, why does it call into itself, but with one byte off?
© Stack Overflow or respective owner